mongodb php query in documents with nested objects - php

Question

So here is a sample of a document in my mongodb collection:
{
"_id" : ObjectId("561e0de61c9218b7bf9877c3"),
"Date" : NumberLong(20151014),
"Hour" : NumberLong(10),
"ProductId" : ObjectId("5614ba9c2e131caa098b4567"),
"ProductName" : "Test",
"ProducerId" : ObjectId("5617802151f8adf4db329d52"),
"ProducerName" : "Producer",
"ProducerRate" : NumberLong(300),
"ProducerMedium" : "Emailer",
"TotalLead" : NumberLong(6),
"VerifiedLead" : NumberLong(3),
"UnverifiedLead" : NumberLong(2),
"UnQualifiedLead" : NumberLong(1),
"TotalEarning" : NumberLong(660),
"Consumers" : [
{
"ConsumerId" : ObjectId("5617802151f8adf4db329d54"),
"ConsumerName" : "Consumer1",
"ConsumedRate" : NumberLong(120),
"ConsumedLead" : NumberLong(3),
"Earning" : NumberLong(360)
},
{
"ConsumerId" : ObjectId("5617802151f8adf4db329d58"),
"ConsumerName" : "Consumer2",
"ConsumedRate" : NumberLong(100),
"ConsumedLead" : NumberLong(3),
"Earning" : NumberLong(300)
}
]
}
Now i want to get the ConsumedLead grouped by ConsumerId and ProductId from the database in php.
what i have did so far to give me TotalLead and VerifiedLead grouped by product id but have no idea how to get consumerbased results for same:
$keyf = new MongoCode('function(doc) {
return {\'ProductId\': doc.ProductId,\'ProductName\': doc.ProductName};
}');
$initial = array('TotalLead'=>0,'VerifiedLead'=>0);
$reduce = "function(obj, prev) {
prev.TotalLead += obj.TotalLead;
prev.VerifiedLead += obj.VerifiedLead;
}";
$result = $collection->group($keyf, $initial, $reduce);
var_dump($result);
Any Help Please.
EDIT:
expected result wpuld be :
{ [0]=> array(4) { ["ProductId"]=> object(MongoId)#8 (1) { ["$id"]=> string(24) "5614ba9c2e131caa098b4567" } ["ProductName"]=> string(4) "Test" ["ConsumerId"]=> object(MongoId)#8 (1) { ["$id"]=> string(24) "5617802151f8adf4db329d58" } ["ConsumedLead"]=> float(4) } }

Answer 1

The solution is to use the aggregation framework where the operation includes an $unwind operator initial pipeline stage as this will deconstruct the Consumers array field from the input documents and outputs a document for each element. Each output document replaces the array with an element value. This will then make it possible for the $sum group accumulator operator in the $group step to work and thus givies you the required ConsumedLead grouped by ConsumerId and ProductId:
db.collection.aggregate([
{
"$unwind": "$Consumers"
},
{
"$group": {
"_id": {
"ProductId": "$ProductId",
"ConsumerId": "$Consumers.ConsumerId"
},
"TotalConsumedLead": {
"$sum": "$Consumers.ConsumedLead"
}
}
}
])
Running this aggregation operation on the above sample will result:
/* 0 */
{
"result" : [
{
"_id" : {
"ProductId" : ObjectId("5614ba9c2e131caa098b4567"),
"ConsumerId" : ObjectId("5617802151f8adf4db329d58")
},
"TotalConsumedLead" : NumberLong(3)
},
{
"_id" : {
"ProductId" : ObjectId("5614ba9c2e131caa098b4567"),
"ConsumerId" : ObjectId("5617802151f8adf4db329d54")
},
"TotalConsumedLead" : NumberLong(3)
}
],
"ok" : 1
}
So your final working aggregation in PHP should be:
$pipeline = array(
array('$unwind' => '$Consumers'),
array(
'$group' => array(
'_id' => array(
'ProductId' => '$ProductId',
'ConsumerId' => '$Consumers.ConsumerId',
),
'TotalConsumedLead' => array(
'$sum' => '$Consumers.ConsumedLead'
),
)
),
);
$out = $collection->aggregate($pipeline ,$options);