How to get following output using PHP - php

Question

My sample desired output should be
1 2 3 4 5
2 4
3 3
4 2
5 4 3 2 1
Here is my PHP code
for($i=1;$i <= 5;$i++) {
for($j=1;$j<=$i;$j++) {
echo "$j";
}
for($y=0;$y<(5-$i)*4;$y++) {
echo ' ';
}
for($l=$i;$l>0;$l--) {
echo "$l";
}
echo "<br/>";
}
But I got this output.
output:-
1 1
12 21
123 321
1234 4321
1234554321
Please try to solve my problem. Thanks in advance.

Answer 1

for($i=1; $i<=5; $i++){
echo $i." ";
}
echo "<br />";
for($i=2; $i<=5; $i++){
if($i==5){
echo $i;
}
else{
echo $i." ";
if($i==2){
echo (4)."<br />";
}
if($i==3){
echo (3)."<br />";
}
if($i==4){
echo (2)."<br />";
}
}
}
echo " ";
for($i=4; $i>=1; $i--){
echo $i." ";
}
#Mark has the best solution, I guess.

Answer 2

Here's a quick solution for an arbitrary array of 1-character values:
$values = range(1,7);
$count = count($values);
foreach($values as $k=>$v) {
if($k == 0)
echo implode(" ", $values), "\n";
elseif($k == $count-1)
echo implode(" ", array_reverse($values)), "\n";
else
echo $v, " ", str_repeat(" ", $count-2), $values[$count-1-$k], "\n";
}
This will produce:
1 2 3 4 5 6 7
2 6
3 5
4 4
5 3
6 2
7 6 5 4 3 2 1

Answer 3

$count = 5;
$last = 0;
for ($i = 1; $i <= $count; $i++) {
if($i == 1) {
for ($x = 1; $x <= 5; $x++) {
echo $x . ' ';
}
$last = $x;
} elseif ($i == 5) {
for ($b = 5; $b >= 1; $b--) {
echo $b . ' ';
}
} else{
for($c=1; $c <= 5; $c++) {
if($c == 1) {
echo $i . ' ';
} elseif ($c == 5) {
echo ($last - $i) . ' ' ;
} else {
echo ' ';
}
}
}
echo '<br>';
}