I am passing several zip codes(retrieved by a previous lat/long search) and other data via GET to another page that will retrieve all listings from a database that contains those zip codes in the address.
So the url looks like this:
http://blahblahblah.com/listings.php?date=2015-10-23&zc=0=23547&1=28456&2=27678
My question is how do I loop through those zip codes in my db query? It seem like running a separate query for each zip code would be pretty taxing if given to many zipcodes.
$zc = array(); //initiate the array
$zc[0] = $_POST['zip']; // Add the starting zip code to the array
mysqli_query($conn, "select * zip_code within a certain range of lat and lng");
// return results
while($row = mysqli_fetch_assoc($sql)){
$zip = $row['db_zip'];
array_push($zip);
}
So there is how I am getting the info into the array. After that it is on to building the URL to display a link on a calendar for each day of the month that there is a listing.
//A ton of other stuff then
//echo the link using html_build_query() to add the zips to the get parameters.
echo ''.$d_count.'';
So then I am on to processing the info on the next page, which is where I am really confused.
Ok guys given the number of zip codes I could end up passing, GET was not going to work.
The solution that Mike gave was indeed correct, however, it had to be done by passing the zip codes to the next page via sessions.
Like so:
$_SESSION['zc'] = $zc;
and then imploding the array using the imploded data in the query:
$tmp = implode(", ", $_SESSION['zc']);
$sql = mysqli_query($conn, "SELECT * FROM listingss WHERE zipcode IN ($tmp) AND l_date = '$date'");
listings.php?date=2015-10-23&zc[]=23547&zc[]=28456&zc[]=27678
use implode function of php like this
$tmp = implode(",", $zc);
and then
SELECT * FROM TABLE WHERE zip_code in ($tmp);
Related
I've been writing some code that essentially collects information based on schools and the user search input. Once the information is pulled up, I also query a database containing users to show how many are signed up at each school, and then another database containing files showing how many files have been uploaded from each school.
I imagine this would require a three tiered loop? If I query the school database and then the student database in succession it works great (Every school will have the appropriate number of students signed up displayed). However the problem is with the files. If I add in the file query, it will only show the first two results of the schools.
This leads me to believe that the file database query isn't correct and after testing a two tiered loop (this time will files instead of students) it appears to be the case. So, what am I doing wrong with the file database code? I copied it directly from the student database code so I haven't a clue why this one won't work. Here is the code that works:
mysql_select_db($database_geographic, $geographic);
$query_school = "SELECT * FROM geographic.school WHERE countryid='$countryid' AND stateid='$stateid' ORDER BY school_name ASC";
$school = mysql_query($query_school, $geographic) or die(mysql_error());
$totalRows_schools = mysql_num_rows($schools);
while ($row_school = mysql_fetch_assoc($school)) {
echo $row_school['school_name'];
echo $row_school['city_name'];
echo $row_school['state_name'];
echo $row_school['schoolid'];
$schoolid = $row_school['schoolid'];
mysql_select_db($database_user_information, $user_information);
$query_users = "SELECT COUNT(*) AS studentcount FROM users WHERE school_name= '$schoolid'";
$users = mysql_query($query_users, $user_information) or die(mysql_error());
while ($row_users = mysql_fetch_assoc($users)) {
echo $row_users['studentcount']; }
But if I throw in this third files loop statement it will not work.
mysql_select_db($database_files, $files);
$query_files = "SELECT COUNT(*) AS filecount FROM file_data WHERE school_id= '$schoolid'";
$files = mysql_query($query_files, $files) or die(mysql_error());
while ($row_files = mysql_fetch_assoc($files)) {
echo $row_files['filecount']; }
}
If I use the file query in place of the student query it will not work either. The problem must be with the file query but I can't figure it out. Any help would be awesome! Thanks!
I have a postgres table with four columns labelled dstart which is date data type,
dend which is also a date data type, dcontract which is a date data type and id which is a integer. I am trying to run a php code to get the data using an array and use it in the body of my application. But when I test the array and try to echo some values... My browser just displays the word array... Is there anyway I can be able to retrieve the data or fix this code? Please see code below
<?php
function getLiveDate($campid)
{
global $conn,$agencies;
$return=array(
'livedate'=>'',
'campid'=>'',
'enddate'=>'',
'dateContract'=>'',
);
$sql = "SELECT id, dcontract, dstart, dend
FROM campaigns
WHERE id = '".$campid."' ORDER BY dstart DESC LIMIT 1";
$r = pg_query($conn,$sql);
if ($r)
{
$d = pg_fetch_array($r);
if (!empty($d))
{
$return['livedate'] = $d['dstart'];
$return['campid'] = $d['id'];
$return['enddate'] = $d['dend'];
$return['dateContract'] = $d['dcontract'];
}
}
#pg_free_result($r);
return $return;
}
I am pretty sure, your array $d is "multi-dimensional" and pg_fetch_array() returns an array of arrays, because the result of SQL queries in general may contain multiple rows. You limited it to one row, but you certainly get the correct values by assinging $return['livedata'] = $d[0]['dstart']; or $return['livedata'] = $d['dstart'][0]; and so on (I am not familiar with that particularly function for I usually use MySQL instead of Postgre).
Besides, try echoing your data by means of print_r() instead of echo.
The $return variable is an array, if you want shows the content, you must use print_r or var_dump not echo.
In the project that I am creating, I have a mysql column that is an array of different pieces of data from the database. These pieces of data have info that I want to display. In order to separate these items in the array I used,
$get_query = mysql_query('Select array FROM data');
while($dataRow = mysql_fetch_assoc($getfrnd_query)) {
$array = $dataRow['array'];
if($array != "") {
$data_from_array_column = explode("," $array);
$getdata = mysql_query("SELECT * FROM info WHERE item = $data_from_array_column");
//Then I used a mysql_fetch_assoc to get data based on the item.
}
}
When I run this code, I get an error "Array to string conversion on the line with $getdata".
Is there any way to get this to work?
Thank you.
The problem is that explode returns an array containing the strings in between the character(s) you used as a delimiter (, in your case), not a string.
PHP is getting mad because it doesn't know how to convert your array to a string automatically. So, you will need to convert it yourself. The options are:
You want to select the row where item is equal to the nth element in the array, $data_from_array_column. If this is the case, you need to insert the following line of code after your explode:
$data_from_array_column = $data_from_array_column[0];
If you want to select where it matches any of the elements in the $data_from_array_column array, it will get more complicated. You would need to add this line after the explode:
$data_from_array_column = implode("' OR item='",$data_from_array_column);
and change your query on the next line to:
$getdata = mysql_query("SELECT * FROM info WHERE item='$data_from_array_column'");
This will create a MySQL query that looks some thing like this:
SELECT * FROM info WHERE item='foo' OR item='bar' OR item='bla'
I have a question on how to go about the next phase of a project I am working on.
Phase I:
create a php script that scraped directory for all .txt file..
Open/parse each line, explode into array...
Loop through array picking out pieces of data that were needed and INSERTING everything into the database (120+ .txt files & 100k records inserted)..
this leads me to my next step,
Phase II:
I need to take a 'list' of several 10's of thousand of numbers..
loop through each one, using that piece of data (number) as the search term to QUERY the database.. if a match is found I need to grab a piece of data in a different column of the same record/row..
General thoughts/steps I plan to take
scrape directory to find 'source' text file.
open/parse 'source file'.... line by line...
explode each line by its delimiting character.. and grab the 'target search number'
dump each number into a 'master list' array...
loop through my 'master list' array.. using each number in my search (SELECT) statement..
if a match is found, grab a piece of data in another column in the matching/returned row (record)...
output this data.. either to screen or .txt file (havent decided on that step yet,..most likely text file through each returned number on a new line)
Specifics:
I am not sure how to go about doing a 'multiple' search/select statement like this?
How can I do multiple SELECT statements each with a unique search term? and also collect the returned column data?
is the DB fast enough to return the matching value/data in a loop like this? Do I need to wait/pause/delay somehow for the return data before iterating through the loop again?
thanks!
current function I am using/trying:
this is where I am currently:
$harNumArray2 = implode(',', $harNumArray);
//$harNumArray2 = '"' . implode('","', $harNumArray) . '"';
$query = "SELECT guar_nu FROM placements WHERE har_id IN ($harNumArray2)";
echo $query;
$match = mysql_query($query);
//$match = mysql_query('"' . $query . '"');
$results = $match;
echo("<BR><BR>");
print_r($results);
I get these outputs respectively:
Array ( [0] => sample_source.txt )
Total FILES TO GRAB HAR ID's FROM: 1
TOAL HARS FOUND IN ALL FILES: 5
SELECT guar_nu FROM placements WHERE har_id IN ("108383442","106620416","109570835","109700427","100022236")
&
Array ( [0] => sample_source.txt )
Total FILES TO GRAB HAR ID's FROM: 1
TOAL HARS FOUND IN ALL FILES: 5
SELECT guar_nu FROM placements WHERE har_id IN (108383442,106620416,109570835,109700427,100022236)
Where do I stick this to actually execute it now?
thanks!
update:
this code seems to be working 'ok'.. but I dont understand on how to handle the retirned data correctly.. I seem to only be outputting (printing) the last variable/rows data..instead of the entire list..
$harNumArray2 = implode(',', $harNumArray);
//$harNumArray2 = '"' . implode('","', $harNumArray) . '"';
//$query = "'SELECT guar_num FROM placements WHERE har_id IN ($harNumArray2)'";
$result = mysql_query("SELECT har_id, guar_num FROM placements WHERE har_id IN (" . $harNumArray2 . ")")
//$result = mysql_query("SELECT har_id, guar_num FROM placements WHERE har_id IN (0108383442,0106620416)")
or die(mysql_error());
// store the record of the "example" table into $row
$row = mysql_fetch_array($result);
$numRows = mysql_num_rows($result);
/*
while($row = #mysql_fetch_assoc($result) ){
// do something
echo("something <BR>");
}
*/
// Print out the contents of the entry
echo("TOTAL ROWS RETURNED : " . $numRows . "<BR>");
echo "HAR ID: ".$row['har_id'];
echo " GUAR ID: ".$row['guar_num'];
How do I handle this returned data properly?
thanks!
I don't know if this answers your question but I think you're asking about sub-queries. They're pretty straightforward and just look something like this
SELECT * FROM tbl1 WHERE id = (SELECT num FROM tbl2 WHERE id = 1);
That will only work if there is one unique value to that second subquery. If it returns multiple rows it will return a parse error. If you have to select multiple rows research JOIN statements. This can get you started
http://www.w3schools.com/sql/sql_join.asp
I am not sure how to go about doing a 'multiple' search/select statement like this?
With regards to a multiple select, (and I'll assume that you're using MySQL) you can perform that simply with the "IN" keyword:
for example:
SELECT *
FROM YOUR_TABLE
WHERE COLUMN_NAME IN (LIST, OF, SEARCH, VALUES, SEPARATED, BY COMMAS)
EDIT: following your updated code in the question.
just a point before we go on... you should try to avoid the mysql_ functions in PHP for new code, as they are about to be deprecated. Think about using the generic PHP DB handler PDO or the newer mysqli_ functions. More help on choosing the "right" API for you is here.
How do I handle this returned data properly?
For handling more than one row of data (which you are), you should use a loop. Something like the following should do it (and my example will use the mysqli_ functions - which are probably a little more similar to the API you've been using):
$mysqli = mysqli_connect("localhost", "user", "pass");
mysqli_select_db($mysqli, "YOUR_DB");
// make a comma separated list of the $ids.
$ids = join(", ", $id_list);
// note: you need to pass the db connection to many of these methods with the mysqli_ API
$results = mysqli_query($mysqli, "SELECT har_id, guar_num FROM placements WHERE har_id IN ($ids)");
$num_rows = mysqli_num_rows($results);
while ($row = mysqli_fetch_assoc($results)) {
echo "HAR_ID: ". $row["har_id"]. "\tGUAR_NUM: " . $row["guar_num"] . "\n";
}
Please be aware that this is very basic (and untested!) code, just to show the bare minimum of the steps. :)
Hey all i am trying to figure out a way to see what all values are within the array:
$sql = "select * from product where type = ? limit 1";
$query = self::$__CONN__->prepare($sql);
$query->execute(array($type)) or die(print_r($query->errorinfo()));
I am new at PHP and im not sure what all that is doing to populate the query string. I am guessing that the first query is connecting to the server and sending out the query but how do i see what its returning back in the array above?
Any help would be great!
Just dump the $type variable
var_dump($type);
Or if you are interested in the array wrapper itself
var_dump(array($type));