Quick question (hopefully)
I am saving a form as a pdf using php and would like to save the $filename as something like:
/New_Form_[user].pdf
(where [user] is $POST['forename']+$POST['surname'])
Is this possible? if so how?
my current code:
$filename = "HTC_619 New User.pdf";
The "New User" bit i want auto populated from Firstname and Surname from the form.
so:
$filename = "HTC_619_$POST['Forename']_$POST['Surname']
Thanks
Phil
yes you can do it like
header("Content-Disposition: attachment; filename=\"$filename\"")
$filename = "HTC_619". $username."_".$surname.".pdf";
pass the post first name and last name in $filename variable
$name=$_POST['forename']+$_POST['surname'];
$filename="htc_619"."_".$name.".pdf";
Related
I'm creating a PDF page from an html form, so my php looks like this (for example):
$pdf->Cell(0,0,$_POST['teacher_name'],0,2,'C');
What is my missing step that I can define that variable (teacher_name) to create my output file as:
$pdf->Output('homework-teacher_name.pdf', 'D');
and the teacher_name in the output is replaced by whatever is submitted in the form?
$fileName = 'homework-' . $_POST['teacher_name'] . '.pdf';
$pdf->Output($fileName, 'D');
Remember to sanitize external inputs using filter_input
nb. order of Output() parameters! according to http://www.fpdf.org/en/doc/output.htm ist should be:
$pdf->Output('D', $fileName);
$fullname = $row["fullname"];
$pdf_file_name = $fullname.".pdf";
$pdf->Output($pdf_file_name,'D');
It is working.
I have created a form that submits the data to a filename on the server. The form submit is working fine, it generates the requested file called "we_input_.sts".
I am trying to use the following code to grab two variables from the form "bfstnme" and "gfstnme"and attach them to the filename eg "wed_import-Jane_Bill.sts
This is the amended code: However I am still unable to get it to work.
I am trying different ideas to get this to work correctly. I have tried moving the code around but I'm still obviously missing something. The last line before the $savestring== is "$fp=fopen("wed-import-.sts", "a+");
The last lines after the $savestring are : fwrite($fp,$savestring); fclose($fp);
<?php
$bfirstname = $_POST['bfstnme'];
$gfirstname = $_POST['gfstnme'];
$file = 'wed_import_.sts';
$current = file_get_contents($file);
$new_file = 'wed_input_'.$bfirstname.'&'.$gfirstname.'.sts';
file_put_contents($new_file, $current);
?>
Here is the way I have solved it using the valuable assistance of all concerned.
$names .= ("$bfstnme" . "$gfstnme");
$fp = fopen("wed_import_($names).sts", "a+");
The results of the above give me a filename called:
"wed_Import_[JaneBill].sts. I only need to work out how to put an amperstand (&) betwen the names.
Thank you to all.
If you want put the info inside the file you must change the + by a . like this:
$current .= ("gfirstname" . "bfirstname");
If you want change the name, you must do something like #Jay_P says
Why you don't name the file before writing to it?
<?php
$gfirstname = $_POST['gname'];
$bfirstname = $_POST['bname'];
$file = 'wed_input_Bride_Groom.sts';
// Opens the file to get existing content hopefully
$current = file_get_contents($file);
// Appends bride and groom first names to the file hopefully
$current .= ("gfirstname" . "bfirstname");
$new_file = 'wed_input_'.$gfirstname.'_'.$bfirstname.'.sts';
// Write the contents back to the file
file_put_contents($new_file, $current);
?>
Let's assume you have the names in a variable called $names. You can easily append the text with the FILE_APPEND flag like this:
file_put_contents('wed_input_Bride_Groom.sts', $names, FILE_APPEND);
I hope someone can help me with this php code.
At the moment its just saving an image with the file name "img.png" to the server but with every time a new canvas screenshot is taken the image is just overwritten.
My aim is to create a new unique (like numbered chronological by time taken) file name for the images with every new screenshot and save it on the server.
Here the php code so far:
$data = $_REQUEST['base64data'];
echo $data;
$image = explode('base64,',$data);
file_put_contents('img.png', base64_decode($image[1]));
Thank you.
regards
Try
$filename = 'img_'.date('Y-m-d-H-s').'.png';
file_put_contents($filename, base64_decode($image[1]));
This will save your file with a filename containing the current date and time, e.g.
img_2013-09-19-21-50.png
Try using a session variable to increment a counter like so:
<?php
session_start();
if(!isset($_SESSION['counter'])){
$_SESSION['counter'] = 0;
}
$_SESSION['counter']++;
$data = $_REQUEST['base64data'];
echo $data;
$image = explode('base64,',$data);
file_put_contents('img'.$_SESSION['counter'].'.png', base64_decode($image[1]));
?>
There's several ways to do it, but the easiest is just to add a timestamp/datestamp to the image name. Format the name as you want.
$img_name = 'img'.date('YmdHisu').'.png'; // Date & time with microseconds
$img_name = 'img'.time().'.png'; // unix timestamp
Leave the base64data structure use this one it will work fine.
$fileName = preg_replace('#[^a-z.0-9]#i', '', $fileName);
$image = explode(".", $fileName);
It will give a random number to each image file.
either create a UID using uniqid() function for the filename or create a folder with the name of the username who is uploading the file and leave the original filename. The disadvantage of the first one is that you will have to save the original filename somewhere to show to the user.
https://stackoverflow.com/a/4371988/2701758
**
/* simply for local time first give your continent then '/' then your country's
capital.
*/
date_default_timezone_set('Asia/Dhaka');
$now = new DateTime();
$now = $now->format("Y-m-d H:i:s.u");
$new_name = $now.$image;
/*what you want to add just write with dot,such
$new_name = 'img'.$now.$image;
*/
**
this way i load image using php:
header("Content-type: image/jpeg");
$image=imagecreatefromjpeg("http://i.imgur.com/zWaQJNCb.jpg");
imagejpeg($image);
but problem is, if i want to save the image manually from my web browser to my desktop then all the images has same name like ix.jpeg [here file name is: ix.php] but i cant understand what is the way to configure the header so that images will have random name.. like 25xc.jpeg, 36s5a2f.jpeg... while saving it on desktop.. any idea?
this is will do the job!
$dt = date(time());
header("Content-type: image/jpeg");
header('Content-Disposition: inline; filename="'. $dt .'.jpg"');
$image=imagecreatefromjpeg("http://i.imgur.com/knNxDFnb.jpg");
imagejpeg($image);
Use the filename value in your header call. See Example 1.
<?php
// We'll be outputting a PDF
header('Content-type: application/pdf');
// It will be called downloaded.pdf
header('Content-Disposition: attachment; filename="downloaded.pdf"');
// The PDF source is in original.pdf
readfile('original.pdf');
?>
I'll leave the "generate a random string" part up to you. I'd suggest basing it on the checksum of the file, but that's just me.
This is what you need to do if you would like to generate unique names for your users, all you need to do is to use actual time stamp and use the filename parameter in the header, you can do like below (if you use random generation there will be a very few cases where you will get the same name twice) :
$dt = date(time());
header("Content-type: image/jpeg");
header('Content-Disposition: attachment; filename="'. $dt .'.jpg"');
The above will generate unique images names like below :
1362504465.jpg
I hope this helps.
There are dozens if not hundred ways to do that.
Append time() after file name. This way all the file names will
have a (unique)number.
Use a hashing function, like md5().
Use this code-
function generateRandomName(len) {
$out = '';
for($i=0; $i<len; $i++) {
$out.=chr(rand(65,122));
}
return $out;
}
Simply append rand function after your file name (But then the file names won't be of equal length).
Google is your friend.
This would make an 8 characters long name of letters a-z, but you could do some magic and/or use http://www.asciitable.com/
function randChar() {
return char(rand(97, 122);
// Then you could either do a random number from 97 to 122 for a-z or just make an array of all the characters you would like in the filename.
}
$filename = '';
$amountOfChars = 8;
for($i = 0; $i < $amountOfChars; $i++; ) $filename .= randChar();
Hope this helps
I have an multiple input sending files and I need guard this images with another name inside my folder called 'home';
So the pictures filing with the name home1.jpg, home2.jpg, etc
So, here is my code:
$file = $_FILES['Filedata'];
$filename_home = "";
$img_array = array($filename);
foreach($img_array as $key=>$value){
$filename_home.="home".$key.".jpg";
}
But this doesn't producing the result.
Any help, will be appreciate
Where does $filename come from? It looks like you want to use $file instead.