I've a problem with php and foreach...
The first query result like this:
while ($row = $s->fetch())
{
$registration[] = array(
'id_registration' => $row['id_registration'],
'discipline' => $row['discipline'],
'speciality' => $row['speciality'],
'category' => $row['category'],
'subcat' => $row['subcat']
);
}
excuse me, I was not very precise...
I have 2 table
- the first has a primary key (id_registration) that identifies the registration
- in the second table there are firstrname and lastname of the athletes which refer to the first table by id_registration.
how can I get all the registrations and the athletes of every registration and print all with one o more foreach loop?
I hope I was clear.
$iscrizioni = array();
while ($row = $s->fetch())
{
$iscrizioni['id_gara'] = $row['id_gara'];
$iscrizioni['disc'] = $row['disc'];
$iscrizioni['spec'] = $row['spec'];
$iscrizioni['cat'] = $row['cat'];
$iscrizioni['subcat'] = $row['subcat'];
}
pre($iscrizioni);
Related
I have a sql table with some category, i get them in a array.. all fine but when i try to get data from another table foreach category, always return me for first category selected.
This is my code:
$gameguidecategoryes = array();
$gameguides = array();
$dbselectgameguidecategoryes = new DB_MSSQL;
$dbselectgameguidecategoryes->Database=$newweb_db;
$dbselectgameguidecategoryes->query("Select GameGuideCatNr,GameGuideCatName_$languageid as GameGuideCatName,GameGuideCatImage from GameGuide_Category where GameGuideCatVisible = 1 order by GameGuideCatOrder asc");
for($i=0;$i < $dbselectgameguidecategoryes->num_rows();++$i) {
if ($dbselectgameguidecategoryes->next_record()){
$GameGuideCatNr = $dbselectgameguidecategoryes->f('GameGuideCatNr');
$GameGuideCatName = $dbselectgameguidecategoryes->f('GameGuideCatName');
$GameGuideCatImage = $dbselectgameguidecategoryes->f('GameGuideCatImage');
}
$gameguidecategoryes_temp = array(
'ggcname' => $GameGuideCatName,
'ggcimg' => $GameGuideCatImage,
);
$gameguidecategoryes[$i] = $gameguidecategoryes_temp;
$dbselectgameguide = new DB_MSSQL;
$dbselectgameguide->Database=$newweb_db;
$dbselectgameguide->query("Select GameGuideID,GameGuideName_$languageid as GameGuideName from GameGuide_Content where GameGuideCat = $GameGuideCatNr and GameGuideVisible = 1 order by GameGuideOrder asc");
for($ii=0;$ii < $dbselectgameguide->num_rows();++$ii) {
if ($dbselectgameguide->next_record()){
$GameGuideID = $dbselectgameguide->f('GameGuideID');
$GameGuideName = $dbselectgameguide->f('GameGuideName');
}
$gameguides_temp = array(
'ggid' => $GameGuideID,
'ggn' => $GameGuideName,
);
$gameguides[$ii] = $gameguides_temp;
}
}
Why $gameguides return data only from first category?
Thank you
Your second loop keeps getting trashed by the first loop. e.g. Consider what happens:
You fetch your categories, and (let's pretend) there's 4 of them.
You store some information in $gameguidecategoryes[0]
You run the second query, get some content for category #0, say, 3 records
That gets stored in $gameguides[0], [1], [2]
Your outer loop ticks again, and you start on categoryes[1]
The inner loop ticks again, you get 4 records, and now you're storing them into the SAME again: $gameguides[0], [1], [2], [3], etc...
You've now trashed the data you fetched in the first loop, and will
do so for every category you fetch.
This code is very inefficient. You should learn how to use JOINs, and fetch into a single structure, e.g.
SELECT category.id, category.name, ...., content.id, content.name
FROM categories
LEFT JOIN content ON categories.id = content.category_id
ORDER BY ...
and then something like
$data = array();
while($row = fetch row from db) {
if (!isset($data[$row['category.id']]) {
$data[$row['category.id']] = array(
'name' => $row['category.name'],
'content' => array()
);
}
$data[$row['category.id']]['content'][] = array(
... save content data here
);
};
Better work on clean code
$gameguidecategoryes = $gameguides = $gameguidescategoryids = array();
$dbselectgameguidecategoryes = new DB_MSSQL;
$dbselectgameguidecategoryes->Database=$newweb_db;
$dbselectgameguidecategoryes->query("Select GameGuideCatNr,GameGuideCatName_$languageid as GameGuideCatName,GameGuideCatImage from GameGuide_Category where GameGuideCatVisible = 1 order by GameGuideCatOrder asc");
while ($dbselectgameguidecategoryes->next_record()) {
$gameguidescategoryids[] = $dbselectgameguidecategoryes->f('GameGuideCatNr');
$gameguidecategoryes[] = array(
'ggcname' => $dbselectgameguidecategoryes->f('GameGuideCatName'),
'ggcimg' => $dbselectgameguidecategoryes->f('GameGuideCatImage'),
);
}
if (count($gameguidescategoryids)) {
$dbselectgameguide = new DB_MSSQL;
$dbselectgameguide->Database=$newweb_db;
$dbselectgameguide->query("Select GameGuideID,GameGuideName_$languageid as GameGuideName from GameGuide_Content where GameGuideCat IN (".implode(',', $gameguidescategoryids).") and GameGuideVisible = 1 order by GameGuideOrder asc");
while ($dbselectgameguide->next_record()){
$gameguides[] = array(
'ggid' => $dbselectgameguide->f('GameGuideID'),
'ggn' => $dbselectgameguide->f('GameGuideName'),
);
}
}
I found on the PHP documentation the function "array_multisort" that is meant to sort an array "of columns". They provide one example where the user has an array of rows and then the user has to transform this array of rows into an array of columns. In my case the array is already set by columns, such as:
tablearray
{
['Employee_ID'] = {0 => row1, 1 => row2, 2 => row3, 3 => row4}
['First_Name'] = {0 => row1, 1 => row2, 2 => row3, 3 => row4}
['LastName'] = {0 => row1, 1 => row2, 2 => row3, 3 =>row4}
}
I want to sort by Employee_ID and I need all the other columns to follow the same order. I tried:
array_multisort($tablearray['Employee_ID'], SORT_ASC);
But it only sorts the first column (which becomes a mess). The array has more than 10 columns and it changes the column names depending on the search (the columns names are its keys).
On PHP's documentation for this function, the example provided shows that the after transforming the rows array into a columns array, we should use the original array as a third parameter to match the keys - I don't have the "original" array to do the match since I didn't transform anything.
Thank you.
Desired output, as suggested by one user:
Original:
array
{
['Employee_ID'] = (1002, 4508, 0002, 1112)
['Business_Unit'] = ('UER', 'ABC', 'XYZ', 'EER')
['LastName'] = ('Smith', 'Vicente', 'Simpson', 'Thompson')
}
Sorted by Employee ID:
array
{
['Employee_ID'] = (0002, 1002, 1112, 4508)
['Business_Unit'] = ('XYZ', 'UER', 'EER', 'ABC')
['LastName'] = ('Simpson','Smith', 'Thompson', 'Vicente')
}
--
My original array is a database query output:
Array
(
[0] => Array
(
[Employee_ID] => 0000
[Supervisor_ID] => 00000
[Location_Descr] => somewhere
[Start_Date] => 06/03/2002
[Service_Date] => 06/03/2002
[Rehire_Date] => 00/00/00
[Business_Unit] => YYYY
[Job_Title] => Manager
[Email] => email#example.com
[Dept_Desc] => bla bla bla
[Employee_Name_LF] => Last, First
[Supervisor_Name_LF] => Last, First
[Term_Date] => 00/00/00
[Preferred_Name] => Someone
[Source] => Sheet2
)
)
There a several more rows.
The main purpose is to show the results as an HTML table and to generate a CSV file. I already made those functions using the modified structure (the first that I posted). I thought it would be easier to deal with that structure... Indeed it was, but not for sorting unfortunately.
The array_multisort documentation (http://php.net/manual/en/function.array-multisort.php) suggests separating each column as an individual array.. However, as you can see I have several columns (and the user can select more or less to be shown before performing the query.. So I can't just list all of them on the statement).
I a willing to change everything just to make the code better to be worked with.
Ugly - would be a lot easier if you formatted the input tables.
$arr = array(
'Employee_ID' => array('1002', '4508', '0002', '1112'),
'Business_Unit' => array('UER', 'ABC', 'XYZ', 'EER'),
'LastName' => array('Smith', 'Vicente', 'Simpson', 'Thompson')
);
$employees = array();
foreach (range(0, sizeof($arr[current(array_keys($arr))]) - 1) as $k) {
$emp = array();
foreach ($arr as $col => $vals) {
$emp[$col] = $arr[$col][$k];
}
$employees[] = $emp;
}
$sort = array();
foreach ($employees as $k => $v) {
$sort[$k] = $v['Employee_ID'];
}
array_multisort($sort, SORT_ASC, $employees);
print_r($employees);
And to put back in the original format:
$arr_sorted = array();
foreach (array_keys($arr) as $col) {
$arr_sorted[$col] = array();
foreach ($employees as $emp) {
$arr_sorted[$col][] = $emp[$col];
}
}
print_r($arr_sorted);
Thank you for posting the extra details in your question, as they did help in understanding the intent of your question.Now, you didn't tell us how that table should look; If you want the employees one per row, or one per column. Which is kind of crucial to know. Normally one would have one employee per line, especially if this is to be exported to CVS. However, I have a suspicion that it's the latter you want. Otherwise you've gone about this in a very overly complicated manner.Point in case: Normal one-per-row layout:
<?php
$db = new PDO();
// Defining the fields we need here, to avoid having too long a string for the query.
$fields = "e.employee_id, e.first_name, e.lastname, u.business_unit, s.email";
// Do the sorting in the database itself. Not only is this faster, but it
// is also a lot easier to sort it exactly as you'd like.
// Note that I don't use prepared statements here, as there is no user-input.
$query = <<<outSQL
SELECT {$Fields} FROM `unit` AS u
INNER JOIN `employee` AS e ON e.employee_id = u.unit_id
INNER JOIN `employee` AS s ON s.employee_id = u.supervisor_id
ORDER BY e.`employee_id`
outSQL;
$data = $db->query($query);
// Creating a printf() template for the output, to make the code easier to maintain.
$rowTemplate = <<<outHTML
<tr>
<td>%1\$d</td>
<td>%2\$s</td>
<td>%3\$s</td>
</tr>
outHTML;
// Generate the table template, using placeholders for where the data will be added..
$tableTemplate = <<<outHTML
<table>
<thead>
<tr>
<th>ID</th>
<th>First name</th>
<th>Last name</th>
</tr>
</thead>
<tbody>
%s
</tbody>
</table>
outHTML;
// Regular table output, one employee per line.
$temp = '';
foreach ($data as $e) {
// hs() is a shortcut function to htmlspecialchars (), to prevent against XSS.
$temp .= sprintf($rowTemplate, $e['employee_id'], hs($e['first_name']), hs($e['lastname']));
}
// Add the rows to the table, so that you can echo the completed product wherever you need.
$employeeTable = sprintf($tableTemplate, $temp);
If you want to do it one per column, it becomes a bit more intricate. Though, still a bit easier than your first attempt. :)
Namely, something like this:
<?php
$db = new PDO();
// Defining the fields we need here, to avoid having too long a string for the query.
$fields = "employee_id, first_name, lastname";
// Do the sorting in the database itself. Not only is this faster, but it
// is also a lot easier to sort it exactly as you'd like.
// Note that I don't use prepared statements here, as there is no user-input.
$data = $db->query("SELECT {$Fields} FROM `employees` ORDER BY `employee_id`");
// We need to know how many columns we'll have. One per employee.
$columns = count ($data);
// Rows have a header in front of each line, and one td tag for each employee.
$rowTemplate = "\t\t<th>%s</th>\n".str_repeat("\t\t\t<td>%s</td>\n", $columns);
// Generate the table template, using placeholders for where the data will be added..
$tableTemplate = <<<outHTML
<table>
<tbody>
%s
</tbody>
</table>
outHTML;
// Reformat the array to give us the data per-column.
$temp = array ();
foreach ($data as $field => $e) {
// Since we've already sorted the data in the database we don't need to do any further sorting here.
// Also note that I'm doing the escaping here, seeing as this array will only be used for output.
$temp['Employee ID'][] = intval($e['employee_id']);
$temp['First name'][] = hs($e['first_name']);
$temp['Last name'][] = hs($e['lastname']);
}
// Now we do the same as in the above example.
$rows = '';
foreach ($temp as $label => $l) {
// We have the label as the first template variable to be added, so put it as the first element.
array_unshift($l, $label);
// Add the current row of items to the output, using the previously established template.
$rows = vprintf($rowTemplate, $l);
}
// Add the rows to the table, so that you can echo the completed product wherever you need.
$employeeTable = sprintf($tableTemplate, $temp);
PS: Haven't tested the code, but it should work.
I ran into his problem and after much angst found a really nice solution in the notes on the php manual page - I now have the following function which i use whenever I need to solve this type of problem.
function fnArrayOrderby(){
//function to sort a database type array of rows by the values in one or more column
//source http://php.net/manual/en/function.array-multisort.php - user notes
//example of use -> $sorted = fnArrayOrderby($data, 'volume', SORT_DESC, 'edition', SORT_ASC);
$args = func_get_args(); //Gets an array of the function's argument list (which can vary in length)
//echo "sorting ".$args[0]."<br>";
if (!isset($args[0])) { return;}
$data = array_shift($args); //Shift an element off the beginning of array
foreach ($args as $n => $field) {
if (is_string($field)) {
$tmp = array();
foreach ($data as $key => $row)
$tmp[$key] = $row[$field];
$args[$n] = $tmp;
}
}
$args[] = &$data;
call_user_func_array('array_multisort', $args);
return array_pop($args);
}
I'm creating an API for my mobile application. I'm developing this with PHP MYSQL and the Slim framework (which is largely irrelevant for this problem).
I'm trying to pull multiple "venues" from my mysql database, and retrieve multiple "venue_images" for each "venue". The database:
venues venue_images
------ ------------
id PK image_venue_id FK (to venues)
venue_name image_path
active
I then need to output the data in this format:
{
"completed_in":0.01068,
"returned":10,
"results":[
{
"venue_id":"1",
"venue_name":"NameHere",
"images": [
{
"image_path":"http://www.pathhere.com"
},
{
"image_path":"http://www.pathhere2.com"
}
]
}
]
}
So basically, the images are iterated multiple times for each venue.
My current code is:
$sql = "
SELECT
venues.id, venues.venue_name, venues.active,
venue_images.image_venue_id, venue_images.image_path
FROM
venues
LEFT JOIN
venue_images ON venue_images.image_venue_id = venues.id
WHERE
venues.active = 1
LIMIT 0, 10
";
$data = ORM::for_table('venues')->raw_query($sql, array())->find_many();
if($data) {
foreach ($data as $post) {
$results[] = array (
'venue_id' => $post->id,
'venue_name' => $post->venue_name,
'images' => $post->image_path
);
}
//Build full json
$time = round((microTimer() - START_TIME), 5);
$result = array(
'completed_in' => $time,
'returned' => count($results),
'results' => $results
);
//Print JSON
echo indent(stripslashes(json_encode($result)));
} else {
echo "Nothing found";
}
My current code works, however it produces this:
{
"completed_in":0.01068,
"returned":10,
"results":[
{
"venue_id":"1",
"venue_name":"The Bunker",
"images":"https://s3.amazonaws.com/barholla/venues/1352383950-qPXNShGR6ikoafj_n.jpg"
},
{
"venue_id":"1",
"venue_name":"The Bunker",
"images":"https://s3.amazonaws.com/barholla/venues/1352384236-RUfkGAWsCfAVdPm_n.jpg"
}
]
}
There's two images for "The Bunker". Instead of storing the images within the venue array, it's creating a duplicate row of "The Bunker", with the second image. Like I said earlier, I need to have multiple images iterating within each venue. Any help would be much appreciated! Thanks!
You want to use GROUP_CONCAT
Something like this (not 100% accurate probably :) )
$sql = "
SELECT
v.id, v.venue_name, v.active,
GROUP_CONCAT(i.image_path) as venue_image_string
FROM
venues v
LEFT JOIN
venue_images i ON i.image_venue_id = v.id
WHERE
v.active = 1
GROUP BY i.image_venue_id
LIMIT 0, 10
";
You may have to fiddle a little but should put you on the right track (note: provides venue_image_string as CSV)
Why can't you use multiple queries instead of..? Its faster and simple..!
$sql = "SELECT venues.id, venues.venue_name, venues.active FROM venues WHERE venues.active = 1 LIMIT 0, 10";
$data = ORM::for_table('venues')->raw_query($sql, array())->find_many();
if($data) {
foreach ($data as $post) {
$results[] = array ();
$sql = "SELECT image_path FROM venue_images WHERE image_venue_id = $post->id";
$images = ORM::for_table('venue_images')->raw_query($sql, array())->find_many();
$results[] = array (
'venue_id' => $post->id,
'venue_name' => $post->venue_name,
'images' => $images);
}
//Build full json
$time = round((microTimer() - START_TIME), 5);
$result = array(
'completed_in' => $time,
'returned' => count($results),
'results' => $results
);
//Print JSON
echo indent(stripslashes(json_encode($result)));
} else {
echo "Nothing found";
}
I have a database that stores accounts and subscriptions. An account can contain accounts and subscriptions and have more than three parent levels.
A row from the database query result looks something like this:
$array = (0 => array("level" => "2", "accountno" => "123124234", "accountname" => "Hansel", "parentaccountno" => "000213123", "subscription" => "5423213213", "username" => "Gretchen");
(Level 1 means that it is top level and it will have PARENTACCOUNTNO = null).
From this I am trying to create a multidimensional array which looks something like this:
accounts:
000213123
accounts:
123124234
name: Hansel
subscriptions:
5423213213
username: Gretchen
This is the code I have so far, which works really well on the first two levels. When there are are three levels or more things become more complicated, since each account only knows about its own parent:
$hierarchy = array();
foreach ($decode as $row) {
$accountno = $row["ACCOUNTNO"];
$msisdn = $row["MSISDN"];
if ($row["PARENTACCOUNTNO"] == null)
$base_array_key = $hierarchy["accounts"];
$base_array_key[$accountno] = array("name" => $row["ACCOUNTNAME"], "accounts" => array(), "subscriptions" => array());
$hierarchy["accounts"][$accountno]["accounts"]["321323123213"] = "blaha";
if ($row["MSISDN"] != null)
$hierarchy["accounts"][$accountno]["subscriptions"][$msisdn] = array("enduser" => $row["ENDUSER"]);
}
The solution I have in mind right now is to pass the base key from each iteration to the next iteration, and then if for example the previous level was two levels above this one just use some sort of string replace to remove the last two parts of the key.
Any better ideas? I am quite sure this is a shitty way of doing what I am trying to accomplish.
Do all your results look like that ? So then, where's are the parent accounts ? Or am i missing something ? I would simple rewrite the query to get a more "linear" result, like:
parentaccountno | accountno | accountname | bla
-----------------------------------------------
000213123 | 123124234 | Hansel | abc
When every result row looks like this, you can simple create your final array like that:
foreach ($decode as $row) {
$my_array = [ $row["parentaccountno"] ][ $row["accountno"] ]["accountname"] = $row["accountname"];
$my_array = [ $row["parentaccountno"] ][ $row["accountno"] ]["bla"] = $row["bla"];
}
Create a temporary associative array:
$all_records = array();
Populate it with the results you find in the database:
while($result = get_results_from_db()) {
$accountno = $result[accountno];
$all_records[$accountno] = $result;
}
Now you have an array indexed by account numbers so it's easy to find any record if you know it's account number. So you iterate through the array to associate children to parents:
$top_level_records = array();
foreach($all_records AS $record) {
$parentaccountno = $record[parentaccountno];
if(!empty($parentaccountno)) {
$parent = &$all_records[$record[parentaccountno]];
if(empty($parent['accounts']))
$parent['accounts'] = array()
$parent['accounts'][] = $record;
}
else {
$top_level_records[] = $record;
}
}
I appreciate the answers, but I think the problem is my database query which should contain records of all the parents of an account and not just the parent, using something like SYS_CONNECT_BY_PATH in Oracle SQL.
update
I have made this table: I have 2 array's UGentArray and InternshipsArray. How can I set these in my table? instead of "Row column 1 data" and "Row column 2 data". My question is: I want the values from UgentArray and InternshipArray as 2 columns under Each title UGentID and Internships
enter code here// Make table and display on screen.
$tbl_header = array();
$tbl_header[] = array("data" => "UGentID");
$tbl_header[] = array("data" => "Internships");
$tbl_row = array();
foreach($studentUGentID as $key => $value) {
for($i = 0; $i<count($value); $i++) {
$tbl_row[] = $value[$i]['value'];
}
}
$tbl_row[] = "Row column 2 data";
$tbl_rows = array();
$tbl_rows[] = $tbl_row;
$html = theme_table($tbl_header,$tbl_rows);
return $html;![enter image description here][1]
Without having an example of the data you are starting with it is difficult to give you exact code to solve your problem.
In general the best way to built tables in Drupal is like this:
$table_headers = array(
t('UGentID'), // this is the header for the first column
t('Internships'), // this is the header for the second column
);
$table_rows = array()
foreach ($studentUGentID as $key => $value) {
$table_rows[] = array(
'column 1 data', // add all the data for the row one column
'column 2 data', // at a time
);
}
$html = theme('table', $table_headers, $table_rows);
As I said without knowing what is in $studentUGentID and $internships I cannot help further.
With sample data I could help you more.