How to display content from MYSQL Join if ID is not relational - php

Question

I have an artist page that is supposed to show the albums released by a particular artist.
I am joining two tables to accomplish this. The relation is the artist_name. Both the artist table and the albums tables have different IDs.
Unfortunately, the artist page is showing ALL of the album photos in the database instead of only the ones related to the artist.
My thought process was to to use the $_GET method to grab the artist name which would be included in the URL when the user clicks the link to visit that artist's page. But obviously, this is not working.
Here's my script:
$artist_name = $_GET['artist_name'];
//Query the database to show the albums
$albums = "SELECT artist.artist_name,albums.artist_name,albums.photo,albums.album_title
FROM artist,albums
WHERE artist.artist_name=albums.artist_name
ORDER BY year_released ASC";
$q = $db->query($albums);
$q->setFetchMode(PDO::FETCH_ASSOC);
html:
<?php while ($r = $q->fetch()): ?>
<span class="margin-two album">
<img src="http://mywebsite.com/albums/<?php echo $r['photo']; ?>" alt="picture of the album <?php echo $r['album_title']; ?> by <?php echo $r['artist_name']; ?>" title="<?php echo $r['album_title']; ?>" \>
</span>
<?php endwhile; ?>
How can I output the correct albums for each artist?

Answer 1

Use below query with left join to albums table.
$artist_name = $_GET['artist_name'];
//Query the database to show the albums
$albums = "SELECT artist.artist_name,albums.artist_name,albums.photo,albums.album_title
FROM artist,albums
LEFT JOIN
albums on albums.artist_name = artist.artist_name
WHERE artist.artist_name=$artist_name
ORDER BY year_released ASC";
$q = $db->query($albums);
$q->setFetchMode(PDO::FETCH_ASSOC);
Let me know if you have any question.

Answer 2

Change your $albums string to :
$albums = "SELECT artist.artist_name, albums.photo, albums.album_title
FROM artist
LEFT JOIN albums ON (artist.artist_name=albums.artist_name)
WHERE artist.artist_name=$artist_name
ORDER BY year_released ASC";

Answer 3

Thanks to everyone for pointing me in the right direction with MYSQL LEFT JOIN. After doing a bit more research, I got the following code to work by adding USING in my script.
$artist_name = $_GET['artist_name'];
//Query the database to show the albums
$albums = "SELECT * FROM artist
LEFT JOIN albums
USING (artist_name)
WHERE artist_name='$artist_name'
ORDER BY year_released";