Remove from array if id exists in database? - php

Question

I am pulling data from an api and as such i have a loop that stores some ids into an array.
What i need to do is select all ids from my database and then remove any ids that have been found in the database from the initial array. so i can continue to query the api for ids that i do not have currently.
To make more sense please look below:
$matches = $database->get_results('SELECT match_id FROM `matches` WHERE `order_id`='.$order_id);
if ($matchlist->totalGames !== 0) {
foreach ($matchlist as $key) {
$gameIds[] = $key->matchId;
}
}
I need to remove the ids from $gameIds if they already are stored in the $matches.
Any ideas?
Thanks
I have tried:
$matches = $database->get_results('SELECT `match_id` FROM `matches` WHERE `order_id`='.$order_id);
if ($matchlist->totalGames !== 0) {
foreach ($matchlist as $key) {
$gameIds[] = $key->matchId;
}
$arr_matches = object2array($matches);
$new_array = array_diff($arr_matches, $gameIds);
var_dump($new_array);
}
error:
Catchable fatal error: Object of class stdClass could not be converted to string

Answer 1

Step 1: Change object to array
function object2array($object)
{
if (is_object($object)):
foreach ($object as $key => $value):
$array[$key] = $value;
endforeach;
else:
$array = $object;
endif;
return $array;
}
Step 2:
$arr_matches = object2array($matches)
$new_array = array_diff($arr_matches , $gameIds);
// Will remove all elements contained in $gameIds from $arr_matches array.