copying json object to javascript array - php

Question

I want to copy json object to javascript array,
{
"profiledata1":{"id":0,"music":0,"image_x":130,"image_y":155,"mouth_x":0,"mouth_y":-28.125,"active":true,"default":false},
"profiledata2":{"id":1,"music":0,"image_x":130,"image_y":155,"mouth_x":0,"mouth_y":0,"active":true,"default":false},
"profiledata3":{"id":2,"music":0,"image_x":0,"image_y":0,"mouth_x":0,"mouth_y":0,"active":false,"default":false},
"profiledata4":{"id":3,"music":0,"image_x":0,"image_y":0,"mouth_x":0,"mouth_y":0,"active":false,"default":false},
"profiledata5":{"id":4,"music":0,"image_x":0,"image_y":0,"mouth_x":0,"mouth_y":0,"active":false,"default":false},
"upload":"http:\/\/localshost\/",
"format":"jpeg","status":1 }
This is my json object returned when i call some.php through ajax,
I want to copy profiledata1 to userdata_arr[0],profiledata2 to userdata_arr[1],profiledata3 to userdata_arr[2],profile4data to userdata_arr[3],profiledata5 to userdata_arr[5] in java script.
My java script is as follows,
$.ajax({
type: "POST",
url: "some.php",
data: {action:'load',
id:7}
}).done(function(o) {
var data = $.parseJSON(o);
if (!data || data === null) {
someError(true);
}else{
if(data.status==true){
userdata_arr[0] = data.profiledata1[0];
userdata_arr[1] = data.profiledata2[0];
userdata_arr[2] = data.profiledata3[0];
userdata_arr[3] = data.profiledata4[0];
userdata_arr[4] = data.profiledata5[0];
uploadDir = data.upload;
imgFormat = data.format;
somefunction();
}else{
someError(true);
}
}
});
when i execute this script i'm getting userdata_arr as undefined! Please help me to rectify this problem.
I'm also attaching the some.php here,
<?php
if ($_POST['action']=='load') {
$uid=$_POST['id'];
header("content-type:application/json");
// fetch contents from db with $uid;
$query = mysqli_query($link,$sql);
while ($row = mysqli_fetch_array($query)) {
$prof1 = $row['prof1'];
$prof2 = $row['prof2'];
$prof3 = $row['prof3'];
$prof4 = $row['prof4'];
$prof5 = $row['prof5'];
}
$jp1 = json_decode($prof1, 1);
$jp2 = json_decode($prof2, 1);
$jp3 = json_decode($prof3, 1);
$jp4 = json_decode($prof4, 1);
$jp5 = json_decode($prof5, 1);
echo json_encode($dta = array('profile1data' =>json_decode($prof1),'profile2data' =>json_decode($prof2),'profile3data' =>json_decode($prof3),'profile4data' =>json_decode($prof4),'profile5data' =>json_decode($prof5) ,'upload' =>'http://localhost/img/', 'format' =>'jpeg', 'status' =>1 )); ?>
Thanks in advance!

Answer 1

That's because you haven't declared your userdata_arr. To fix it, declare your array/object variable before using it. In your else code-block, do this:
else{
var userdata_arr = {}// declare your object
if(data.status==true){ //proceed to use your already-declared object, also notice the quote marks surrounding the object members/indexes
userdata_arr["0"] = data.profiledata1[0];
userdata_arr["1"] = data.profiledata2[0];
userdata_arr["2"] = data.profiledata3[0];
userdata_arr["3"] = data.profiledata4[0];
userdata_arr["4"] = data.profiledata5[0];
uploadDir = data.upload;
imgFormat = data.format;
somefunction();
}else{
someError(true);
}
}