how to insert different multiple arrays in mysql using php - php

Question

I have a form something like below:
<input name="first_name[]" type="text">
<input name="last_name[]" type="text">
<input name="email[]" type="email">
I am using while loop to print/echo number of groups of above form fields it required.
There will be multiple data in it, i'm not understanding how use insert query to insert data in mysql table using php.

Answer 1

First, you will need to know how many records you are trying to insert. I used first_name for this, but you could use any of them. (I am assuming since these are grouped together that you will always have the same number of first_name, last_name, and email.):
$count = count($_POST['first_name']);
After you know that, you can build an SQL statement that will insert all of the records in one query:
$sql = "INSERT INTO people (first_name, last_name, email) VALUES ";
$sql .= implode(', ', array_fill(0, $count, '(?, ?, ?)'));
The second line (implode...) will create sets of placeholders in the statement for each record you are trying to insert. (The three question marks represent the three columns you are inserting.) For example, if you had two field groups, the statement would look like:
INSERT INTO people (first_name, last_name, email) VALUES (?, ?, ?), (?, ?, ?)
After you have created the SQL string, you can create a new PDO connection and use that connection to create a prepared statement using your SQL.
$pdo = new PDO($dsn, $user, $password);
$statement = $pdo->prepare($sql);
Next you need to bind your values to the prepared statement. There are various different ways to do this. Here is one example:
// Create a multidimensional array using each of the fields from your field groups
$columns = array($_POST['first_name'], $_POST['last_name'], $_POST['email']);
$index = 1; // This is the index of the placeholder in the prepared statement
for ($i=0; $i < $count; $i++) { // This will loop as many times as you have field groups
$row = array_column($columns, $i);
// using array_column will pull everything from the $i index of each of the sub-arrays
// e.g. first_name[$i], last_name[$i], email[$i]
foreach ($row as $value) {
// bind the value and increment the index
$statement->bindValue($index, $value);
$index++;
}
}
After you have bound all the parameters, you can execute the prepared statement:
$statement->execute();

Answer 2

You can try something like this (you can find comments in the code):
if (isset($_POST['yourSubmitButton']) && isset($_POST['first_name'])) {
try {
$conn = new PDO("mysql:host=localhost;dbname=mysql", 'db_username', 'db_password');
}
catch(PDOException $e) {
echo $e->getMessage();
die();
}
$sql = 'INSERT INTO your_table (first_name, last_name, email) VALUES ';
$sql_append = array(); //Here we have the placeholder to be inserted
$binds = array(); //Here he have the values for the placeholders
for($i = 0; $i < count($_POST['first_name']); $i++) {
if (!( isset($_POST['first_name'][$i]) && isset($_POST['last_name'][$i]) && isset($_POST['email'][$i]) )) {
//We need all the values to be valid
continue;
}
//Add the placeholders and bind values
$sql_append[] = '(first_name = :first_name'.$i.', last_name = :last_name'.$i.', email = :email'.$i.')';
$binds[':first_name'.$i] = $_POST['first_name'][$i];
$binds[':last_name'.$i] = $_POST['last_name'][$i];
$binds[':email'.$i] = $_POST['email'][$i];
}
//Implode and add to the query and then execute
$sql = $sql.implode(', ', $sql_append).';';
$stmt = $conn->prepare($sql);
$stmt->execute($binds);
}
If you have 2 rows $sql will have:
echo $sql;
Result:
INSERT INTO your_table (first_name, last_name, email) VALUES (first_name = :first_name0, last_name = :last_name0, email = :email0), (first_name = :first_name1, last_name = :last_name1, email = :email1);