This question already has answers here:
What's the difference between an argument and a parameter?
(38 answers)
Closed 7 years ago.
I don't understand difference of arguments and parameter in function.Is there anybody who tell me details about arguments and parameters. What is arguments and what is parameter?
To be simple -
Variables used in function definition are parameter.
Values passed during function call are arguments
function abc($x)
{
//----
//$x is parameter..
}
abc(35); //35 is an argument
Related
This question already has answers here:
PHP | What are three dots before a function arguments?
(1 answer)
Reference Guide: What does this symbol mean in PHP? (PHP Syntax)
(24 answers)
Closed 3 years ago.
What is the real purpose of function with ellipsis in its parameter?
I have this function:
class Dog{
public function type(...$numbers){
var_dump($numbers);
}
}
and this function
class Dog{
public function type($numbers){
var_dump($numbers);
}
}
Whether I put ellipsis or not, if I call the type function putting multiple parameters in it, its type will always be an array.
So my question is, why exactly should I put the ellipsis inside the parameter of a function?
It's just syntactic sugar, called variable-length argument lists. It lets you pass the function multiple arguments that it will turn into an array automatically. In that example, it would let you call type(1, 2, 3) and $numbers would be an array of those three numbers.
This question already has answers here:
What is the meaning of three dots (...) in PHP?
(9 answers)
Closed 5 years ago.
I'm learning PHP http://php.net/manual/en/migration70.new-features.php and in the following example, I don't understand ... prepended with the $ints parameter in the function definition.
<?php
// Coercive mode
function sumOfInts(int ...$ints)
{
return array_sum($ints);
}
var_dump(sumOfInts(2, '3', 4.1));
Can anybody please tell me what those dots are for?
Thanks.
that means that when you call that function, you can pass X integers and the function will process them, doesn't matter how many are they. If you call sumOfInts(3,4,6,2,9) or sumOfInts(3,2,9), the function works, no matter how many arguments you pass
This question already has answers here:
PHP: "... variables can be passed by reference" in str_replace()?
(3 answers)
Closed 7 years ago.
What is causing this error?
Fatal error: Only variables can be passed by reference in /var/www/application
/lib/testing/imageMaker/imageMaker.php on line 24
$x=str_replace ($s1,'',$s2);
$y=str_replace ($s1,'',$s2, 1 ); //Line 24
As described here: PHP Manual: str_replace
count
If passed, this will be set to the number of replacements performed.
You cannot pass the literals and rather pass the reference:
$x=str_replace ($s1,'',$s2);
$y=str_replace ($s1,'',$s2, $count);
echo $count;
This question already has answers here:
Anonymous recursive PHP functions
(6 answers)
Closed 9 years ago.
i need to recursively call a variable function, how can i do this?
$rec = function($li) use($html,$rec) { // error, rec was not defined yet
if( ... ) $rec( ... );
}
how can i do this?
Use the function variable $rec by reference (&$rec) so you can set it to the function then. This will also define it.
use($html, &$rec)
^
You find this principle outlined in the question Anonymous recursive PHP functions.
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
How to pass variable number of arguments to a PHP function
I make my framework in php
I want to have variable function arguments
ex
if I have 2 parameter
$a,$b;
the function become
function name($a,$b);
and if I have 3 parameter
$a,$b,$c;
the function become
function name($a,$b,$c);
Check out http://www.php.net/manual/en/functions.arguments.php#functions.variable-arg-list. Is that what you're looking for? If not, can you just accept an array?