How to run simple Php API? - php

Question

I used Php Slim Framework for my API. I install the Slim Framework to my web root directory on my server and copy the index.php file I coded.
Index.php:
<?php
require 'vendor/autoload.php';
$app = new \Slim\Slim();
$app->contentType('application/json');
$app->get('/users', 'getUsers');
$app->get('/user/:id', 'getUser');
$app->run();
function getConnection() {
$dbhost="localhost";
$dbuser="";
$dbpass="";
$dbname="";
$dbh = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbuser, $dbpass);
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
return $dbh;
}
function getUsers() {
$sql = "select * FROM manga";
try {
$db = getConnection();
$stmt = $db->query($sql);
$users = $stmt->fetchAll(PDO::FETCH_OBJ);
$db = null;
echo json_encode($users);
}
catch(PDOException $e) {
echo json_encode($e->getMessage());
}
}
?>
I am getting 500 (Internal Server Error).
Edit: I changed "$app = new Slim();" to the "$app = new \Slim\Slim();" then receive the below error.
I am using EasyEngine(Nginx).
Edit-2:Now 500 Internal gone but another error showing.
XMLHttpRequest cannot load http://api.mangayurdu.com/users. No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'http://deneme.mangayurdu.com' is therefore not allowed access.
Here is my code that getting JSON data:
.factory('MY', function($http){
var factory = {};
var url = 'http://api.mangayurdu.com/users?callback=JSON_CALLBACK';
factory.isimler = $http.get(url);
return factory;
})

Answer 1

From the posted code it looks like Slim can't find a function called getUser. getUsers() is defined in your code, but no getUser() function.

Answer 2

try putting this in the start of your PHP page
<?php header('Access-Control-Allow-Origin: *');?>