How to get data of both table using join in codeigniter - php

Question

I have two array
Array
(
[0] => stdClass Object
(
[id] => 14
[employee_id] => ST0011
[emp_name] => Munish Sharma
[gender] =>
[marital_status] =>
[address] =>
[postal_code] =>
[home_phone] =>
[mobile_phone] =>
[work_email] =>
[private_email] =>
[joined_date] => 1970-01-01 00:00:00
[emp_salary] => 0
[confirmation_date] => 0000-00-00 00:00:00
[department] => HRM
[f_name] => fname
[dob] => 1970-01-01
[c_address] =>
[domainName] =>
[emp_status] => active
)
[1] => stdClass Object
(
[id] => 12
[employee_id] => ST001dasd
[emp_name] => Rakesh Negi
[gender] =>
[marital_status] =>
[address] =>
[postal_code] =>
[home_phone] =>
[mobile_phone] =>
[work_email] =>
[private_email] =>
[joined_date] => 2015-08-11 00:00:00
[emp_salary] => 0
[confirmation_date] => 0000-00-00 00:00:00
[department] => HRM
[f_name] => dsad
[dob] => 1970-01-01
[c_address] =>
[domainName] =>
[emp_status] => active
)
[2] => stdClass Object
(
[id] => 13
[employee_id] => ST001
[emp_name] => Rakesh Negi
[gender] =>
[marital_status] =>
[address] =>
[postal_code] =>
[home_phone] =>
[mobile_phone] =>
[work_email] =>
[private_email] =>
[joined_date] => 2015-08-06 00:00:00
[emp_salary] => 0
[confirmation_date] => 0000-00-00 00:00:00
[department] => HRM
[f_name] => Father Name
[dob] => 1970-01-01
[c_address] =>
[domainName] =>
[emp_status] => active
)
)
and the second array is this
Array
(
[0] => stdClass Object
(
[id] => 55
[emp_id] => ST001
[check_in] => 11:38:09
[check_out] => 00:00:00
[total_time] => 00:00:00
[status] =>
[date_time] => 2015-10-20
[emp_name] => Rakesh Negi
)
)
Now I want to make it like this
Array
(
[0] => stdClass Object
(
[id] => 14
[employee_id] => ST0011
[emp_name] => Munish Sharma
[gender] =>
[marital_status] =>
[address] =>
[postal_code] =>
[home_phone] =>
[mobile_phone] =>
[work_email] =>
[private_email] =>
[joined_date] => 1970-01-01 00:00:00
[emp_salary] => 0
[confirmation_date] => 0000-00-00 00:00:00
[department] => HRM
[f_name] => fname
[dob] => 1970-01-01
[c_address] =>
[domainName] =>
[emp_status] => active
)
[1] => stdClass Object
(
[id] => 12
[employee_id] => ST001dasd
[emp_name] => Rakesh Negi
[gender] =>
[marital_status] =>
[address] =>
[postal_code] =>
[home_phone] =>
[mobile_phone] =>
[work_email] =>
[private_email] =>
[joined_date] => 2015-08-11 00:00:00
[emp_salary] => 0
[confirmation_date] => 0000-00-00 00:00:00
[department] => HRM
[f_name] => dsad
[dob] => 1970-01-01
[c_address] =>
[domainName] =>
[emp_status] => active
)
[3] => stdClass Object
(
[id] => 55
[emp_id] => ST001
[check_in] => 11:38:09
[check_out] => 00:00:00
[total_time] => 00:00:00
[status] =>
[date_time] => 2015-10-20
[emp_name] => Rakesh Negi
)
)
I want to remove the value from first array if the em_id in the both array will be same is it possible in?
I tried using where condion with join like this
$date = date('Y-m-d');
$this->db->select('hrm_attendance.*,employees.emp_name');
$this->db->from('hrm_attendance');
$this->db->join('employees','hrm_attendance.emp_id=employees.employee_id','LEFT OUTER');
$this->db->where('hrm_attendance.date_time = "'.$date.'"');
$this->db->order_by('check_in','asc');
$query = $this->db->get();
return $query->result();
and getting this output
(
[0] => stdClass Object
(
[id] => 55
[emp_id] => ST001
[check_in] => 11:38:09
[check_out] => 00:00:00
[total_time] => 00:00:00
[status] =>
[date_time] => 2015-10-20
[emp_name] => Rakesh Negi
)
)
But I want the output I have described above
if I remove $this->db->where('hrm_attendance.date_time = "'.$date.'"'); line then I am getting the all record from both the table I want all the data from the employee table with all ID and only those data from the hrm_attendance where the emp_id is available with where condition
$this->db->where('hrm_attendance.date_time = "'.$date.'"');

Answer 1

Please check the Code igniter Docs
http://www.codeigniter.com/userguide2/database/active_record.html#select
$this->db->select('*');
$this->db->from('blogs');
$this->db->join('comments', 'comments.id = blogs.id');
$query = $this->db->get();
// Produces:
// SELECT * FROM blogs
// JOIN comments ON comments.id = blogs.id
in select('*') you can specify your limited fields also.

Answer 2

In your db->where is incorrect $this->db->where('hrm_attendance.date_time = "'.$date.'"');
http://www.codeigniter.com/user_guide/database/query_builder.html#selecting-data
public function some_name() {
$date = date('Y-m-d');
$this->db->select('*');
$this->db->from($this->db->dbprefix . 'hrm_attendance ha', 'LEFT');
$this->db->join($this->db->dbprefix . 'employees e', 'e.employee_id = ha.emp_id', 'LEFT');
$this->db->where('ha.date_time', $date);
$this->db->order_by('check_in','ASC');
$query = $this->db->get();
return $query->result();
// Or Try With result_array();
// return $query->result_array();
}

Answer 3

I find out the solution by adding some code like this
$date = date('Y-m-d');
$this->db->select('hrm_attendance.*,employees.emp_name');
$this->db->from('hrm_attendance');
$this->db->join('employees','hrm_attendance.emp_id=employees.employee_id','LEFT OUTER');
$this->db->where('hrm_attendance.date_time = "'.$date.'"');
$this->db->order_by('check_in','asc');
$query = $this->db->get();
$result = $query->result();
$count = count($result);
for($i = 0;$i<$count;$i++)
{
$id[] = $data['user_logged_in'][$i]->emp_id;
}
$this->db->select('*');
$this->db->from('employees');
$this->db->where_not_in('employee_id',$id);
$query = $this->db->get();
$data['absent'] = $query->result();
print_r($data['absent']);
By using this I got the all those employee who are not in the table hrm_attendance