Called and canceled of the admin-ajax.php file multiple times - php

I have an issue in a Wordpress installation with a plugin. There is a calendar which you can click on a day (or a range of days) and from ajax calls through admin-ajax.php it calculates product costs.
The problem is that, when I click on a calendar cell, the admin-ajax.php is called twice. The first time for a few milliseconds and canceled immediately. Then automatically, it calls it once again and get the ajax response. When I click for a second time on a calendar cell, the admin-ajax.php is called 3 times. The first two are canceled and only the last one get a response.
I found that the code that is used for this part is the following. However, I cannot find any issue on it, even if I can see those cancelled calls on Developer console.
$('.wc-bookings-booking-form')
.on('change', 'input, select', function() {
var index = $('.wc-bookings-booking-form').index(this);
if ( xhr[index] ) {
xhr[index].abort();
}
$form = $(this).closest('form');
var required_fields = $form.find('input.required_for_calculation');
var filled = true;
$.each( required_fields, function( index, field ) {
var value = $(field).val();
if ( ! value ) {
filled = false;
}
});
if ( ! filled ) {
$form.find('.wc-bookings-booking-cost').hide();
return;
}
$form.find('.wc-bookings-booking-cost').block({message: null, overlayCSS: {background: '#fff', backgroundSize: '16px 16px', opacity: 0.6}}).show();
xhr[index] = $.ajax({
type: 'POST',
url: booking_form_params.ajax_url,
data: {
action: 'wc_bookings_calculate_costs',
form: $form.serialize()
},
success: function( code ) {
if ( code.charAt(0) !== '{' ) {
console.log( code );
code = '{' + code.split(/\{(.+)?/)[1];
}
result = $.parseJSON( code );
if ( result.result == 'ERROR' ) {
$form.find('.wc-bookings-booking-cost').html( result.html );
$form.find('.wc-bookings-booking-cost').unblock();
$form.find('.single_add_to_cart_button').addClass('disabled');
} else if ( result.result == 'SUCCESS' ) {
$form.find('.wc-bookings-booking-cost').html( result.html );
$form.find('.wc-bookings-booking-cost').unblock();
$form.find('.single_add_to_cart_button').removeClass('disabled');
} else {
$form.find('.wc-bookings-booking-cost').hide();
$form.find('.single_add_to_cart_button').addClass('disabled');
console.log( code );
}
},
error: function() {
$form.find('.wc-bookings-booking-cost').hide();
$form.find('.single_add_to_cart_button').addClass('disabled');
},
dataType: "html"
});
})
.each(function(){
var button = $(this).closest('form').find('.single_add_to_cart_button');
button.addClass('disabled');
});
And here is a screenshot from the Dev Console:
EDIT: I think I found the problem, but I am not sure. There is also this part of code which was supposed to not used at all. There is a feature for time on calendar, but it isn't activated. So, this code should not be run.
$('.wc-bookings-booking-form').on( 'date-selected', function() {
show_available_time_blocks( this );
});
var xhr;
function show_available_time_blocks( element ) {
var $form = $(element).closest('form');
var block_picker = $form.find('.block-picker');
var fieldset = $form.find('.wc_bookings_field_start_date');
var year = parseInt( fieldset.find( 'input.booking_date_year' ).val(), 10 );
var month = parseInt( fieldset.find( 'input.booking_date_month' ).val(), 10 );
var day = parseInt( fieldset.find( 'input.booking_date_day' ).val(), 10 );
if ( ! year || ! month || ! day ) {
return;
}
// clear blocks
block_picker.closest('div').find('input').val( '' ).change();
block_picker.closest('div').block({message: null, overlayCSS: {background: '#fff', backgroundSize: '16px 16px', opacity: 0.6}}).show();
// Get blocks via ajax
if ( xhr ) xhr.abort();
xhr = $.ajax({
type: 'POST',
url: booking_form_params.ajax_url,
data: {
action: 'wc_bookings_get_blocks',
form: $form.serialize()
},
success: function( code ) {
block_picker.html( code );
resize_blocks();
block_picker.closest('div').unblock();
},
dataType: "html"
});
}

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Form validation using jquery, php and sql

I am trying to validate part of a form, I am stuck on checking the database to see if a company name exists before submitting the form. This is a stripped down demo from the jquery ui modal from with the addition of checking if the company already exists. I am aware of SQL injection and am not doing anything about it just yet. At the moment the form won't submit as I'm missing something, I just don't know what yet.
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This is what I have so far
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The php side (crud.php):
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break;
case 'check':
$result = mysql_query('SELECT company_name FROM company_info WHERE company_name = "'.$company_name.'"');
$num = mysql_num_rows($result);
echo $num;
break;
}
CheckCompany returns nothing. You are returning true or false from success but that goes nowhere.
You need an outer deferred so you can return something from your ajax success, back through checkcompany out to your call.
Basically, checkcompany is called and exits/returns normally. SOme time later, the success function runs but that is independent because it's async. It's not part of your checkcompanmy function.
Ideally, you should trigger an event on ajax success that your element subscribes to.
Examples from comment below:
checkCompany(o,n) {
var retval = false;
$.ajax({
sync : true,
success: function(data) {
retval = true;
}
});
return retval;
}
OR asynch:
checkCompany(o,n) {
$.ajax({
success: function(data) {
$("#ID").trigger('ajsuccess.company');
}
});
}
OR using returned promise:
if (valid) {
checkCompany().done(function() {
do the secondary ajax call in here
}
}
checkCompany(o,n) {
return $.ajax();
}

How to disable drag and drop and browse events while an ajax request is in process?

I want to prevent the user to stop selecting or drag and drop while the previous ajax request is in process.
How can i do this...
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Here is the ajax request :
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How can i prevent the user while the previous files upload is in progress.
Updated
ok got it upto some extent (but this is also not a good idea, user can add div back from the firebug and send files again)
i have used
$( document ).ajaxStart(function() {
$( "#total" ).remove();
});
and in ajax start :
$(document).ajaxStop( function( ) {
//how can i add div back say : add <div id='total'></div> after <div id='someid'></div>
});
Is there any possibility that i can stop second ajax request while the first ajax is in process?
Apart from enabling/disabling drag and drop while ajax is in progress, I believe a better solution will be to show an transparent or translucent overlay which covers that area and prevent the user from selecting any draggable.
For disabling/enabling using jquery:
Use $( "#total" ).draggable( "disable" ); inside beforeSend() function of ajax.
Use $( "#total" ).draggable( "enable" ); inside success() of function ajax
Using CSS:
demo: http://jsfiddle.net/lotusgodkk/GCu2D/184/
CSS:
.checked {
position:fixed;
top:0;
left:0;
right:0;
bottom:0;
background:#BFBFBF;
opacity:0.5;
text-align:center;
}
.checked div {
margin:0 auto;
top:50%;
left:50%;
position:absolute;
}
HTML:
<div class="checked">
<div>Please wait...</div>
</div>
Just toggle the hide/show during ajax
Use $('.checked').show(); in beforeShow() and $('.checked').hide(); in success()
Finally i have used
if($.active === 0)
{
call ajax
}
else
{
alert("please wait previous request is in process");
}

datatables:jQuery loses serialize while posting

Can anybody help me with this? While alerting sData, it contains all the values I need, but when POSTing, it contains only data from current page in datatables.
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alert( "The following data would have been submitted to the server: \n\n"+sData );
$( {
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Alert: (2 checkboxes checked on 1 and two on second page)
id=2205&id=2204&id=2181&id=2179
POST: (2 checkboxes checked on current page)
id=2181&id=2179
Instead of fnGetNodes, use $
Example:
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jQuery(function ($) {
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$.post('listen.php', {
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UPDATE
PHP code:
<?php
if ( $_POST['action'] == 'follow' ) {
$json = '';
if ( $_POST['fid'] == "2" ) {
$json = array( array( "id" => 1 , "name" => "luca" ),
array( "id" => 2 , "name" => "marco" )
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}
echo json_encode($json);
}
?>
jQuery code:
$.ajax({
type: 'POST',
url: 'listen.php',
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it's XMLHTTP Object that is responsible behind the scene.
your php script should output text... so lets say the query works output "YES" if it doesn't output "NO" then use this function in your $.post():
function (data) {
if(data=="YES"){
// worked
}
else{
// didn't work
}
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