Receive image via PHP curl, then upload to S3 - php

Question

I am using PHP CURL to generate a customized PNG image from a REST API. Once this image has loaded I would like to upload it into an AWS S3 Bucket and show the link to it.
Here's my script so far:
$ch = curl_init();
$timeout = 5;
curl_setopt($ch, CURLOPT_URL, 'http://url-to-generate-image.com?options=' + $_GET['options']);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec($ch);
$info=curl_getinfo($ch);
curl_close($ch);
//require S3 Class
if (!class_exists('S3')) {
require_once('S3.php');
}
//AWS access info
if (!defined('awsAccessKey')) {
define('awsAccessKey', 'MY_ACCESS_KEY');
}
if (!defined('awsSecretKey')) {
define('awsSecretKey', 'MY_SECRET_KEY');
}
//instantiate the class
$s3 = new S3(awsAccessKey, awsSecretKey);
$s3->putBucket('bucket-name', S3::ACL_PUBLIC_READ);
$file_name = md5(rand(99,99999999)) + '-myImage.png';
if ($s3->putObjectFile($data, 'bucket-name' , $file_name, S3::ACL_PUBLIC_READ)) {
echo 'success';
$gif_url = 'http://bucket-name.s3.amazonaws.com/'.$file_name;
} else {
echo 'failed';
}
It keeps failing. Now, I think the problem is with where I use putObjectFile - the $data variable represents the image, but maybe it has to be passed in another way?
I am using a common PHP Class for S3: http://undesigned.org.za/2007/10/22/amazon-s3-php-class

Answer 1

Use PHP memory wrapper to store the contents of the image, and use $s3->putObject() method:
$fp = fopen('php://memory', 'wb');
fwrite($fp, $data);
rewind($fp);
$s3->putObject([
'Bucket' => $bucketName,
'Key' => $fileName,
'ContentType' => 'image/png',
'Body' => $fp,
]);
fclose($fp);
Proven method (you may need to alter the code a bit) with PHP 5.5 and latest AWS libraries.
http://php.net/manual/en/wrappers.php.php