PHP: Using scandir bu excluding ../ ./ in the result - php

Question

I'm using scandir and a foreach loop to display a list of files in a directory to the user. My code is below:
$dir = scandir('/user1/caravans/public_html/wordpress/wp-content/uploads/wpallimport/files');
foreach($dir as $directory)
{
echo "<br/><input type='checkbox' name=\"File[]\" value='$directory'/>$directory<br>";
}
The problem is the script also echos a "." and a ".." (without the speech marks), is there an elegant way to remove these? Short or a regular expression. Thanks

Answer 1

Just continue if the directory is . or .. I recommend to take a look at the control structures here
$dir = scandir('/user1/caravans/public_html/wordpress/wp-content/uploads/wpallimport/files');
foreach($dir as $directory) {
if( $directory == '.' || $directory == '..' ) {
// directory is . or ..
// continue will directly move on with the next value in $directory
continue;
}
echo "<br/><input type='checkbox' name=\"File[]\" value='$directory'/>$directory<br>";
}
Instead of this:
if( $directory == '.' || $directory == '..' ) {
// directory is . or ..
// continue will directly move on with the next value in $directory
continue;
}
you can use a short version of it:
if( $directory == '.' || $directory == '..' ) continue;

Answer 2

You can eliminate these directories with array_diff:
$dir = scandir($path);
$dir = array_diff($dir, array('.', '..'));
foreach($dir as $entry) {
// ...
}

Answer 3

Another solution, in addition to swidmann's answer, is to simply remove '.' and '..' before iterating over them.
Adapted from http://php.net/manual/en/function.scandir.php#107215
$path = '/user1/caravans/public_html/wordpress/wp-content/uploads/wpallimport/files';
$exclude = ['.', '..'];
$dir = array_diff(scandir($path), $exclude);
foreach ($dir as $directory) {
// ...
}
That way you can also easily add other directories and files to the excluded list should the need arise in the future.