PHP with Json + SQL - php

Question

I'm having trouble correctly display, in JSON, a result originated from two tables in my database.
The situation is this: I have orders in a table (A) and the products these orders in another table (B).
My code:
$sqlcode2 = mysql_query("Select a.numero as numOrc, a.nomeclie, a.valortotal, a.formapagto, a.emissao, b.codprod, b.qtdade, b.valorunit, b.tipopreco from orcamento a, prodorc b");
$jsonObj= array();
if($something == 'all')
{
while($result=mysql_fetch_object($sqlcode2))
{
$jsonObj[] = $result;
$teste= array('pedidos' => $jsonObj);
}
}
$final_res =json_encode($teste);
echo $final_res;
The JSON result is like this:
{
"pedidos": [
{
"numOrc": "1",
"nomeclie": "CONSUMIDOR",
"valortotal": "2.077,20",
"formapagto": "2",
"emissao": "2013-02-15 16:09:11",
"codprod": "4775",
"qtdade": "1",
"valorunit": "500,00",
"tipopreco": "B"
},
{
"numOrc": "2",
"nomeclie": "MARCELO AUGUSTO BOTURA",
"valortotal": "2.077,20",
"formapagto": "2",
"emissao": "2013-02-15 16:21:56",
"codprod": "4775",
"qtdade": "1",
"valorunit": "500,00",
"tipopreco": "B"
}
]
}
As you can see, the result is only one product in each order. I needed the result to be as below (Detalhes TAG):
{
"pedidos": [
{
"numOrc": "2",
"nomeclie": "MARCELO AUGUSTO BOTURA",
"valortotal": "2.077,20",
"formapagto": "2",
"emissao": "2013-02-15 16:21:56",
"Detalhes":
[
{
"codprod": "4775",
"qtdade": "1",
"valorunit": "500,00",
"tipopreco": "B"
},
{
"codprod": "5555",
"qtdade": "3",
"valorunit": "800,00",
"tipopreco": "A"
}
]
}
]
}

Answer 1

A quick example of what FirstOne suggests would look like this. See how the orders are selected first and then a 2nd query is used to gather additional information about that order.
$sqlcode2 = mysql_query("Select a.numero as numOrc, a.nomeclie, a.valortotal, a.formapagto, a.emissao from orcamento a");
$jsonObj= array();
if($something == 'all')
{
while($result=mysql_fetch_object($sqlcode2))
{
$sqlcode3 = mysql_query("Select b.codprod, b.qtdade, b.valorunit, b.tipopreco
FROM prodorc b WHERE b.numOrc = " . $result->numOrc);
$Detalhes = array();
while($orderResult=mysql_fetch_object($sqlcode3))
{
$Detalhes[] = $orderResult;
}
$result->Detalhes = $Detalhes;
$jsonObj[] = $result;
}
}
$teste= array('pedidos' => $jsonObj);
$final_res =json_encode($teste);
echo $final_res;