I am making a test for uploading a file in Laravel 5.1 project.
One of the checking in validation method looks like this
//assuming $file is instance of UploadedFile class
if ( ! $file->isValid()) {
/*add errors and return*/
}
And I need to test this check.
The question is: How do I create an invalid uploaded file ?
(UploadedFile extends Symfony\Component\HttpFoundation\File class which extends SplFileInfo php class)
I often find it's helpful to look at the library source:
https://github.com/symfony/symfony/blob/master/src/Symfony/Component/HttpFoundation/File/UploadedFile.php
You can see that the isValid method checks if $this->error === UPLOAD_ERR_OK, which is the default.
The only way to set error, since it's a private variable, is through the constructor:
public function __construct($path, $originalName, $mimeType = null, $size = null, $error = null, $test = false)
So when creating your $file object, just make sure to set $error to something. Here's all of the available error constants:
http://php.net/manual/en/features.file-upload.errors.php
So for example you could do this:
$file = new UploadedFile($path, $origName, $mimeType, UPLOAD_ERR_INI_SIZE, true);
The last parameter is needed when testing to disable checking that file was uploaded via HTTP (in case your test actually creates file)
Related
I am using Symfony 3.4.8 and I try to create a form for uploading a file. I followed exact the Symfony document steps but got the error:
Controller "AppBundle\Report::uploadReport()" requires that you provide a value for the "$fileUploader" argument. Either the argument is nullable and no null value has been provided, no default value has been provided or because there is a non optional argument after this one.
Here is part of my code, the rest are the same from the document except I changed the class name. Clearly when the function get called, there is no FileUploader argument passed into the function. If I remove the argument FileUploader $fileUploader, the page can load without throwing exception but it won't get the file. I am new to Symfony, how can I solve this problem?
/**
* #Route("/report/create-report/upload/", name="report_create")
*/
public function uploadReport(Request $request, FileUploader $fileUploader)
{
$report = new Report();
$form = $this->createForm(ReportType::class, $report);
$form->add('submit', SubmitType::class);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
// $file stores the uploaded PDF file
/** #var Symfony\Component\HttpFoundation\File\UploadedFile $file */
$file = $report->getReport();
$fileName = $fileUploader->upload($file);
$report->setBrochure($fileName);
//$fileName = $this->generateUniqueFileName().'.'.$file->guessExtension();
// moves the file to the directory where brochures are stored
//$file->move(
// $this->getParameter('reports_directory'),
// $fileName
//);
// updates the 'brochure' property to store the PDF file name
// instead of its contents
//$report->setReport($fileName);
// ... persist the $product variable or any other work
}
return $this->render('report/createReport.html.twig', array(
'form' => $form->createView(),
));
}
I have seen the post but I cannot get that answer to work on my end as there is no such variable $container.
Last update: I gave up trying implement upload from scratch. I used the recommended bundle to make it work with minimum amount of coding.
the argument brochures_directory of your FileUploader.php service seems to be emtpy.
Did you specify it in service.yml?
Did you also add it in your config.yml ?
And then did you clear symfony cache after change ?
I'm facing following problem and can't seem to figure this one out.
I wrote an API endpoint accepting a POST with binary data (header: content-type:image/jpeg).
I know i can read out the raw string with file_get_content('php://input') or Laravel's $request->getContent().
PHP also has a function createimagefromstring($string) which also seems to read the string in correctly.
What i'd like to do is create an UploadedFile from this raw data , so that I can handle it with already written functions.
Is this possible?
Thank you in advance
I think I found it... Still curious if there are improvements that can be made..
$imgRaw = imagecreatefromstring( $request->getContent() );
if ($imgRaw !== false) {
imagejpeg($imgRaw, storage_path().'/tmp/tmp.jpg',100);
imagedestroy($imgRaw);
$file = new UploadedFile( storage_path().'/tmp/tmp.jpg', 'tmp.jpg', 'image/jpeg',null,null,true);
// DO STUFF WITH THE UploadedFile
}
You can try to use base64 encoding. Symfony have some nice stuff for this.
Your code will be smthng like this:
$base64Content = $request->request->get('base64Content'); // this is your post data
$yourFile = new UploadedBase64EncodedFile(new Base64EncodedFile($base64Content)); // this is an instance of UploadedFile
Hope it helps!
As per Laravel 8
Just follow the constructor:
* #param string $path The full temporary path to the file
* #param string $originalName The original file name of the uploaded file
* #param string|null $mimeType The type of the file as provided by PHP; null defaults to application/octet-stream
* #param int|null $error The error constant of the upload (one of PHP's UPLOAD_ERR_XXX constants); null defaults to UPLOAD_ERR_OK
* #param bool $test Whether the test mode is active
$file = new UploadedFile(
$pathIncludingFilename,
$fileName,
'image/jpeg',
null,
false
);
There is no need to manually create it, Symfony parses received $_FILES array for you. Http Request object has a FileBag property called $files with a get() method which returns an UploadedFile instance.
/** #var UploadedFile $file */
$file = $request->files->get('user-pictures-upload')[0];
$cmd = new UploadPictureCmd($file, $this->getUser()->getId());
Here is the example of generating images files using fzaninotto/faker in Symfony 4 Fixtures
class FileFixtures extends Fixture
{
private $faker;
private $parameterBag;
public function __construct(ParameterBagInterface $parameterBag)
{
$this->faker = Factory::create();
$this->parameterBag = $parameterBag;
}
public function load(ObjectManager $manager)
{
$tempFixturesPath = $this->parameterBag->get('kernel.project_dir') . '/tmp';
if (!file_exists($tempFixturesPath)) {
mkdir($tempFixturesPath);
}
$fileName = $this->faker->image($tempFixturesPath, 640, 480, 'cats', false, true);
$file = new UploadedFile($tempFixturesPath . '/' . $fileName, $fileName, 'image/jpeg', null, null, true);
//do something with $file
}
}
If it counts for anything, this is how I did it in Laravel 5.4. In my case, I wanted to be able to easily resize an image and be able to do something like this.
request()->file('image')->resize(250, 250)->store('path/to/storage');
This is what I did to the UploadedFile class.
Illuminate\Http\UploadedFile.php ~this file ships with the Laravel framework
public function resize($w, $h) {
$image = Intervention::make($this)->fit($w, $h)->save($this->getPathname());
$filesize = filesize($this->getPathname());
return new static(
$this->getPathname(),
$this->getClientOriginalName(),
$this->getClientMimeType(),
$filesize,
null,
false
);
}
Using Intervention, I resized the image that is stored in the /tmp/ folder when files are uploaded and then I saved it in the same place. Now all I do after that is create an instance of UploadedFile so that I can keep using Laravel's methods on request()->file('image'). Hope this helps.
I want to save file uploaded through form into a json file for this I need to get post data which is easily get through Request or Input class methods.
The problem is whenever I use Request or Input I can't get methods such as getClientOriginalName to get name of file and other parameters of file.
My FileController code is as below:
<?php namespace App\Http\Controllers;
use App\Http\Requests;
use Illuminate\Http\Request; // this handles both for Input and Request as in laravel 5.1 documentation
use Illuminate\Support\Facades\Input; // though added some classes to get work
use Illuminate\Support\Facades\File; // though added some classes to get work
use Illuminate\Filesystem\Filesystem; // though added some classes to get work
class FileController extends Controller
{
public function index()
{
$files = $this->getAllData();
return view('document.index', compact('files'));
}
public function create()
{
return view('document.create');
}
public function store(Request $request)
{
$name = $request->input('title');
echo $name;
$file = $request->file('afile');
if($request->hasFile('afile')) {
$file = $request->file('afile');
print_r($file); // return array of uploaded as expected
$filename = $file->getClientOriginalName(); // not working
// or
$filename = Input::file('afile')->getClientOriginalName(); // not working
echo $filename;
}
// print_r($file);
// $data= array('title'=>$name, 'afile'=>$file);
// $this->create_entry($data);
// return redirect('document');
}
}
FYI my file upload is sucessful and has got file array as
Array ( [0] => Symfony\Component\HttpFoundation\File\UploadedFile Object ( [test:Symfony\Component\HttpFoundation\File\UploadedFile:private] => [originalName:Symfony\Component\HttpFoundation\File\UploadedFile:private] => new_file_1.txt [mimeType:Symfony\Component\HttpFoundation\File\UploadedFile:private] => text/plain [size:Symfony\Component\HttpFoundation\File\UploadedFile:private] => 0 [error:Symfony\Component\HttpFoundation\File\UploadedFile:private] => 0 [pathName:SplFileInfo:private] => E:\xampp\tmp\php5680.tmp [fileName:SplFileInfo:private] => php5680.tmp ) )
The only problem is I can't get methods of Symphon2 API though i used
use Input;
or
use Illuminate\Support\Facades\Input;
Every methods of Input are not working either to check its valid or not.
Every tutorial I refer or documentation from laravel 5 uses same as I have used in my code.
So any Kind of suggestion or solution is really appreciated.
the functions as used in this documentation are working but no other methods except than that.
Your missing the use statement for the Input facade. Add the following to your use statements.
use Illuminate\Support\Facades\Input;
You may try this:
$filename = $file->getClientOriginalName();
Since you have already used the following:
$file = $request->file('afile');
The file method returns an instance of Symfony\Component\HttpFoundation\File\UploadedFile and in this case, the instance is already cached in the $file variable.
Also to make sure the upload was successful you may check it using something like this:
if($request->hasFile('afile')) {
$file = $request->file('afile');
$filename = $file->getClientOriginalName() .'.'. $file->getExtension();
}
this works for me
\Input::file('file')->getClientOriginalName();
In your form open tag add 'files' => true
{!! Form::open(array('files' => true, ....)) !!}
In the controller check first if the file has been uploaded correctly
if (!Input::file('afile')->isValid())
{
// return error 50x
}
$filename = Input::file('afile')->getClientOriginalName();
can't apply method to non-object means that Input::file(...) returned null and therefore the file wasn't uploaded or it doesn't exists. Then, when you call ->getClientOriginalName() from a null value php throws an exception.
I'm using yii framework but I think this is related to PHP
In my controller, I have the following code
$model = new Events;
$model->type_id = $type_id;
$checkFileUpload = checkFileUpload($model);
the function checkFileUpload is a custom function which contains
function checkFileUpload($model)
{
$rnd = rand(0, 9999);
$uploadedFile = CUploadedFile::getInstance($model, 'image');
if($uploadedFile->error == 0)
{
$fileName = "{$rnd}-{$uploadedFile}"; // random number file name
$model->image = $fileName;
...
I got the error get property of non-object in $uploadedFile->error.
I've tried to use reference to the model instead, but it is deprecated and does not work for me.
If I use the code of the called function (checkFileUpload) within the controller code, it works fine. I suspect that object is not passed in a correct way.
Any help?
This is because your call to CUploadedFile::getInstance returns null and not the instance you desired.
Null is returned if no file is uploaded for the specified model attribute.
— Yii Documentation
It seems like your file was not correctly uploaded. I am not a Yii Framework user, but the documentation states:
The file should be uploaded using CHtml::activeFileField.
— Yii Documentation
So you should verify that the file was actually correctly uploaded with the proper method from the Yii Framework.
PS: Objects are always passed by reference.
$model = new Events;
$type_id=$model->type_id;
$checkFileUpload = checkFileUpload($model);
function checkFileUpload($model)
{
$rnd = rand(0, 9999);
$uploadedFile = CUploadedFile::getInstance($model, 'image');
if(!isset($uploadedFile->getHasError()))
{
$fileName = "{$rnd}-{$uploadedFile}"; // random number file name
$model->image = $fileName;
The problem occurred because at the time when you are using $uploadedFile->error,the value of $uploadedFile is null.
The following line is not giving you the desired value
$uploadedFile = CUploadedFile::getInstance($model, 'image');
Which means no file has been uploaded.
Try CVarDumper::dump($_FILES,10,true);
This will tell you whether the problem is with the UPLOADING OF THE FILE or GETTING THE DETAILS OF THE UPLOADED FILE
you cant access the private property $_error $uploadedFile->_error if you are trying to. you must call $uploadedFile->getError() in your code. Also $uploadedFile will return null if no file uploaded so you must take care of that as well.
$rnd = rand(0, 9999);
$uploadedFile = CUploadedFile::getInstance($model, 'image');
if(!empty($uploadedFile) && !$uploadedFile->getHasError())
{
$fileName = "{$rnd}-{$uploadedFile}"; // random number file name
$model->image = $fileName;
will work for you.
I have worked on a codeigniter 2.1.3 application which was developed on windows running wamp 2.2 (php 5.4.3). I recently uploaded the application to a ubuntu 12.04 server running apache 2.2.22 and php 5.4.6.
My model classes are named like billView.php, categoryModel.php etc. Note the capital letters. The name of the classes inside the php files is also the same. And the name i give when calling the models from controller classes is also the same.
But when I run my app on Ubuntu, I get this error
Unable to locate the model you have specified: billview
The error is thrown from this line:
$this->load->model('billView');
(i.e. php is ignoring the capital letter)
When I rename the model file (only the model filename, class name stays intact) then the error disappears.
How to solve this problem without manually renaming all my files?
From the documentation:
Where Model_name is the name of your class. Class names must have the
first letter capitalized with the rest of the name lowercase. Make
sure your class extends the base Model class.
It's better to follow the naming convention than to work around it.
Hope this helps.
The problem that you are facing is that Windows filesystem (NTFS) is case insensitive, so in windows, billview.php and billView.php are the same file.
On Linux, as you might be guessing now, the typical filesystems (ext2/3/4, xfs, reiserfs...) are case sensitive, and for that reason, billview.php and billView.php are (or may be) different files. In your case, one exists and the other does not.
Inside CodeIgniter autoloader function/method/class/whatever, it is trying to require the file that has the class you are instantiating, so if you tell it that you need the model billview, it will try to require path/to/model/billview.php;, and this file does not exist, so the model doesn't get loaded and then your application fails.
Of course it is recommended to follow a naming convention if there is one as Amal Murali suggests, but it is not the issue here. If all your classes, files, and instances in code had the same capitalization (whether it may be all_lowercase, ALL_UPPERCASE, camelCase or sTuPiD_CaSe) everything would have worked.
So, please refer to your files/class names with the same capitalization as you have created them, and the capitalization in a class name should follow that of the file name it is stored in.
You will have the same problems if your html code refers to files (images, css, js files) in different capitalization for the same reason. The webserver will be looking for image.jpg but it will not exist (the existing file would be Image.JPG for example).
In a related note, variables in php are case sensitive, but functions and classes aren't. despite that, call them always with the right capitalization to avoid problems.
I personally have found this convention in CodeIgniter to make no sense. I wouldn't recommend hacking the CodeIgniter core but you can easily extend the CI_Loader class. Here is mine from CI version 2.2.0.
<?php
class MY_Loader extends CI_Loader
{
/**
* Model Loader
*
* This function lets users load and instantiate models.
*
* #param string the name of the class
* #param string name for the model
* #param bool database connection
* #return void
*/
public function model($model, $name = '', $db_conn = FALSE)
{
if (is_array($model))
{
foreach ($model as $babe)
{
$this->model($babe);
}
return;
}
if ($model == '')
{
return;
}
$path = '';
// Is the model in a sub-folder? If so, parse out the filename and path.
if (($last_slash = strrpos($model, '/')) !== FALSE)
{
// The path is in front of the last slash
$path = substr($model, 0, $last_slash + 1);
// And the model name behind it
$model = substr($model, $last_slash + 1);
}
if ($name == '')
{
$name = $model;
}
if (in_array($name, $this->_ci_models, TRUE))
{
return;
}
$CI =& get_instance();
if (isset($CI->$name))
{
show_error('The model name you are loading is the name of a resource that is already being used: '.$name);
}
//$model = strtolower($model);
foreach ($this->_ci_model_paths as $mod_path)
{
if ( ! file_exists($mod_path.'models/'.$path.$model.'.php'))
{
continue;
}
if ($db_conn !== FALSE AND ! class_exists('CI_DB'))
{
if ($db_conn === TRUE)
{
$db_conn = '';
}
$CI->load->database($db_conn, FALSE, TRUE);
}
if ( ! class_exists('CI_Model'))
{
load_class('Model', 'core');
}
require_once($mod_path.'models/'.$path.$model.'.php');
//$model = ucfirst($model);
$CI->$name = new $model();
$this->_ci_models[] = $name;
return;
}
// couldn't find the model
show_error('Unable to locate the model you have specified: '.$model);
}
}
?>
All I did was copy the the CI_Loader::model method then comment out these two lines
//$model = strtolower($model);
//$model = ucfirst($model);
All you have to do is put the above class in your application/core/ folder and it should work.