Increment Operator in addition statement [closed] - php

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Can anyone explain in depth why this outputs 9
here is my code in PHP:
$x = 4;
$x = $x+++$x++;
echo $x;

Execution goes like this:
$x = $x++ + $x++; ($x = 4)
$x = 4 + $x++; ($x = 5)
$x = 4 + 5; ($x = 6)
$x = 9;
For a more detailed answer of a more complex example in Java, see this answer: Incrementor logic

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PHP: Is there a difference between use of ++ or +=1 [closed]

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When using increment on variables in Javascript, lint says that x += 1 is preferred over x ++.
But what about in PHP?
Is there any difference between the += and ++ or does it just not really matter?
Well whatever you might say about conventions, try running the following...
$i = 1; $s = 's';
$i++; $s++;
echo $i.'<br>'.$s.'<br>';
$i = 1; $s = 's';
$i += 1; $s += 1;
echo $i.'<br>'.$s.'<br>';
the output is somewhat unexpected...
2
t
2
1
so I would say it could matter very much which is chosen!
x += 1 is rather equivalent to ++x.
All those expressions (x += 1, x++ and ++x) increment the value of num by one, but the value of x++ is the value x had before it got incremented.

PHP check if value is one of other numbers in loop [closed]

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If i have a loop for example
for ($a=1; $a<6; $a++)
Is it possible to say for the first loop if another variable like $b is the same as one of the other numbers that will come like 2, 3, 4 or 5.
And what if i have a word split, so every letter is a variable like this:
$letter1 = str_split($word)[0];
$letter2 = str_split($word)[1];
$letter3 = str_split($word)[2];
$letter4 = str_split($word)[3];
$letter5 = str_split($word)[4];
How can i check if $a is at 1 in the loop,if it is not letter1 but letter2, 3, 4 or 5?
sure. Just check it against the counter:
for ($a=1; $a<6; $a++){
if ($a===$b){
echo ("b is caught!");
break;
}
}

how to use biasedNumberBetween faker? [closed]

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I am trying to get a number between 1 to 6 with more chances to be close to 1.
i have tried this:
<li>{{Faker\Factory::create()->biasedNumberBetween($min = 10, $max = 20, $function = 'unbiased')}}</li>
What i am trying to do is to generate a number from 1 to 6 rand(1,6); but make the numbers be closer to one as the lower numbers will have more weight than the others.
Something like this ?
<?php
function weightedRand($min, $max, $weightedMax) {
$arr = array();
for($i = 0; $i < 10; $i++) {
$arr[] = rand($min, $weightedMax);
}
$arr[] = rand($min, $max);
return $arr[rand(0,10)];
}
echo weightedRand(1,6, 3);
?>
numbers below 4 will now be more likely than numbers above :)

php extract numbers and variables in math function [closed]

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I have a math function, for example:
string = "3x+6.5y-23z"
I need to extract the function and get x, y, z; give value x = 6, y = 7, z = 8; and solve.
you can do it like this
<?php
$x = 6;
$y = 7;
$z = 8;
echo $string = 3*$x+6.5*$y-23*$z;
?>

PHP:How To Initialize Variable? [closed]

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I have one question to you, and I hope you will help me. I want to write calculator but i don't have chance tu change operations , I can only use addition operation. I don't know what happened. can anyone help me?
look at it, what happened?
<?php
$x = isset($_POST['field']);
if($x == 1){
echo $x + 5;
}
elseif($x == 2){
echo $x - 5;
}
?>
You code is wrong as this line will evaluate only as 0 (false) or 1 (true) if condition is met:
$x = isset($_POST['field']);
You need to do it that way:
$x = isset($_POST['field']) ? $_POST['field'] : 0;
(where 0 is default value, $x is assigned to in case there's no $_POST['field]` set.
$x = isset($_POST['field']) ? (int)$_POST['field'] : 0;
You want the value, not the boolean if it's set or not.

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