I have the following code:
$sql = "SELECT * FROM Tickets WHERE stat='Open'";
$result = mysql_query($sql);
mysql_close($con);
?>
<!DOCTYPE>
<html>
<body>
<table class="striped">
<tr class="header">
<td>Username</td>
<td>Title</td>
<td>Description</td>
<td>Admin Name</td>
<td>Category</td>
<td>Status</td>
<td>Urgency</td>
<td>Time In</td>
<td> </td>
</tr>
<?php
while ($row = mysql_fetch_array($result)) {
echo "<tr>";
echo "<td>".$row[username]."</td>";
echo "<td>".$row[title]."</td>";
echo "<td>".$row[description]."</td>";?>
<td><select>
<?php
echo "<option value'".$row[admin_name]."'>".$row[admin_name]."</option>";
$sql = mysql_query("SELECT username FROM Users WHERE user_type='admin'");
while ($u = mysql_fetch_array($sql)){
echo "<option value='".$u['username']."'>".$u['username']."</option>";
}
?>
</select></td>
<?php
echo "<td>".$row[category]."</td>";
echo "<td>".$row[stat]."</td>";
echo "<td>".$row[urgency]."</td>";
echo "<td>".$row[time_in]."</td>";
echo "<td><a href='close.php'>Close Ticket</a></td>";
echo "</tr>";
}
?>
</table>
<a href='update.php'>Update</a>
</body>
</html>
I have two links on this page. Both of them need to update a SQL database. The Close ticket link needs to just update the single row, while the update link should update all of them. I am not sure how to get the info from one php to the next. It seems like you can put the individual row information into a Post array for the close ticket link, but I am not sure how. For the update link it needs to take the value of the dropdown in the table and change the admin_name field to that value.
Related
This question already has answers here:
Creating dynamic tables in HTML using MySQL and PHP
(2 answers)
Closed 11 months ago.
I want to show the list of an array in a table, I want to insert each ID in the ID column, each name in the "name" column, etc...
But it's showing all the content in single column, How I can fix it?
It shows like that right now:
[![enter image description here][1]][1]
PHP:
<table class="blueTable">
<thead>
<tr>
<th>ID</th>
<th>USER</th>
<th>MAIL</th>
</tr>
</thead>
<tfoot>
<tr>
<td colspan="3">
<div class="links">« <a class="active" href="#">1</a> 2 3 4 »</div>
</td>
</tr>
</tfoot>
<tbody>
<?php
$query = $db->query("SELECT * FROM users ORDER by id");
echo "<tr>";
while ($row = $query->fetch_array()) {
echo "<td>" . $row['id'] . "</td>";
echo "<tr><td>" . $row['username'] . "</td></tr>";
echo "<tr><td>" . $row['email'] . "</td></tr>";
}
?>
</tbody>
</table>
[1]: https://i.stack.imgur.com/jPTR8.png
change while() loop code like below:
$query = $db->query("SELECT * FROM users ORDER by id");
while($row = $query->fetch_array()){
echo "<tr>"; //put <tr> opening code inside, not outside
echo "<td>".$row['id']."</td>";
echo "<td>".$row['username']."</td>"; //remove <tr></tr>
echo "<td>".$row['email']."</td>"; //remove <tr></tr>
echo "</tr>"; //</tr> need to be added at last
}
Try this
<?php
$query = $db->query("SELECT * FROM users ORDER by id");
while($row = $query->fetch_array()){
?>
<tr>
<td> <?php echo $row['id'] ?></td>
<td> <?php echo $row['username'] ?> </td>
<td> <?php echo $row['email'] ?> </td>
</tr>
<?php
}
?>
I have this table im trying to display users, being 2 users per 2 columns, then list down. Here is what i have so far:
<?php $result = mysql_query("SELECT * from users WHERE adminlevel='5'");
while($row = mysql_fetch_array($result)) { echo
" <table>
<tr>
<td width='85' align='left'><br><center>". $row['username'] . "</center>
</td>
<td align='right'><center></center>
</td>
</tr>
<td width='85' align='left'><center></center>
</td>
<td align='right'><center></center>
</td>
</table>";
} ?>
This just displays the members as rows going down, and missing out the other column completely. I was hoping that it would display the username in each of the table fields. I also did try putting ". $row['username'] ." in the other fields too, but that just duplicated it.
EDIT:
So iv'e changed it to this, I can't see going down as I only have 2 members, Would this work:
<?php $result = mysql_query("SELECT * from users WHERE adminlevel='5'"); ?>
<table>
<tr>
<?php while($row = mysql_fetch_array($result)) { echo
"<td width='85' align='left'><font size='1px'><center>". $row['username'] . "</font></center></td>
<td align='right'><center></center></td>";
} ?>
</tr>
</table>
example:
try something like this
<table>
<tr>
<th>name</th>
<th>name</th>
</tr>
<?php
$result = mysql_query("SELECT * from users WHERE adminlevel='5'");
$i = 0;
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
if ($i == '0') echo "<tr>";
echo "<td>{$row['username']}</td>";
if ($i == '1') echo "</tr>";
$i++;
if($i =='2')$i='0';
}
?>
</table>
I think you're asking why the other fields in your "user" mysql table aren't showing up.
They aren't there because you only asked for the username:
$row['username']
If you have first/last name in your mysql table, you can retrieve it in the same way:
$row['firstname']
$row['lastname']
In your code you got the row as a key/value array like this:
$row = mysql_fetch_array($result)
The "key" is the name of the mysql column, like username, lastname, firstname. And the value is what is stored in the mysql table under that row/column, like joecool, smith, joe.
Insert Is Fine But if I select this value from database All Values are fine but single values fetch array problem I don't know how to solve this task. Please Update this code asap.
This Is Insert Code .....
<?php
if(isset($_POST['sendmessage'])){
$entermessage = $_POST['teachermessage'];
$checkbox_user = $_POST['usernameallcheckbx'];
$arr = implode(',',$checkbox_user);
//$arr2 = explode(',',$arr);
$insert = mysql_query("INSERT into usermessages(fromteacher,toparent,messages) VALUES('".$_SESSION['username']."','$arr','$entermessage')");
if($insert == 1){
echo "<h1>successful</h1>";
}
else{
echo mysql_error();
}
}
?>
<form method="post">
<div style="float:left; width:450px;"><br/><br/>Message: <br/>
<textarea style="width:400px; height:300px;" name="teachermessage"></textarea><br/>
<input type="submit" value="Send" name="sendmessage" /></div>
<div style="float:left; with:200px; padding-top:55px;">
<table>
<tr>
<?php
$select_query1 = mysql_query("SELECT * FROM register_user WHERE teacher='$teachername'");
while($chckbx=mysql_fetch_array($select_query1))
{
?>
<td><?php echo "<input type='checkbox' name='usernameallcheckbx[]' value=". $chckbx['userid']." />"; ?></td>
</tr>
<tr>
<td><?php echo $chckbx['parent_fname']." ".$chckbx['parent_lname']; ?></td>
</tr>
<?php
}
?>
</table>
</div>
</form>
And This Is Select Code....
<h2>Messages</h2>
<?php
$select_query3 = mysql_query("SELECT * FROM usermessages");
$fetch= mysql_fetch_array($select_query3);
$data=$fetch['toparent'];
$arr=explode(',',$data);
//$userids=explode(',',$data);
$sessionshow=$_SESSION['userid'];
$userids=in_array("$sessionshow",$arr);
$select_query2 = mysql_query("SELECT * FROM usermessages WHERE toparent in ('$userids')='".$_SESSION['userid']."'");
?>
<table border="0" cellpadding="0" cellspacing="0">
<tr>
<th>Teacher Name</th>
<th>Message</th>
</tr>
<?php
while($fetch_name2=mysql_fetch_array($select_query2))
{
echo "<tr>";
echo "<td>".$fetch_data=$fetch_name2['fromteacher']."</td>";
echo "<td>".$fetch_data=$fetch_name2['messages']."</td>";
echo "</tr>";
}
?>
</table>
I have only put this as an answer to show some incorrect code - remove fetch data from your loop as it doesn't do anything
while($fetch_name2=mysql_fetch_array($select_query2))
{
echo "<tr>";
echo "<td>".$fetch_name2['fromteacher']."</td>";
echo "<td>".$fetch_name2['messages']."</td>";
echo "</tr>";
}
even better is use of a HEREDOC:
while($fetch_name2=mysql_fetch_array($select_query2))
{
echo <<<EOF
<tr>
<td>{$fetch_name2['fromteacher']}</td>
<td>{$fetch_name2['messages']}</td>
</tr>
EOF;
}
I really can't figure out what you're trying to do, but maybe this is the query you want:
SELECT * FROM usermessages WHERE FIND_IN_SET('$sessionshow', toparent)
FIND_IN_SET(str, strlist) searches the comma-separated list in strlist for an element that equals str, and returns the position in the list; if it's not found it returns 0, which counts as false.
I can't see any purpose to any of the code that uses $select_query3.
I am new to php and dropdown menus, my query works, but when displaying it is always missing the last row entered. So if I have two rows entered, the drop down will only display one? What am I doing wrong?
<?php
require("********");
$query=mysql_query("select * from types");
echo "<table >
<tr align='left'>
<th><font color='red'>Description</th>
</tr>";
$options='';
while($dbfield = mysql_fetch_array($query))
{
$options .= '<option>'.$dbfield['Description'].'</option>';
echo "
<form method='post'>
<td><select name='Description'><? echo $options; ?></select>
</tr>";
You don't close (}) your while loop.
You're also not consistent
with your table structure.
mysql_ functions are also deprecated.
<?php
require("********");
$query=mysql_query("select * from types");
echo "<form method='post'>
<table>
<tr align='left'>
<th><font color='red'>Description</th>
</tr>";
$options='';
while($dbfield = mysql_fetch_array($query)) {
$options .= '<option>'.$dbfield['Description'].'</option>';
}
echo "<tr>
<td><select name='Description'><? echo $options; ?></select>
</tr>";
My code
<?php
include('ConnectToDb.php');
$query = "SELECT * FROM News WHERE NewsFlag = 1 ORDER BY PostDate DESC";
$arrCount = -1;
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
$ID=$row['ID'];
$PostDate = $row['PostDate'];
$NewsHeader = stripslashes($row['NewsHeader'])
;
$NewsStart = stripslashes($row['NewsStart'])
;
echo "<hr>";
echo "<div>". date('j F Y',strtotime($PostDate)). "</div>";
echo "<p>";
$news_id = strval(sprintf("%1$04d",$ID));
$array = scanImageFolder("newsImages/newsThumbs",$news_id);
if(count($array)>0) {
echo "<img src='". $array[0]. "' alt='' />";
}
echo "<h2 style='text-align:center'><u><a href='latestnews_full.php?ID=$ID'>". $NewsHeader. "</a></u></h2>";
echo "<div style='text-align:left'><h3>";
echo $NewsStart. " ......<a href='latestnews_full.php?ID=$ID'>(more)</a><br />";
echo "<div style='text-align:center'>";
echo "</div>";
echo "</h3></div>";
}
?>
displays my data nicely on four lines with date at the top, then a picture, title and then description.
However, I want to display the data as a table like this
<table style="width: 100%">
<tr>
<td colspan="2">postDate here</td>
</tr>
<tr>
<td rowspan="2">picture here</td>
<td>newsHeader here</td>
</tr>
<tr>
<td>newsStart here</td>
</tr>
</table>
I'm not sure how to echo the table cells correctly and all of my attempts so far have resulted in a white page. Could anyone please enlighten me?
I'd suggest you to make your logic separated from your presentable part. Close the PHP tag once you are ready fetching the results, assigning var's etc, then:
<table style="width: 100%">
<?php
//yourcode
//...
//...
$NewsStart = stripslashes($row['NewsStart']);
$news_id = strval(sprintf("%1$04d",$ID));
$array = scanImageFolder("newsImages/newsThumbs",$news_id);
?>
<tr>
<td colspan="2"><?= date('j F Y',strtotime($PostDate)) ?></td>
</tr>
<tr>
<?php
if(count($array)>0) {
?>
<td rowspan="2"><img src='<?= $array[0] ?>' alt='' /></td>
<?php } ?>
<td><?= $NewsHeader ?></td>
</tr>
<tr>
<td><?= $NewsStart ?> </td>
</tr>
<?php } ?>
</table>
However, it's again not so clear, and I would suggest using a template engine. If you want I can post a code with assigning vars to Smarty and output your presentation in Smarty template