PHP Get most repeated value in Array - php

Question

I have an array within an array like this:
Array
(
[0] => Array
(
[name] => B
[id] => 924572
)
[1] => Array
(
[name] => A
[id] => 120689
)
[2] => Array
(
[name] => A
[id] => 120689
)
[3] => Array
(
[name] => C
[id] => 919644
)
[4] => Array
(
[name] => A
[id] => 120689
)
[5] => Array
(
[name] => B
[id] => 924572
)
)
How can I get the most repeated value from object named name and id?
I've already tried the code below but I'm getting an error: Warning: array_count_values(): Can only count STRING and INTEGER values!
$count = array_count_values($info);
arsort($count);
$popular = array_keys($count);
echo $popular[0];
Any fix regarding to this problem?

Answer 1

"Serializing way" for searching most repeated couples (name,id):
$out = array();
foreach($arr as $el){
$key = serialize($el);
if (!isset($out[$key]))
$out[$key]=1;
else
$out[$key]++;
}
arsort($out);
foreach($out as $el=>$count){
$item = unserialize($el);
echo "Name = ".$item['name'].' ID = '.$item['id'].' Count = '.$count.'<br/>';
}
Output:
Name = A ID = 120689 Count = 3
Name = B ID = 924572 Count = 2
Name = C ID = 919644 Count = 1
update Without loop
.....
arsort($out);
$most = unserialize(key($out));
$most_count = array_shift($out);
echo $most['name'];
echo $most['id'];
echo $most_count;
Output:
A
120689
3

Answer 2

A more linear solution.
$arr = Array
(
Array
(
"name" => "B",
"id" => 924572
),
Array
(
"name" => "A",
"id" => 120689
),
Array
(
"name" => "A" ,
"id" => 120689
),
Array
(
"name" => "C",
"id" => 919644
),
Array
(
"name" => "A",
"id" => 120689
),
Array
(
"name" => "B",
"id" => 924572
));
$countArr = Array();
for($i = 0; $i < count($arr); $i++)
{
$tmpArr = $arr[$i];
if(array_key_exists($tmpArr["name"],$countArr))
$countArr[$tmpArr["name"]]++;
else
$countArr[$tmpArr["name"]] = 0;
}
arsort($countArr);
var_dump($countArr);

Answer 3

Maybe you can work with this solution:
<?php
$info = array(
array(
"name" => "B",
"id" => 924572
),
array(
"name" => "A",
"id" => 120689
),
array(
"name" => "A",
"id" => 120689
),
array(
"name" => "C",
"id" => 919644
),
array(
"name" => "A",
"id" => 120689
),
array(
"name" => "B",
"id" => 924572
),
);
$result = array();
foreach ($info as $infoKey => $infoValue) {
foreach ($infoValue as $itemKey => $itemValue) {
if ($itemKey != "name") {
continue;
}
if (array_key_exists($itemValue, $result)){
$result[$itemValue]++;
continue;
}
$result[$itemValue] = 1;
}
}
arsort($result);
var_dump($result);
Will result in:
array (size=3)
'A' => int 3
'B' => int 2
'C' => int 1

Answer 4

Based on finding the mode and mapping in PHP. Would this work?
$name_array = array_map(function($x) {return $x["name"];}, $info);
$count = array_count_values($name_array);
$mode = array_keys($count, max($count));
To return an array of "name", "id" pairs use:
$return_value = array_filter($info, function($x) use ($mode) { return (in_array($x["name"], $mode));});

Answer 5

Makes use of array_column (requires PHP 5.5 or shim).
$count_values = array_count_values(array_column($array, 'name'));
$most_frequent_name = array_search(max($count_values), $count_values);
Then if you want all arrays with this name:
$items = array_filter($array, function ($v) use ($most_frequent_name) {
return $v['name'] == $most_frequent_name;
});
If several names may have the same top frequency:
$count_values = array_count_values(array_column($array, 'name'));
$most_frequent_names = array_keys($count_values, max($count_values));
$items = array_filter($array, function ($v) use ($most_frequent_names) {
return in_array($v['name'], $most_frequent_names);
});

Answer 6

Try following code. It will give you count of occurrences of all elements
function array_icount_values($arr,$lower=true) {
$arr2=array();
if(!is_array($arr['0'])){$arr=array($arr);}
foreach($arr as $k=> $v){
foreach($v as $v2){
if($lower==true) {$v2=strtolower($v2);}
if(!isset($arr2[$v2])){
$arr2[$v2]=1;
}else{
$arr2[$v2]++;
}
}
}
return $arr2;
}
$arr = array_icount_values($array);
echo "<pre>";
print_r($arr);