I have two tables Candidates & Qualifications with a joining pivot table called Results.
What I want to do is select all candidates for this centre and filter them by a value in the pivot table.
So select all candidates from centre 1 where the pivot “status” = “REGISTERED”
I have tried numerous approaches and am currently with the one below but nothing is working.
$candidates = Candidate::where('batch_centre_id','=', $id)->with(array('qualification' => function($q)
{
$q->wherePivot('status','=', 'REGISTERED');
}))->get();
Any advice would be much appreciated
In Eloquent wherePivot method can only be loaded on a relation. The way you're doing it, you're calling it on qualifications relation, therefore you're fetching all candidates and then, for each of them, you're loading qualifications that have status=REGISTERED. That's why you're getting all candidates.
You could work around it by using Eloquent's whereHas() method that let's you filter the base model you're trying to fetch by attributes of some relation. In your case the following should work:
$candidates = Candidate::where('batch_centre_id','=', $id)
->whereHas('qualifications', function($q) {
$q->wherePivot('status','=', 'REGISTERED');
})->with('qualifications')->get();
This way you'll get only candidates that have a qualification with status=REGISTERED and all their qualifications. If you want to additionally filter loaded qualifications by status, add the constraint like you did in your code:
$candidates = Candidate::where('batch_centre_id','=', $id)
->whereHas('qualifications', function($q) {
$q->wherePivot('status','=', 'REGISTERED');
})->with(array('qualifications', function($q) {
$q->wherePivot('status','=', 'REGISTERED');
})->get();
Related
In laravel 8, I am filtering blog articles by category. However when I select multiple categories in my select menu. I do get the proper request . for example: articles/category/?category_ids=3,4
But it will only output one selected filter. If I select 2 filters it just selects that next filter as if I only selected that one. (I also use Axios but the request is done proper, so its in my Controller)
Here is my code I tried:
$data['articles'] = Article::whereHas('categories', function ($query) use($category_ids){
$query->whereHas('category_id', '=', $category_ids)->where('premium',0);
;})->get();
I also tried:
$data['articles'] = Article::whereHas('categories', function ($query) use($category_ids){
$query->whereIn('category_id', [$category_ids])->where('premium',0);
;})->get();
So how do I get to query both or more category id's ?
I am using a pivot table:
Articles can have many Categories
Categories can have many Articles
I use article_category as a pivot table
When checking for relationship existence in many-to-many relations, the check is still to be done against the id in the categories table.
Try this
$category_ids = collect(explode(',', $request->category_ids))
->map(fn($i) => trim($i))
->all();
$data['articles'] => Article::whereHas('category', fn($query) =>
$query->whereIn('categories.id', $category_ids)
->where('categories.premium', 0)
)->get();
You can explode the categories and then make the query like this.
$categories = explode(',',$request->categories);
$data['articles'] = Article::whereHas('categories', function ($query) use($categories){
$query->whereIn('category_id', $categories)->where('premium',0);
})->get();
I'm trying to get all the data from the parent that only has a child. Please see my code below.
$customers = Customer::with(['items' => function($query){
return $query->where('status', 2);
}])->get();
dd($customers);
But the code above returns all the customer. By the way, I'm using laravel 4.2.
Items Table:
Customer Table:
with() is for eager loading. That basically means, along the main model, Laravel will preload the relationship(s) you specify. This is especially helpful if you have a collection of models and you want to load a relation for all of them. Because with eager loading you run only one additional DB query instead of one for every model in the collection.
has() is to filter the selecting model based on a relationship. So it acts very similarly to a normal WHERE condition. If you just use has('relation') that means you only want to get the models that have at least one related model in this relation.
e.g :
$users = Customer::has('items')->get();
// only Customer that have at least one item are contained in the collection
whereHas() works basically the same as has() but allows you to specify additional filters for the related model to check.
e.g
$users = Customer::whereHas('items', function($q){
$q->where('status', 2);
})->get();
// only customer that have item status 2
Adding group by to calculating sum
this is another example from my code :
Customer::select(['customer.name', DB::raw('sum(sale.amount_to_pay) AS total_amount'), 'customer.id'])
->where('customer.store_id', User::storeId())
->join('sale', 'sale.customer_id', '=', 'customer.id')
->groupBy('customer.id', 'customer.name')
->orderBy('total_amount', 'desc')
->take($i)
->get()
in your case :
Customer::select(['customer_id', DB::raw('sum(quantity) AS total')])
->whereHas('items', function ($q) {
$q->where('status', 2);
})
->groupBy('customer_id')
->get();
whereHas() allow you to filter data or query for the related model in your case
those customer that have items and it status is 2
afetr getting data we are perform ->groupBy('customer_id')
The GROUP BY statement is often used with aggregate functions (COUNT, MAX, MIN, SUM, AVG) to group the result-set by one or more columns.
select(['customer_id', DB::raw('sum(quantity) AS total')]) this will select customer id and calculate the sum of quantity column
You should use whereHas not with to check child existence.
$customers = Customer::whereHas('items', function($query){
return $query->where('status', 2);
})->get();
dd($customers);
I assume you already defined proper relationship between Customer and Item.
You should try this:
$customers = Customer::whereHas('items', function($query){
$query->where('status', 2);
})->get();
dd($customers);
Customer::select(['items.customer_id',DB::raw('count(items.id) AS total_qty')])
->join('items', 'items.user_id', '=', 'customer.customer_id')
->groupBy('items.customer_id')
->havingRaw('total_qty > 2')
->get();
OR
$data=DB::select("select `items`.`customer_id`, count(items.id) AS total_qty
from `customers`
inner join `items`
on `items`.`customer_id` = `customers`.`customer_id`
group by `items`.`customer_id` having total_qty >= 2");
correct table name and column name.
I have a little complicated relationship and I also want to order my results using column in the other table, let's see:
$book = Book::where('id', '=', $id)->with([
'versions.titles' => function ($query) {
//I want to paginate table "titles"
$query->groupBy('titles.title')->paginate(15);
},
'versions.titles.numbers' => function ($query) {
// but I want to order it by "numbers.order_key"
$query->orderBy('numbers.order_key', 'asc')->get();
}])
->first();
Of course, this code doesn't work properly - titles column isn't sorted by numbers.order_key. Does anybody have any idea how to get it? I don't really want to use joins because of a complication of my relationships.
Update:
My models
Book:
-id
Title:
-id
Version:
-id
-book_id
titles_version:
-title_id
-version_id
Number:
-id
-book_id
-title_id
I want to obtain one nested record to paginate titles, e.g. $book->versions->titles->paginate(15), where titles have to be ordered by numbers.order_key.
I have M:N relationship between tables handymen and categories. So, pivot table is category_handyman. How to fetch all handymen data, who have category_id=1 in pivot table? I wanted to do something like this: (but this doesnt work)
$handymen = Handyman::with('categories')
->where('category_id', 1)
->get();
You can use whereHas() method to filter on related records:
$handymen = Handyman::whereHas('categories', function($query) {
$query->whereId(1);
})->get();
I have two tables, say "users" and "users_actions", where "users_actions" has an hasMany relation with users:
users
id | name | surname | email...
actions
id | id_action | id_user | log | created_at
Model Users.php
class Users {
public function action()
{
return $this->hasMany('Action', 'user_id')->orderBy('created_at', 'desc');
}
}
Now, I want to retrieve a list of all users with their LAST action.
I saw that doing Users::with('action')->get();
can easily give me the last action by simply fetching only the first result of the relation:
foreach ($users as $user) {
echo $user->action[0]->description;
}
but I wanted to avoid this of course, and just pick ONLY THE LAST action for EACH user.
I tried using a constraint, like
Users::with(['action' => function ($query) {
$query->orderBy('created_at', 'desc')
->limit(1);
}])
->get();
but that gives me an incorrect result since Laravel executes this query:
SELECT * FROM users_actions WHERE user_id IN (1,2,3,4,5)
ORDER BY created_at
LIMIT 1
which is of course wrong. Is there any possibility to get this without executing a query for each record using Eloquent?
Am I making some obvious mistake I'm not seeing? I'm quite new to using Eloquent and sometimes relationship troubles me.
Edit:
A part from the representational purpose, I also need this feature for searching inside a relation, say for example I want to search users where LAST ACTION = 'something'
I tried using
$actions->whereHas('action', function($query) {
$query->where('id_action', 1);
});
but this gives me ALL the users which had had an action = 1, and since it's a log everyone passed that step.
Edit 2:
Thanks to #berkayk looks like I solved the first part of my problem, but still I can't search within the relation.
Actions::whereHas('latestAction', function($query) {
$query->where('id_action', 1);
});
still doesn't perform the right query, it generates something like:
select * from `users` where
(select count(*)
from `users_action`
where `users_action`.`user_id` = `users`.`id`
and `id_action` in ('1')
) >= 1
order by `created_at` desc
I need to get the record where the latest action is 1
I think the solution you are asking for is explained here http://softonsofa.com/tweaking-eloquent-relations-how-to-get-latest-related-model/
Define this relation in User model,
public function latestAction()
{
return $this->hasOne('Action')->latest();
}
And get the results with
User::with('latestAction')->get();
I created a package for this: https://github.com/staudenmeir/eloquent-eager-limit
Use the HasEagerLimit trait in both the parent and the related model.
class User extends Model {
use \Staudenmeir\EloquentEagerLimit\HasEagerLimit;
}
class Action extends Model {
use \Staudenmeir\EloquentEagerLimit\HasEagerLimit;
}
Then simply chain ->limit(1) call in your eager-load query (which seems you already do), and you will get the latest action per user.
My solution linked by #berbayk is cool if you want to easily get latest hasMany related model.
However, it couldn't solve the other part of what you're asking for, since querying this relation with where clause would result in pretty much the same what you already experienced - all rows would be returned, only latest wouldn't be latest in fact (but latest matching the where constraint).
So here you go:
the easy way - get all and filter collection:
User::has('actions')->with('latestAction')->get()->filter(function ($user) {
return $user->latestAction->id_action == 1;
});
or the hard way - do it in sql (assuming MySQL):
User::whereHas('actions', function ($q) {
// where id = (..subquery..)
$q->where('id', function ($q) {
$q->from('actions as sub')
->selectRaw('max(id)')
->whereRaw('actions.user_id = sub.user_id');
})->where('id_action', 1);
})->with('latestAction')->get();
Choose one of these solutions by comparing performance - the first will return all rows and filter possibly big collection.
The latter will run subquery (whereHas) with nested subquery (where('id', function () {..}), so both ways might be potentially slow on big table.
Let change a bit the #berkayk's code.
Define this relation in Users model,
public function latestAction()
{
return $this->hasOne('Action')->latest();
}
And
Users::with(['latestAction' => function ($query) {
$query->where('id_action', 1);
}])->get();
To load latest related data for each user you could get it using self join approach on actions table something like
select u.*, a.*
from users u
join actions a on u.id = a.user_id
left join actions a1 on a.user_id = a1.user_id
and a.created_at < a1.created_at
where a1.user_id is null
a.id_action = 1 // id_action filter on related latest record
To do it via query builder way you can write it as
DB::table('users as u')
->select('u.*', 'a.*')
->join('actions as a', 'u.id', '=', 'a.user_id')
->leftJoin('actions as a1', function ($join) {
$join->on('a.user_id', '=', 'a1.user_id')
->whereRaw(DB::raw('a.created_at < a1.created_at'));
})
->whereNull('a1.user_id')
->where('aid_action', 1) // id_action filter on related latest record
->get();
To eager to the latest relation for a user you can define it as a hasOne relation on your model like
namespace App\Models;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Support\Facades\DB;
class User extends Model
{
public function latest_action()
{
return $this->hasOne(\App\Models\Action::class, 'user_id')
->leftJoin('actions as a1', function ($join) {
$join->on('actions.user_id', '=', 'a1.user_id')
->whereRaw(DB::raw('actions.created_at < a1.created_at'));
})->whereNull('a1.user_id')
->select('actions.*');
}
}
There is no need for dependent sub query just apply regular filter inside whereHas
User::with('latest_action')
->whereHas('latest_action', function ($query) {
$query->where('id_action', 1);
})
->get();
Migrating Raw SQL to Eloquent
Laravel Eloquent select all rows with max created_at
Laravel - Get the last entry of each UID type
Laravel Eloquent group by most recent record
Laravel Uses take() function not Limit
Try the below Code i hope it's working fine for u
Users::with(['action' => function ($query) {
$query->orderBy('created_at', 'desc')->take(1);
}])->get();
or simply add a take method to your relationship like below
return $this->hasMany('Action', 'user_id')->orderBy('created_at', 'desc')->take(1);