How to pass the selected value in dropdown (HTML) to PHP - php

Question

I am building a select option dynamically. I am selecting from the select option, one value. (values for list come from php
How can I pass that selected value to PHP?
<select id ="s1" name="swimopt" class="so">
<?php echo $options; ?>
</select>'
THe $options are coming from a MySQL and populating the dropdown
When I select a value, and try
echo $_POST['swimopt'];
does not show selected value
Please help
<form id="swimdata" method="POST" action="save.php">
<input type="radio" style="font-size: 16px;font-weight: bolder" name="gender" class ="gender" value="boys">BOYS
<input type="radio" style="font-size: 16px;font-weight: bolder" name="gender" class ="gender" value="girls">GIRLS
<table id="meetTable" style="width:auto">
<tr>
<th>EVENT:</th>
<th>NAME:</th>
<th>LANE:</th>
<th>TIME:</th>
<th>PLACE:</th>
<th>SCORE 1:</th>
<th>SCORE 2:</th>
<th>PLACE:</th>
<th>TIME:</th>
<th>LANE:</th>
<th>NAME:</th>
</tr>
</table>
<input type="submit" name="formSubmit" value="Submit" />
<input type="hidden" name="action1" value="addSwimmer" id="action1">
</form>
This is my PHP getting the $options from mySQL
if ($result->num_rows > 0) {
$options= '';
// output data of each row
while($row = $result->fetch_assoc()) {
$options .= "<tr><td>" . $row["swimmer_id"]. "</td><td>" . $row["first_name"]. " " . $row["last_name"]. " </td><td> " . $row["school_name"]. "</td></tr>";
}
} else {
echo "0 results";
}
echo $options;
$conn->close();
ScreenShots:
Options echoed into select box:
<select id ="s1" name="swimopt" class="so">
<?php echo $options; ?>
</select>'
PHP file code
$sql = "select first_name, last_name from swimming where gender='m'";
$results = mysqli_query($link,$sql);
if ($results->num_rows > 0) {
$options = '';
// output data of each row
while($row = $results->fetch_assoc()) {
$fname=$row["first_name"];
$lname=$row["last_name"];
$options .= "<option value= >" . $row["first_name"] . " " . $row["last_name"]."</option>";
}
} else {
echo "0 results";
}
echo $options;
$link->close();
?>

Answer 1

I think I see what your problem is. You're not setting a select option.
Try this:
<?php
$options = 'John';
?>
<form id="swimdata" method="POST" action="save.php">
<input type="radio" style="font-size: 16px;font-weight: bolder" name="gender" class ="gender" value="boys">BOYS
<input type="radio" style="font-size: 16px;font-weight: bolder" name="gender" class ="gender" value="girls">GIRLS
<table id="meetTable" style="width:auto">
<tr>
<th>EVENT:</th>
<th>NAME:</th>
<th>LANE:</th>
<th>TIME:</th>
<th>PLACE:</th>
<th>SCORE 1:</th>
<th>SCORE 2:</th>
<th>PLACE:</th>
<th>TIME:</th>
<th>LANE:</th>
<th>NAME:</th>
</tr>
</table>
<select id ="s1" name="swimopt" class="so" value="">
<?php
for($i=0;$i<10;$i++){
echo '<option value="user '.$i.'" >user '.$i.'</option>';
}
?>
</select>
<input type="submit" name="formSubmit" value="Submit" />
<input type="hidden" name="action1" value="addSwimmer" id="action1">
</form>

Answer 2

The select option must be wrapped with html tag <option> with a value attribute, which will be posted if it is selected.
According to your given code you are not generating options for a select. So try something like this:
if ($result->num_rows > 0) {
$options= '';
// output data of each row
while($row = $result->fetch_assoc()) {
$options .= "<option value=\"". $row["swimmer_id"] ."\">" . $row["first_name"]. " " . $row["last_name"]. " - " . $row["school_name"]. "</option>";
}
} else {
echo "0 results";
}
echo $options;
$conn->close();
Now if you $_POST it you will get the swimmer id