How to create query by using php [closed] - php

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I try to get list after query by using php drop down list.
My code looks like this for now:
$con = mysql_connect($server,$user_name,$password,$database);
$db_found = mysql_select_db($database, $con);
if ($db_found) {
print "Database Found ";
}
else {
print "Database NOT Found ";
}
$result = mysql_query($con,$db_found,"SELECT
connection_log.user,count(*)
as 'connection_count', sum(TIMESTAMPDIFF(MINUTE,
connection_log.logondate,connection_log.logoffdate))
as `connection_time`
FROM connection_log
INNER JOIN users
ON connection_log.user=users.user WHERE users.groups
LIKE '%cpg_sirket_dyo%'
and connection_log.logondate>='2015-09-01 00:00:00'
and connection_log.logoffdate<'2015-10-01 00:00:00'
group by connection_log.user
order by connection_count desc");
while ($row = mysql_fetch_array($result)) {
echo $row['name']."<br />";
}
But when I run this php I get some error like shown below:
Database Found PHP Warning: mysql_query() expects at most 2 parameters, 3 >given in /var/www/html/test.php on line 22
PHP Warning: mysql_fetch_array() expects parameter 1 to be resource, null >given in /var/www/html/test.php on line 23
Have you any idea?

Answer 1

mysql_query
mysql_query ( string $query [, resource $link_identifier = NULL ] )
Only need two parameter needed
1)Your query.
2)The MySQL connection
You just remove your database name inside your mysql_query also swap position of query and connection
$result = mysql_query("SELECT....",$con);
Use backtick in column and table name instead of quotes
Correct your qyery with
SELECT
connection_log.user,count(*)
as `connection_count`, sum(TIMESTAMPDIFF(MINUTE,
connection_log.logondate,connection_log.logoffdate))
as `connection_time`
FROM connection_log
INNER JOIN users
ON connection_log.user=users.user WHERE users.groups
LIKE '%cpg_sirket_dyo%'
and connection_log.logondate>='2015-09-01 00:00:00'
and connection_log.logoffdate<'2015-10-01 00:00:00'
group by connection_log.user
order by connection_count desc
Note:- mysql is deprecated instead use mysqli or PDO

Answer 2

Have a look at http://php.net/manual/en/function.mysql-query.php
There are only 2 parameters, the query and (optinal) the connection, so you have to use:
$result = mysql_query("SELECT ...", $con);

Answer 3

You need to remove this $db_found out of your function :
http://php.net/manual/en/function.mysql-query.php
$result = mysql_query($yourQuery,$con);
Also try using mysqli instead of mysql which is deprecated.
MySQL vs MySQLi when using PHP

Answer 4

Use below code,
$con = mysql_connect($server,$user_name,$password);
$db_found = mysql_select_db($database);
if ($db_found) {
print "Database Found ";
}
else {
print "Database NOT Found ";
}
$result = mysql_query("YOUR QUERY",$con);
while ($row = mysql_fetch_array($result)) {
echo $row['name']."<br />";
}