How to get value FROM Ajax in index.php - php

I would like to get the value sent from php via AJAX in php. But i can not get value. Where is my mistake?
It is my functions.js
$(document).ready(function(){
$(".yeni_problem").click(function(){
var uid = 1;
$.ajax({
url: 'admin.php',
type: "post",
data: {'uid': uid},
success: function(data){
// $("#cvb").text(data);
},
statusCode: {
404: function(){
alert("admin.php not found");
}
}
});
});
});
and it is my php page that, i control sending value in here. The Codes is large but i write small form. Which that when i run the small codes on other folders as other site it does't work.
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>HELPDESK</title>
<link rel="stylesheet" href="css/bootstrap.min.css">
<link rel="stylesheet" href="css/css.css">
<link rel="stylesheet" href="css/default.css">
<link rel="stylesheet" href="css/animate.css">
<link rel="stylesheet" href="css/icon.css">
</head>
<body>
<button class="yeni_problem">Yeni Problem</button>
<?php
if(isset($_POST['uid'])){
echo "Value:".$_POST['uid'];
}else{
echo "<hr>Value not found<br/>";
}
var_dump($_POST);
?>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript" src="js.js"></script>
<script type="text/javascript" src="functions.js"></script>
<script type="text/javascript" src="bootstrap.min.js"></script>
<?php
echo "</body>
</html>";
?>
When i click to ".yeni_problem" class i can not get value.

1st- check you include Jquery
2nd- Be sure admin.php page in the same directory with file you called functions.js in if not check its path
3rd- you pass uid not data so in php use
<?php
if(isset($_POST['uid'])){
echo "Value:".$_POST['uid'];
}else{
echo "Value not found";
}
?>
4th: and if you dynamically generate the element with class="yeni_problem" .. so use
$('body').on('click',".yeni_problem", function(){
instead of
$(".yeni_problem").click(function(){
5th: if yeni_problem is a submit button or anchor so you need to use e.preventDefault(); to prevent page from reloading
$(".yeni_problem").click(function(e){
e.preventDefault();
// rest of code here
6th: if yeni_problem is a form use .submit()
$(".yeni_problem").submit(function(e){
e.preventDefault();
// rest of code here

Pay attention to your code: in the JS snippet, the parameter passed to the server is "uid", which means your server will be getting a $_POST array with a position labeled "UID".
<?php
if(isset($_POST["uid"])){
echo "Value:".$_POST["uid"];
}else{
echo "Value not found";
}
?>
You should also check what is in the $_POST variable, insert var_dump($_POST) and comment out the rest of the code.

Related

Posting data using jQuery Ajax to another php file [duplicate]

This question already has answers here:
What is the order of inline onclick vs addeventlistener and why?
(3 answers)
Closed 2 years ago.
I have two PHP pages. On one of the pages, I want to post data to the other page when a button is pressed. However, when I try to access the post array from the other page, it appears empty. Would appreciate if someone could show me where I'm going wrong. (Also I'm not allowed to use a html form to post)
Page called test2.php:
<?php
if(isset($_POST['testing1'])){
die(json_encode($_POST));
}
?>
<html>
<head>
<link rel="stylesheet" type="text/css" href="styles.css">
<link rel="stylsheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.9.3/Chart.min.js" integrity="sha512-s+xg36jbIujB2S2VKfpGmlC3T5V2TF3lY48DX7u2r9XzGzgPsa6wTpOQA7J9iffvdeBN0q9tKzRxVxw1JviZPg==" crossorigin="anonymous"></script>
<script src="https://cdn.jsdelivr.net/gh/emn178/chartjs-plugin-labels/src/chartjs-plugin-labels.js"></script>
<script src="https://code.jquery.com/jquery-3.3.1.min.js"></script>
</head>
<body>
<button id="testbtn" onclick="location.href='test1.php'">Test Button</button>
<script>
$(document).ready(function(){
$('#testbtn').click(function() {
$.ajax({
method: 'POST',
url: 'test1.php',
data: {
testing1: 'string1',
testing2: '111'
},
success: function(data){
alert(data);
output = JSON.parse(data);
}
});
});
});
</script>
</body>
</html>
Page called test1.php:
<?php
$testvar = json_encode($_POST);
echo $testvar;
?>
<html>
<head>
<link rel="stylesheet" type="text/css" href="styles.css">
<link rel="stylsheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.9.3/Chart.min.js" integrity="sha512-s+xg36jbIujB2S2VKfpGmlC3T5V2TF3lY48DX7u2r9XzGzgPsa6wTpOQA7J9iffvdeBN0q9tKzRxVxw1JviZPg==" crossorigin="anonymous"></script>
<script src="https://cdn.jsdelivr.net/gh/emn178/chartjs-plugin-labels/src/chartjs-plugin-labels.js"></script>
<script src="https://code.jquery.com/jquery-3.3.1.min.js"></script>
</head>
<body>
</body>
</html>
the reason the it's failing is because you have so much html on test1.php
alert(data) is having an issue because there is so much content.
JSON.parse(data) is failing because it's not just json it's also html
test1.php should just simply parse post to json and echo it
<?php
echo json_encode($_POST);
?>
When you press the button 2 things are happening in same time :
The ajax call that sends data to the page test1.php
The page redirection beacause of the onClick attribute on the button.
The ajax request calls the page test1.php which is not the same instance as the page you call when you use the onClick attribute. So I think you could try placing "location.href = 'test1.php'" in the success function and store $_POST in a session variable. That way the data will reach the test1.php page before your redirect.
success: function(data){
alert(data);
output = JSON.parse(data);
location.href = 'test1.php';
}
Maybe like this:
Page called test2.php:
<head>
<link rel="stylesheet" type="text/css" href="styles.css">
<link rel="stylsheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.9.3/Chart.min.js" integrity="sha512-s+xg36jbIujB2S2VKfpGmlC3T5V2TF3lY48DX7u2r9XzGzgPsa6wTpOQA7J9iffvdeBN0q9tKzRxVxw1JviZPg==" crossorigin="anonymous"></script>
<script src="https://cdn.jsdelivr.net/gh/emn178/chartjs-plugin-labels/src/chartjs-plugin-labels.js"></script>
<script src="https://code.jquery.com/jquery-3.3.1.min.js"></script>
</head>
<body>
<button id="testbtn" onclick="location.href='test1.php'">Test Button</button>
<script>
$(document).ready(function(){
$('#testbtn').click(function() {
$.ajax({
method: 'POST',
url: 'test1.php',
data: "yourData="+"{
testing1: 'string1',
testing2: '111'
}",
dataType:"json",
success: function(data){
alert(data);
output = JSON.parse(data);
}
});
});
});
</script>
</body>
</html>
Page called test1.php:
<?php
if(isset($_POST["yourData"]){
$testvar = json_decode($_POST["yourData"]);
echo $testvar->testing1."<br/>";
echo $testvar->testing2;
}else{
echo"is not set";
}
if(!empty($_POST["yourData"]){echo $_POST["yourData"];}else{echo"is empty";}
?>
<html>
<head>
<link rel="stylesheet" type="text/css" href="styles.css">
<link rel="stylsheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.9.3/Chart.min.js" integrity="sha512-s+xg36jbIujB2S2VKfpGmlC3T5V2TF3lY48DX7u2r9XzGzgPsa6wTpOQA7J9iffvdeBN0q9tKzRxVxw1JviZPg==" crossorigin="anonymous"></script>
<script src="https://cdn.jsdelivr.net/gh/emn178/chartjs-plugin-labels/src/chartjs-plugin-labels.js"></script>
<script src="https://code.jquery.com/jquery-3.3.1.min.js"></script>
</head>
<body>
</body>
</html>
NB:
dataType:"json" used if you want to get a json answer;
if you use dataType:"json" that mean you have to change the method json_decode() in my code to json_encode();
isset() check if name of associative array is exist;
! means not;
empty() check that if the value of that name in associative array is empty (like ' ');
!empty() check that if the value of that name in associative array is not empty (not like ' ').

BootstrapDialog Alert in Codeigniter Controller

I want to use bootstrapDialog alert (https://nakupanda.github.io/bootstrap3-dialog/) instead of default alertbox of browser in my controller but its not working.
I included these scripts I got from the github dist folder in the bottom of view
<link rel="stylesheet" href="assets/css/bootstrap-dialog.min.css" />
<script src="assets/js/bootstrap-dialog.min.js"></script>
Controller
function student(){
if ($student_status == 'paid'){
echo '<script type="text/javascript">';
echo 'BootstrapDialog.alert('Your Registration was successful')';
echo '</script>';
}
else {
// redirect url
}
}
I also tried to echo the css and js files in the controller but failed. If I echo the default alertbox, it works, please what could I be doing wrong?
first - you have some errors:
you need to escape your single quotes of the alert like:
echo 'BootstrapDialog.alert(\'Your Registration was successful\')';
or you could use mix of single and double quotes like:
echo 'BootstrapDialog.alert("Your Registration was successful")';
you also might need to load your script and css with a leading slash like:
<link rel="stylesheet" href="/assets/css/bootstrap-dialog.min.css" />
<script src="/assets/js/bootstrap-dialog.min.js"></script>
you are loading your stylesheet as script, <script src="assets/css/bootstrap-dialog.min.css"></script>; is incorrect, use <link rel="stylesheet" href="your.css">
second - its not a good idea to mix javascript and php the way you do it, you cannot call a jquery function from php, you can only generate html, which then executes at runtime. This would work:
if ($student_status == 'paid'){
$str=' <script src="https://code.jquery.com/jquery-1.12.0.min.js"></script>
<link rel="stylesheet" href="//netdna.bootstrapcdn.com/bootstrap/3.1.1/css/bootstrap.min.css">
<script src="//netdna.bootstrapcdn.com/bootstrap/3.1.1/js/bootstrap.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap3-dialog/1.35.1/js/bootstrap-dialog.min.js"></script>
<script type="text/javascript">
setTimeout(function() {
BootstrapDialog.alert(\'Your Registration was successful\')
},10);
</script>';
echo $str;
}
note the setTimout() function, it is needed to give a little time to make sure all your files are loaded.
third - The correct way is to use ajax instead: see docs:
jquery ajax calls your php function student.
function student returns true or false.
In the ajax success callback you add your bootstrapDialog.alert
Bootstrap dialog is built on Bootstrap, so you must include bootstrap css and bootstrap js, followed by the bootstrapDialog css and js
<!-- Latest compiled and minified CSS -->
<link rel="stylesheet" href="//netdna.bootstrapcdn.com/bootstrap/3.1.1/css/bootstrap.min.css">
<!-- Latest compiled and minified JavaScript -->
<script src="//netdna.bootstrapcdn.com/bootstrap/3.1.1/js/bootstrap.min.js"></script>
http://jsfiddle.net/mreis1/YJdB7/1/
For Example
View:
<!DOCTYPE html>
<html>
<head>
<link href="//maxcdn.bootstrapcdn.com/bootstrap/3.2.0/css/bootstrap.min.css" rel="stylesheet" type="text/css" />
<link href="https://cdnjs.cloudflare.com/ajax/libs/bootstrap3-dialog/1.35.1/css/bootstrap-dialog.min.css" rel="stylesheet" type="text/css" />
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src="//maxcdn.bootstrapcdn.com/bootstrap/3.2.0/js/bootstrap.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap3-dialog/1.35.1/js/bootstrap-dialog.min.js"></script>
<title>Bootstrap Dialog Test</title>
</head>
<body>
<!-- IF SUCCESSFUL -->
<?php $alert= ''; ?>
<?php if ($alert == 'success'): ?>
<script type = "text/javascript">
BootstrapDialog.alert('Your Registration was Successful');
</script>
<?php endif; ?>
<!-- IF FAILED -->
<?php if($alert == 'failed'): ?>
<script type = "text/javascript">
BootstrapDialog.alert({
title: 'An Error Occured',
message: 'Your Registration failed',
type: BootstrapDialog.TYPE_DANGER,
buttonLabel: 'Close'
});
</script>
<?php endif; ?>
</body>
</html>
Controller:
function student(){
if ($student_status == 'paid'){
$data['alert'] = 'success';
}
else {
$data['alert'] = 'failed';
}
$this->load->view(view_page, $data);
}
Output:
echo "BootstrapDialog.alert('Your Registration was successful')"
You have to either escape quotes or use double quotes.
Try This Code
<link rel="stylesheet" href="<?php echo base_url();?>assets/css/bootstrap-dialog.min.css" />
<script src="<?php echo base_url();?>assets/js/bootstrap-dialog.min.js"></script>

Passing variable using ajax and open next page

I try passing variable from one page to next using ajax.
I have running passing, but I don't know how to open page with this variable.
My actual code:
<!DOCTYPE html>
<html lang="pl">
<head>
<meta charset="UTF-8">
<title>Ajax</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<!-- Latest compiled and minified CSS -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" integrity="sha384-1q8mTJOASx8j1Au+a5WDVnPi2lkFfwwEAa8hDDdjZlpLegxhjVME1fgjWPGmkzs7" crossorigin="anonymous">
<!-- Optional theme -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap-theme.min.css" integrity="sha384-fLW2N01lMqjakBkx3l/M9EahuwpSfeNvV63J5ezn3uZzapT0u7EYsXMjQV+0En5r" crossorigin="anonymous">
<!-- Latest compiled and minified JavaScript -->
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js" integrity="sha384-0mSbJDEHialfmuBBQP6A4Qrprq5OVfW37PRR3j5ELqxss1yVqOtnepnHVP9aJ7xS" crossorigin="anonymous"></script>
<!-- <script src="https://code.jquery.com/jquery-2.2.0.min.js"></script>-->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
</head>
<body>
<button id="test" class="btn btn-lg btn-primary">Test</button>
<script>
$(document).ready(function () {
$("#test").click(function () {
var variable = 'AAAaaa';
//alert($(this).attr('id'));
$.ajax({
type: "POST",
url: 'view.php',
data: {"temp": variable},
success: function (data) {
alert("success!");
}
});
});
});
</script>
</body>
</html>
And second page where I want watching what is in $_Post table
<?php
$table = $_POST;
?>
<pre>
<?= print_r($table);?>
</pre>
Edit for comment:
Not a problem. You can create a callback function inside ajax's
success event. On success, take that data from view.php and send it to
the second page with another ajax call. It will all be done
asynchronously and accomplish what you're asking for. – putipong
I have array in view. For example:
$array = array(
"foo" => "bar",
"bar" => "foo",
);
How to send via post and ajax this array to controller function and open this action, when I press the button.
I tried as above , but does not work
public function actionUuuu()
{
$request = Yii::$app->request;
$array = $request->post();
print_r($array)
In your view.php, you can assign the table data to $_SESSION and then retrieve later in your second page, simply by starting a session with session_start();
A session must be started on every page that requires the use of session data, else it will not work.
view.php:
session_start();
if ($_POST['temp'] == 'AAAaaa') {
$_SESSION['tableData'] = $tableData;
echo true;
} else {
echo false;
}
return;
Javascript:
$(document).ready(function () {
$("#test").click(function () {
var variable = 'AAAaaa';
//alert($(this).attr('id'));
$.ajax({
type: "POST",
url: 'view.php',
data: {"temp": variable},
success: function (data) {
if (data == 'true') {
window.location.replace('secondPage.php');
}
}
});
});
});
secondPage.php
session_start();
$table = $_SESSION['tableData'];

Simple Ajax request with php

I'm trying to pass a simple variable from my jQuery to my php and then echo it on my HTML. It doesn't seem to work though.
I can't get my variable $result to show up on my page. Any thoughts? The Ajax POST seems to be working fine. The problem seems to be communication between php and HTML.
index.html:
<!DOCTYPE html>
<html>
<head>
<title>My Site</title>
<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
<script type='text/javascript' src='front.js'></script>
</head>
<body>
<?php echo $result; ?>
</body>
</html>
front.js:
$(document).ready(function() {
$.post('/back.php', {name: "Bob"}, function(data) {
});
});
back.php:
<?php $result = $_POST['name']; ?>
Try this
index.html:
<!DOCTYPE html>
<html>
<head>
<title>My Site</title>
<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
<script type='text/javascript' src='front.js'></script>
</head>
<body>
</body>
</html>
front.js:
$(document).ready(function() {
$.post('/back.php', {name: "Bob"}, function(result) {
$('body').html(result);
});
});
back.php:
<?php echo $_POST['name']; ?>
Change this
<body>
<div id="show-data"></div>
</body>
And
$(document).ready(function() {
$.post('/back.php', {name: "Bob"}, function(data) {
$('#show-data').html(data);
});
});
And
<?php echo $result = $_POST['name']; ?>
Change Your PHP Code :
<?php echo $_POST['name']; ?>
And Also Your HTML Code :
<!DOCTYPE html>
<html>
<head>
<title>My Site</title>
<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
</head>
<body>
</body>
<script>
$(document).ready(function() {
$.post('/back.php', {name: "Bob"}, function(data) {
$('body').append(data)});
});
</script>
</html>
$result in back.php and $result in index.html aren't related. Setting it in back.php has no effect on index.html. If you echo something in back.php however, that output will be passed to the empty callback function you have in your $.post() call. You can handle the data there and use javascript to insert it into your page.
Just add the following line to your code: $('body').html(data);
Like your question we have three different files one is index.html
1) index.html
<!DOCTYPE html>
<html>
<head>
<title>My Site</title>
<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
<script type='text/javascript' src='front.js'></script>
</head>
<body>
<?php echo $result; ?>
</body>
</html>
2) front.js
$(document).load(function(){
$.ajax({
url: '/back.php',
type: 'POST',
data: 'name=Bob',
async: false,
success: function(data) {
$('body').html(data);
},
cache: false
});
});
3) back.php
<?php echo $result = $_POST['name']; ?>
Now use this, your files will work out. Please let me know if you have any queries.
Puh, lot of mistakes. First, your index.html contains PHP - Code which won't be executed because this is not a PHP - Skript (ending with php).
Second you are saving the value of your request to back.php in a variable, which won't be existing after the request is finished. You can either:
rename index.html to index.php, exchange your statement to
<?php echo $_POST['name']; ?>
and change your request to
$.get('/index.php', {name: "Bob"}, function(data) {
});
which would cause a continously reloading of the site,
or store your result in a $_SESSION (see PHP Session Handling), and retrieve that in your index.php (you got to rename the file).

jQuery click event not working from php listing

I have a story uploading system on my webpage, which uploads stories in a specified folder, and from that it lists their content to the webpage. I made a split, so only 300 chars are shown of the text, when the user clicks it, the rest of it is shown.
Here is my code:
This one lists it:
<?php foreach($dataArray as $data) { ?>
<div class="visible">
<?php echo $data[0]; ?>
</div>
<div class="hidden">
<?php echo $data[1]; ?>
</div>
<?php } ?>
This is my jQuery:
$('.hidden').css('display', 'none');
$('.visible').click(function () {
$('.hidden').css('display', 'inline');
});
This page('tortenetek.php') is ajaxed to the main page ('blog.php'). I included Jquery in blog.php like this:
<link href='http://fonts.googleapis.com/css?family=Niconne&subset=latin,latin-ext' rel='stylesheet' type='text/css'>
<link rel="stylesheet" type="text/css" href="../css/stilus.css"/>
<script type="text/javascript" src="../js/jquery-1.7.2.min.js"></script>
<script type="text/javascript" src="../js/tinybox.js"></script>
<script type="text/javascript" src="../js/ajax.js"></script>
<link href="../css/lightbox.css" rel="stylesheet" />
<script src="../js/lightbox.js"></script>
<script src="../js/story.js"></script>
Story.js is the script file i'm using.
Thanks folks!
Use .on method to attach event to dynamically added elements.
Change it to
$('.visible').on('click',function () {
$('.hidden').css('display', 'inline');
});

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