I need to perform two different counts in one single query.
First Query: count number of transactions from today 30 days back.
Second Query: count number of transactions from last 60 until last 30 days.
I have first query working fine as:
SELECT
COUNT(*) AS sales
FROM
transactions
WHERE DATE(created) > DATE_SUB(NOW(), INTERVAL 30 DAY)
AND STATUS = 1;
How can I incorporate the second query into the above?
You can use COUNT and CASE WHEN:
SELECT
COUNT(CASE WHEN DATE(created) > DATE_SUB(NOW(), INTERVAL 30 DAY) THEN 1 END) AS c1,
COUNT(CASE WHEN DATE(created) <= DATE_SUB(NOW(), INTERVAL 30 DAY) THEN 1 END) AS c2
FROM transactions
WHERE DATE(created) > DATE_SUB(NOW(), INTERVAL 60 DAY)
AND STATUS = 1;
or UNION:
SELECT COUNT(*) AS sales
FROM transactions
WHERE DATE(created) > DATE_SUB(NOW(), INTERVAL 30 DAY)
AND STATUS = 1
UNION ALL
SELECT COUNT(*)
FROM transactions
WHERE DATE(created) > DATE_SUB(NOW(), INTERVAL 60 DAY)
AND DATE(created) < DATE_SUB(NOW(), INTERVAL 30 DAY)
AND STATUS = 1
Related
In my DB I have a column called dato_tid (Datatype = date)
right now I have 2 post
1 where the date is 2018-07-18
2 where the date is 2018-07-20
I need to select the post, that has less then 24 hours to go
SELECT * FROM `udflyt` WHERE dato_tid > DATE_ADD(CURDATE(), INTERVAL -1 day)
this line will select both posts
SELECT * FROM `udflyt` WHERE dato_tid > DATE_ADD(CURDATE(), INTERVAL -24 HOUR)
and so will this, I did try to change the > to < but the same.
SELECT * FROM `udflyt` WHERE dato_tid > (now() - interval 1 day )
this line will also get both posts
So what do I need to do, Thanks
Actually, 24 hours to go means you should ADD a day, not subtract a day.
SELECT *
FROM `udflyt`
WHERE dato_tid <= DATE_ADD(CURDATE(), INTERVAL +1 day);
Will provide only the record with date '2018-07-18' (which is what you are looking for, I believe.
The below shows the values used for comparison for both doing addition and subtraction.
SELECT *, DATE_ADD(CURDATE(), INTERVAL +1 day), DATE_ADD(CURDATE(), INTERVAL -1 day)
FROM `udflyt`
WHERE dato_tid <= DATE_ADD(CURDATE(), INTERVAL +1 day);
I am retrieving today's data from db,I want to retrieve this month,this year data as well,Is it possible in single query? or should I go with separate query for each items?
My query given below,
select sum(it.rate * it.quantity)as sales from invoices i
join invoice_items it on i.id = it.invoice_id
where i.invoice_date > DATE_SUB(NOW(), INTERVAL 1 DAY)
Use conditional aggregation:
select sum(case when i.invoice_date > DATE_SUB(NOW(), INTERVAL 1 DAY) then it.rate * it.quantity
end) as sales_1day,
sum(case when i.invoice_date > DATE_SUB(NOW(), INTERVAL 7 DAY) then it.rate * it.quantity
end) as sales_7day,
sum(case when i.invoice_date > DATE_SUB(NOW(), INTERVAL 1 MONTH) then it.rate * it.quantity
end) as sales_1month,
sum(case when i.invoice_date > DATE_SUB(NOW(), INTERVAL 1 YEAR) then it.rate * it.quantity
end) as sales_1year
from invoices i join
invoice_items it
on i.id = it.invoice_id
I do know that the following conditions will return the total number in the past 7 days
SELECT count(id) FROM registration
WHERE createdDate BETWEEN DATE_SUB(CURDATE(), INTERVAL 7 DAY) AND CURDATE()
Is there a single query that I can do to get the past 7 days returning in an array of 7 results of each individual day?
For example:
day 1 - 10
day 2 - 5
day 3 - 9
..
..
..
This will give you the date and the count.
SELECT DATE(createdDate),COUNT(id)
FROM registration
WHERE createdDate BETWEEN DATE_SUB(CURDATE(), INTERVAL 7 DAY) AND CURDATE()
GROUP BY DATE(createdDate)
Alternatively to give a result closer to your example you could use:
SELECT CONCAT("Day ",DATEDIFF(NOW(), createdDate)) AS day,COUNT(id)
FROM registration
WHERE createdDate BETWEEN DATE_SUB(CURDATE(), INTERVAL 7 DAY) AND CURDATE()
GROUP BY DATE(createdDate)
Add a group-by clause:
SELECT count(id), DATE(createdDate)
FROM registration
WHERE createdDate BETWEEN DATE_SUB(CURDATE(), INTERVAL 7 DAY) AND CURDATE()
GROUP BY DATE(createdDate)
select 8 - n day, count(id)
from registration
join (select 1 n union select 2 union select 3 union select 4 union select 5 union select 6 union select 7) x
on createdDate between date_sub(curdate(), interval n day) and date_sub(curdate(), interval n-1 day)
group by day
order by day
I have Db which has data of an year...so I need a query to select data from based on a date(particularly yesterday's) and count how many are in this.....
Help please!
It has a column with name "created" where all the date & time are present.
code used:
//$thirty_reg = mysql_query("SELECT column FROM user WHERE user.date BETWEEN DATE_SUB(NOW(), INTERVAL 30 DAY) AND NOW()");
//$num_thirty=mysql_num_rows($thirty_reg);
//echo $num_thirty;
select *
from YourTable
where date_sub(curdate(), interval 1 day) < DateColumn
and DateColumn < curdate()
To fetch result set:
SELECT * FROM table WHERE data_date = DATE_SUB(NOW(), INTERVAL 1 DAY)
To fetch count of rows:
SELECT COUNT(*) FROM table WHERE data_date = DATE_SUB(NOW(), INTERVAL 1 DAY)
I have a table with 3 columns: id, updated_at, click_sum.
Many rows have the exact same updated_at value which makes it hard to simply retrieve the data, order by updated_at and display the sums in a chart.
Since there are multiple sums for the same dates which screws the chart.
What I try to achieve is to get the following output:
update_at | click_sum
-----------+-----------
date1 | 100
date2 | 3
date3 | 235
date4 | 231
Optionally only those dates which are form the last month, week or day AND not simply the dates which are NOW() - 1 month.
The current query I build is very large and doesn't work that well.
It groups by dates (no duplicated dates appear) and SUM()s the clicks correctly but defining from when (last month, week, day) the dates are doesn't seem to work properly.
Query: ($interval stands for MONTH or DAY or SECOND or WEEK)
SELECT d.updated_at, SUM(d.clicks_sum) AS click_sum
FROM aggregated_clicks d
JOIN
(
SELECT c.id, MAX(StartOfChains.updated_at) AS ChainStartTime
FROM aggregated_clicks c
JOIN
(
SELECT DISTINCT a.updated_at
FROM aggregated_clicks a
LEFT JOIN aggregated_clicks b ON (b.updated_at >= a.updated_at - INTERVAL 1 DAY AND b.updated_at < a.updated_at)
WHERE b.updated_at IS NULL
) StartOfChains ON c.updated_at >= StartOfChains.updated_at
GROUP BY c.id
) GroupingQuery
ON d.id = GroupingQuery.id
WHERE GroupingQuery.ChainStartTime >= DATE_SUB(NOW(), INTERVAL 1 $interval)
GROUP BY GroupingQuery.ChainStartTime
ORDER BY GroupingQuery.ChainStartTime ASC
maybe I'm assuming too much about the nature of your question (and the table it refers to), but I think this can be done much more simply than the query you've shown.
figuring the latest completed month isn't very hard.
it starts with knowing the first date of this current month -- use this:
date_sub(curdate(), interval (extract(day from curdate())-1) day)
and to know the first day of that previous month, use this:
date_sub(date_sub(curdate(), interval extract(day from (curdate())-1) day), interval 1 month)
so if you want to get the sums for just the days in between -- i.e. the latest completed month, use this:
select updated_at, sum(click_sum) from aggregated_clicks
where updated_at >= date_sub(date_sub(curdate(), interval extract(day from (curdate())-1) day), interval 1 month)
and updated_at < date_sub(curdate(), interval (extract(day from curdate())-1) day)
group by updated_at;
figuring the lastest completed week is just as easy. this example will assume a Sunday-Saturday week.
because of the way the ODBC standard defines date numbers, it's easy to find the end (Saturday) of the previous week:
date_sub(curdate(), interval dayofweek(curdate()) day)
and the beginning (Sunday) of that week is six days before that:
date_sub(curdate(), interval (dayofweek(curdate())+6) day)
so if you want to get the sums for just the days in between -- i.e. the latest completed week, use this:
select updated_at, sum(click_sum) from aggregated_clicks
where updated_at >= date_sub(curdate(), interval (dayofweek(curdate())+6) day)
and updated_at <= date_sub(curdate(), interval dayofweek(curdate()) day)
group by updated_at;
and of course figuring based on the latest completed day is super easy.
to get the date of the previous day, use this:
date_sub(curdate(), interval 1 day)
so if you want the sums just for yesterday, use this:
select updated_at, sum(click_sum) from aggregated_clicks
where updated_at = date_sub(curdate(), interval 1 day)
group by updated_at;
NOTE: I've tested these queries using MySQL 5.1, YMMV.
----------
UPDATE: since the date column is a datetime, simply change all references to updated_at in my queries to date(updated_at) like so:
month case:
select date(updated_at), sum(click_sum) from aggregated_clicks
where date(updated_at) >= date_sub(date_sub(curdate(), interval extract(day from (curdate())-1) day), interval 1 month)
and date(updated_at) < date_sub(curdate(), interval (extract(day from curdate())-1) day)
group by date(updated_at);
week case:
select date(updated_at), sum(click_sum) from aggregated_clicks
where date(updated_at) >= date_sub(curdate(), interval (dayofweek(curdate())+6) day)
and date(updated_at) <= date_sub(curdate(), interval dayofweek(curdate()) day)
group by date(updated_at);
yesterday case:
select date(updated_at), sum(click_sum) from aggregated_clicks
where date(updated_at) = date_sub(curdate(), interval 1 day)
group by date(updated_at);