I have 3 tables in MYSQL From 2 different database running in same server
and my expected Output is
MY attempt of query is
SELECT `biometric`.`Empid`,
,`name`,`location`,`basic`,`hra`,`conveyance`,`total salary`,sum(DISTINCT DATEDIFF(LEAST(`endDate`,'$monthEnd' ),GREATEST(`startdate`,'$monthStart'))+1) as leaves FROM `biometric`.`biometric`,`biometric`.`employee` JOIN `lms`.`leaves` WHERE `biometric`.`empid`= `employee`.`empid` AND `employee`.`empid` = `leaves`.`id` AND
`startdate`<='$monthEnd' AND `endDate`>= '$monthStart' AND `leaves`.`status` = '3'
GROUP BY `Empid`
and here status =3 is approved leave and 1 is non approved leave.
and my out put coming is
Thanks in Advance...
You can try below query, even I did not test it so if you get any error then you can create an sqlfiddle so that I can correct it.
Basic concept is that you need to use left join for lms.leaves table as you need all employee details even they did not took leave under status 3.
SELECT bmt.`Empid`,`name`,`location`,`basic`,`hra`,`conveyance`,`total salary`,
IFNULL(SUM(DISTINCT DATEDIFF(LEAST(`endDate`,'$monthEnd' ),GREATEST(`startdate`,'$monthStart'))+1),0) AS LEAVES
FROM BM.`biometric` AS bmt
JOIN BM.`employee` AS emp ON bmt.`empid`= emp.`empid`
LEFT JOIN `lms`.`leaves` AS lvs ON emp.`empid` = lvs.`id` AND lvs.`status` = '3' AND `startdate`<='$monthEnd' AND `endDate`>= '$monthStart'
GROUP BY bmt.`Empid`;
Related
I want make a leaderboard from my database, I already make a code but the sql says error
"SET #a1 = (SELECT SUM(d.poin_diskusi)
FROM diskusi d
GROUP BY d.id_akun)
MySQL said: Documentation
#1242 - Subquery returns more than 1 row"
heres my sql query :
SET #a1 = (SELECT SUM(d.poin_diskusi)
FROM diskusi d
GROUP BY d.id_akun);
SET #a2 = (SELECT SUM(j.nilai_jawaban)
FROM jawaban j
GROUP BY j.id_akun);
SET #hasil = #a1 + #a2;
SELECT #hasil
Thank you !
this is an example data in table jawaban:
this is an example data in table diskusi:
and my desired answer:
where tera123 have 135 TOTAL(d.poin_diskusi+j.nilai_jawaban) and david123 have 90 TOTAL(d.poin_diskusi+j.nilai_jawaban)
the point is to show TOTAL for every user
It looks to me (without looking at your images; if you want to show information, please provide it in text) like you want something like:
select id_akun, sum(point_value) as total_points from (
select id_akun, sum(poin_diskusi) as point_value
from diskusi group by id_akun
union all
select id_akun, sum(nilai_jawaban) as point_value
from jawaban group by id_akun
) as point_values
group by id_akun
The problem are the GROUP BY keywords. Inside the images you provided with example data, one can see that there are multiple entries for the columns jawaban.id_akun and diskusi.id_akun. Because of that, both SELECT will return multiple rows as result, for each different value of the id columns one summed up row. Try it without the GROUP BY clause.
Hi I am new for developing.Kindly bear my codings. I have created a table arlog with id(auto increment), status, ticket number and code. Ticket and code number is set as unique. That is the duplicate of this combination cannot inserted again. But individually ticket number or cpt can be inserted as many times.It works fine. Now I want to use select query with another table with respect to the arlog table ticket number and code.Here is the select statement
$result = mysql_query("SELECT * FROM `ar` C WHERE provider='".$_SESSION['PROVIDER']
."' AND C.`TicketNo` IN ( SELECT TicketNo FROM `arlog` L where L.status NOT IN('New','Completed','Completed(Ar_aging)
','Completed(Rework)','Rework','Completed_Followup','Completed_Supervising' )
and L.assign='".$_SESSION['NAME']."' ) order by id desc") or die(mysql_error());
The query check the ticket number in arlog and displays correcly. But I want to combine TicketNo and Code in the arlog. I have made research but could not find solution. First of all is it possible?
Please try following sql:
SELECT L.TicketNo ,L.Code,C.* FROM `ar` C left join `arlog` L ON C.TicketNo = L.TicketNo where C.provider='your condition' and L.status NOT IN('New','Completed','Completed(Ar_aging)','Completed(Rework)','Rework','Completed_Followup','Completed_Supervising' ) and L.assign='your condition' order by by C.id desc
Hope this can help you!
I think you need to use CONCAT_WS()
There is a nice example of its usage in below link
MySQL SELECT AS combine two columns into one
I keep falling back into questions with MySQL joining.
And I would like to request a very simple example I could use to continue my journey of understanding learning the MySQL syntax.
Let's say I got the following table's
test_testtable
testtable_id
testtable_name
testtable_user
testtable_option
testtable_textfield
test_testlink
testlink_id
testlink_link
testlink_address
test_address
address_id
address_name
address_phone
address_email
address_street
address_city
address_zip
I would like to make a selection like :
SELECT * (lets say I would define the fields) FROM `test_testable`
JOIN `test_testtable`.`testtable_id` = `test_testlink`.`testlink_link`
AND
JOIN `test_testlink`.`testlink_addres` = `test_address`.`address_id`
WHERE `user_id` = 5
Hence the linking structure is like:
test_testtable.testtable_id = leading
table test_testlink is a table to link the table test_testtable and test_address
And linking table test_testlink uses the field testlink_link to link to the table test_testtable, and uses the field testlink_address to link to the table test_address
This does not work. FOR ME.. Since I continuously seem to fail of catching the correct syntax logic.
So I hope that someone could give me a small example of how to correctly implement such a simple yet critical query!
TIAD!!
A general approach :
SELECT table1.* FROM table1
JOIN table2 ON table2.id_table1 = table1.id
JOIN table3 ON table3.id_table2 = table2.id
WHERE table1.id = 10
For your purpose :
SELECT * (lets say I would define the fields) FROM `test_testable`
JOIN `test_testlink` ON `test_testtable`.`testtable_id` = `test_testlink`.`testlink_link`
JOIN `test_address` ON `test_testlink`.`testlink_addres` = `test_address`.`address_id`
WHERE `user_id` = 5
Please read the reference
You are using wrong syntax. You should mention which tables to join first then based on which fields.
SELECT * (lets say I would define the fields) FROM `test_testable`
INNER JOIN test_testlink
ON `test_testtable`.`testtable_id` = `test_testlink`.`testlink_link`
INNER JOIN `test_address`
ON `test_testlink`.`testlink_addres` = `test_address`.`address_id`
AND `test_testtable`.`user_id` = 5
select * from testlink JOIN testtable ON testlink.tableid = testtable.ID
JOIN testaddress ON testlink.addressid = testaddress.ID
WHERE testtable.ID = 5
I have been doing a lots of research online and from my understanding i think my query is ok
That is why i need your help to point me out what im doing wrong.
What My Query Should Do
My query should fetch our stock level from both warehouse
Problem Is
if the product is not in both warehouse the query dont give any result.
Ok so first i have two database of warehouse stock level. that look like that.
Databases
-warehouse1
-warehouse2
Table
-product
Columns
-id
-SKU
-qty
So my Query is
SELECT
warehouse1.product.id as 1_id,
warehouse2.product.id as 2_id ,
warehouse1.product.SKU,
warehouse1.product.qty as 1_qty,
warehouse2.product.qty as 2_qty
FROM `warehouse1`.`product`
LEFT JOIN `warehouse2`.`product`
ON
(`warehouse1`.`product`.`SKU` = `warehouse2`.`product`.`SKU`)
WHERE
warehouse1.product.SKU = '$sku'
OR
warehouse2.product.SKU = '$sku'
ORDER BY
(1_qty + 2_qty) DESC
if i make the where clause like this
WHERE warehouse1.product.SKU = '$sku'
it is then working but i can't get stock from both warehouse.
What should i do if i want to receive the stock level from both warehouse even if there is no product that im asking for in this database.
Thanks
Try a FULL OUTER JOIN. You're using a LEFT JOIN. That requires that the DB fetch all records that match your WHERE clause on the LEFT side of the join, which is warehouse1, and any potentially matching records from warehouse2 (the right side of the join). If a SKU exists only in warehouse2, you don't see it.
Switching to a FULL OUTER JOIN forces the DB to fetch all matching records from BOTH sides of the join, regardless of which side(s) the matching records exist on.
you can also do this with a union
(SELECT
warehouse1.product.id as 1_id,
warehouse1.product.SKU,
warehouse1.product.qty as 1_qty
FROM `warehouse1`.`product`
WHERE
warehouse1.product.SKU = '$sku' )
union
(SELECT
warehouse2.product.id as 2_id ,
warehouse2.product.SKU,
warehouse2.product.qty as 2_qty
FROM `warehouse2`.`product`
WHERE warehouse2.product.SKU = '$sku' )
Combine your OR's in () (... OR ...):
SELECT
warehouse1.product.id as 1_id,
warehouse2.product.id as 2_id ,
warehouse1.product.SKU,
warehouse1.product.qty as 1_qty,
warehouse2.product.qty as 2_qty
FROM `warehouse1`.`product`
LEFT JOIN `warehouse2`.`product`
ON
(`warehouse1`.`product`.`SKU` = `warehouse2`.`product`.`SKU`)
WHERE (warehouse1.product.SKU = '$sku'
OR
warehouse2.product.SKU = '$sku')
ORDER BY
(1_qty + 2_qty) DESC
I have two tables, Table A and Table B. For each record in table A there are many records in Table B; thus, a one to many relationship exists between tables A and B. I want to perform a query so that for each row returned from table A, all of the corresponding rows will be returned from table B. From what I understand I'll need to use a INNER Join - however, how would I go about accessing all of the returned rows through say, PHP?
$sql = "Select A.ID, B.Name * From A INNER JOIN B ON A.ID = B.ID";
A.ID | B.fName | B.lName
1 nameone lnameone
1 nametwo lnametwo
2 namethree lnamethree
4 namefour lnamefour
Now that I have the above results, I want to use PHP to loop through all of the values of B.Name only for a single A.ID at a time. So, the results I want would look like:
1.
nameOne lNameOne
nameTwo lnametwo
2. namethree lNamethree
4. nameFour lNameFour
Basically, I'm trying to group the query results by the ID in table A.
I appreciate the help very much!
Thank you,
Evan
You could just Google "php get from database," and use some normal array pre-processing, but I worry the advice you find may not be ideal. Here's what I'd do:
$pdo = new PDO('mysql:host=host;dbname=dbname', 'user', 'pass');
$result = $pdo->query(<<<SQL
SELECT
ID,
Name
FROM
A
-- Alternative to `JOIN B USING(ID)` or `JOIN B ON (A.ID = B.ID)
NATURAL JOIN B
SQL
);
$a = array();
while ($row = $result->fetch()) {
if (!isset($a[$row['ID']]) {
$a[$row['ID']] = array();
}
$a[$row['ID']][] = $row['Name'];
}
You could also GROUP BY the ID and GROUP_CONCAT the names to be exploded in PHP later to skip the manual array creation and reduce some iteration (although SQL will do more in that case).
Adding a simple ORDER BY A.ID to the SQL query would probably get you quite far in "grouping" the items together. It's difficult to give a more detailed answer without knowing exactly what you want to do with the "groups".