How can i make a table while fetch assoc - php

Question

Hello i'm a (beginning) php backend dev and i'm working on a dj panel but it doesnt work the right way i tried as many things as i could but i cant get it to work..
$active_ids = '1, 3, 4';
$query = "SELECT * FROM users WHERE id IN ({$active_ids})";
$result = $mysqli->query($query);
$query2 = "SELECT dj, count(*) AS n FROM timetable WHERE dj IN ({$active_ids}) GROUP BY dj";
$result2 = $mysqli->query($query2);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()){
echo "<tr>";
echo "<td>", $row['username'] ,"</td>";
}
if ($result2->num_rows > 0) {
while($row2 = $result2->fetch_assoc()){
echo "<td>", $row2['n'] ,"</td>";
echo "</tr>";
}
}
}
this is what it shows
ZOMBOY
Hater
ZOMBOY2 3
1
1
and this is how it needs to become but i cant find a way to do it
ZOMBOY 3
Hater 1
ZOMBOY2 1

Answer 1

You can use join instead to querying two table
$active_ids = '1, 3, 4';
$query = "SELECT u.username, count(*) AS n FROM users u, timetable tt WHERE u.id=tt.dj and u.id IN ({$active_ids}) GROUP BY tt.dj";
$result = $mysqli->query($query);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()){
echo "<tr>";
echo "<td>", $row['username'] ,"</td>";
echo "<td>", $row['n'] ,"</td>";
echo "</tr>";
}
}

Answer 2

You can do it like this, but must be look Joins
$active_ids = '1, 3, 4';
$query = "SELECT * FROM users WHERE id IN ({$active_ids})";
$result = $mysqli->query($query);
$query2 = "SELECT dj, count(*) AS n FROM timetable WHERE dj IN ({$active_ids}) GROUP BY dj";
$result2 = $mysqli->query($query2);
$columnOne = Array();
$columnTwo = Array();
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()){
$columnOne[]= $row['username'];
}
if ($result2->num_rows > 0) {
while($row2 = $result2->fetch_assoc()){
$columnTwo[] = row2['n'];
}
}
}
echo '<table>';
for($i=0;$i<count($columnOne);$i++){
echo '<tr><td>' . $columnOne[$i] . '</td><td>' . $columnTwo[$i] . '</td></tr>';
}
echo '</table>';

Answer 3

You could try something such as this (Not quite as elegant as others):
# Escape your characters
$active_ids = "'1', '3', '4'";
# Tidy up the querys to reduce the change of reserved words being used
$query = "SELECT * FROM `users` WHERE `id` IN ({$active_ids});";
$result = $mysqli->query($query);
$query2 = "SELECT `dj`, COUNT(*) AS n FROM `timetable` WHERE `dj` IN ({$active_ids}) GROUP BY `dj`";
$result2 = $mysqli->query($query2);
# Count your results
$c1 = count($result);
$c2 = count($result2);
#Set the counter to be the larger of the 2
$counter = (($c1 > $c2) ? $c1 : $c2);
if ($result->num_rows > 0 && $result2->num_rows > 0)
{
# Print the table opener
print '<table class="your_class">';
# Loop through your results
for ($i = 0; $i < $counter; $i++)
{
# Print the data needed
print '<tr><td>' . $result[$i]['username'] . '</td><td>' . $result2[$i]['n'] . '</td></tr>';
}
# End the table
print '</table>';
}