get a variable number from sql - php

I'm a beginner in php. I'm trying get a variable number from sql ,
I have this part of code:
function renderNotification()
{
if ($user_id = $this->getDi()->auth->getUserId()) {
$cnt = $this->getDi()->db->selectCell("SELECT COUNT(ticket_id) FROM ?_helpdesk_ticket WHERE status IN (?a) AND user_id=?",
array(HelpdeskTicket::STATUS_AWAITING_USER_RESPONSE), $user_id);
if ($cnt)
return '<div class="am-info">' . ___('You have %s%d ticket(s)%s that require your attention',
sprintf('', REL_ROOT_URL . '/helpdesk/index/p/index/index?&_user_filter_s[]=awaiting_user_response'), $cnt, '') .
'</div>';
}
}
i want get number of ticket only in other place in my program
This is my try:
<?php echo "%s%d" ; ?>
or
<?php echo $cnt ; ?>
but not work
i'm using Zend , sf , pear , all what i need output %s%d ticket(s)%s from above code in other place or call it

i have found correct way it's below
<?php
$cnt = $di->db->selectCell("SELECT COUNT(ticket_id)
FROM ?_helpdesk_ticket
WHERE status IN (?a)
AND user_id=?",
array(HelpdeskTicket::STATUS_AWAITING_USER_RESPONSE),
$di->user->pk());
echo $cnt;
?>

Related

PHP function called on link click not giving any results

I'm trying to solve this for some time. I have PHP function that is called on link click. When I click on link it's directing me to this function but it's not giving any results.
Here is how I call function.
foreach ($bandsN as $aa) {
$str = explode(',', $aa);
$next = $str[1];
?>
<?php echo $str[0]?> </div> <?php
if (isset($_GET['other'])) {other($next);}
}
In this function it's called mysql stored procedure with parameter of php function.
function other($var)
{
echo $var;
if (!$mysqli->multi_query("CALL p($var)")) {
echo "CALL failed: (" . $mysqli->errno . ") " . $mysqli->error;
}
do{
if($resul = $mysqli->store_result()){
$bands = array();
while($ro = $resul->fetch_row())
{
$bands[] = implode(',', $ro);
}
foreach ($bands as $aa) { ?>
<p > <?php echo $aa?> </p> </div><?php
}
$resul->free();
unset($bands);
}}
while($mysqli->more_results() && $mysqli->next_result());
}
I don't know which is the problem. This code inside function is working because I already have it in other part of app.
If somebody can see what is wrong I would be very grateful.

How to create strings in for loop with SELECT using variable variables PHP

Where I made a mistake to get output like I wrote below?
Inside array are names of tables.
Let's say in those tables are 0 rows, so everywhere should be 0 as a output.
<?php
$g_module =
array(
'm_b_broadcast_live',
'm_b_browsing_live',
'm_e_askfm_likes_live',
'm_e_facebook_followers_live',
'm_e_facebook_group_joins_live',
);
for ($i = 0; $i <= 5; $i++) {
$modules_names = "g_module[$i]";
$modules_from = '$'.$modules_names;
$modules_rows = '$g_module_row_'.$i;
$$modules_rows = mysql_num_rows("SELECT * FROM $$modules_from");
}
echo $g_module_row_1;
echo '</br>';
echo $g_module_row_2;
echo '</br>';
echo $g_module_row_3;
echo '</br>';
echo $g_module_row_4;
echo '</br>';
echo $g_module_row_5;
/* output should be:
0
0
0
0
0
*/
?>
As stated in the comments to your question already, mysql_num_rows() takes a query result as parameter, not a query string.
Also, you should use mysqli! Look at the documentation here.
Something else that you can simplify is to escape the dollar sign so you don't have to concatenate one to $modules_names again.
The corrected code would look like this:
<?php
$g_module = [
'm_b_broadcast_live',
'm_b_browsing_live',
'm_e_askfm_likes_live',
'm_e_facebook_followers_live',
'm_e_facebook_group_joins_live',
];
// you have to create a connection to your database server first
// of course you will have to swap out my placeholders for the actual credentials
$con=mysqli_connect('mysql_server_address_here','username_here','password_here','database_name_here');
for($i=0;$i<=5;$i++){
$modules_from = "\$g_module[$i]";
$modules_rows = "\$g_module_row_$i";
$q=mysqli_query("SELECT * FROM $$modules_from");
//use mysqli_num_rows instead
$$modules_rows = mysqli_num_rows($q);
}
// close your connection after you are finished
mysqli_close($con);
echo $g_module_row_1;
echo '</br>';
echo $g_module_row_2;
echo '</br>';
echo $g_module_row_3;
echo '</br>';
echo $g_module_row_4;
echo '</br>';
echo $g_module_row_5;
<?php
$g_module =
array(
'm_b_broadcast_live',
'm_b_browsing_live',
'm_e_askfm_likes_live',
'm_e_facebook_followers_live',
'm_e_facebook_group_joins_live',
);
foreach($g_module as $table_name){
$count = mysql_num_rows("SELECT * FROM $table_name");
echo "<br/>".$count;
}
?>
I think you should try like this.

Instagram API pagination in PHP

I am trying to create a small instagram app in PHP only (no database) and without getting an access_token (just my client_id). So far so good, (i.e. input user_id returns photos from last 30 days, with likes-count and created_time, in a table), until I get to pagination. As expected, I want to hit a 'more' button which loads next json file and adds additional photos to the existing table, but it falls apart there... Here is what I've got, working, except for the pagination attempt.
NOTE: this is an internal app, so the sensitivity of my client_id is not an issue, if it is exposed
<?php
if (!empty($_GET['user_id'])){
$user_id = ($_GET['user_id']);
$instagram_url = 'https://api.instagram.com/v1/users/' . $user_id . '/media/recent/?client_id=MY_CLIENT_ID';
$instagram_json = file_get_contents($instagram_url);
$instagram_array = json_decode($instagram_json, true);
}
?>
...
<?php
if(!empty($instagram_array)){
$instagram_array['pagination'] as $page { // Attempt at pagination
echo '<p>' .$page['next_url'].'</p>'; // Attempt at pagination
} // Attempt at pagination
foreach($instagram_array['data'] as $image){
if ($image['created_time'] > strtotime('-30 days')) {
echo '<tr>';
echo '<td>' . date('M d, Y', $image['created_time']) . '</td>';
echo '<td>'.$image['likes']['count'].'</td>';
echo '<td><img src="'.$image['images']['standard_resolution']['url'].'" alt=""/ style="max-height:40px"></td>';
echo '</tr>';
}
}
}
?>
</body>
</html>
Note: this is cobbled together from a few other sources - I am a total noob, so please forgive me if I need a little hand-holding...:)
You may specify min_timestamp to return medias which taken later than this timestamp
https://api.instagram.com/v1/users/{user_id}/media/recent/?access_token={access_token}&min_timestamp={min_timestamp}
$instagram_array['pagination']['next_url'] should be removed, it may include your access token which is a sensible data, that must be always invisible.
list_ig.php
<?
$user_id = "...";
$access_token = "...";
//30 day ago
$min_timestamp = strtotime("-30 day",time());
//pagination feature
$next_max_id = $_GET['next_max_id'];
$instagram_url = "https://api.instagram.com/v1/users/" . $user_id . "/media/recent/?access_token=" .$access_token. "&min_timestamp=" . $min_timestamp;
if($next_max_id != "")
$instagram_url .= "&max_id=" . $next_max_id;
$instagram_json = file_get_contents($instagram_url);
$instagram_array = json_decode($instagram_json ,true);
?>
<? if( $instagram_array['pagination']['next_max_id'] != "" ): ?>
More
<? endif;?>
.... print instagram data....
Instagram AJAX Demo
http://jsfiddle.net/ajhtLgzc/

Unable to retrieve results from site

Everything's working fine but I was unable to retrieve the total number of results from the site (faroo)..
<?php
if (isset($_GET['q']))
{
$q = $_GET['q'];
$p = $_GET['p'];
$page = file_get_contents('http://www.faroo.com/api?q=' . $q
. '&start=' . $p . '&l=en&key='.$myownkey.'&src=web&f=json');
// echo $page->{'count'}; //this too not working
$dat_array = json_decode($page, true);
echo $dat_array->{'count'}; //not woking.
}
?>
where am I going wrong?
json_decode($page, true);
The second parameter as "true" turns the data into an associative array rather than an object. To access the data this should work:
echo $dat_array['count'];

php and mysql not showing data, not entering foreach loop

I am having trouble with modifying a php application to have pagination. My error seems to be with my logic, and I am not clear exactly what I am doing incorrectly. I have had before, but am not currently getting errors that mysql_num_rows() not valid result resource
and that invalid arguments were supplied to foreach. I think there is a problem in my logic which is stopping the results from mysql from being returned.
All my "test" echos are output except testing while loop. A page is generated with the name of the query and the word auctions, and first and previous links, but not the next and last links. I would be grateful if a more efficient way of generating links for the rows in my table could be pointed out, instead of making a link per cell. Is it possible to have a continuous link for several items?
<?php
if (isset($_GET["cmd"]))
$cmd = $_GET["cmd"]; else
die("You should have a 'cmd' parameter in your URL");
$query ='';
if (isset($_GET["query"])) {
$query = $_GET["query"];
}
if (isset($_GET["pg"]))
{
$pg = $_GET["pg"];
}
else $pg = 1;
$con = mysql_connect("localhost","user","password");
echo "test connection<p>";
if(!$con) {
die('Connection failed because of' .mysql_error());
}
mysql_query('SET NAMES utf8');
mysql_select_db("database",$con);
if($cmd=="GetRecordSet"){
echo "test in loop<p>";
$table = 'SaleS';
$page_rows = 10;
$max = 'limit ' .($pg - 1) * $page_rows .',' .$page_rows;
$rows = getRowsByProductSearch($query, $table, $max);
echo "test after query<p>";
$numRows = mysql_num_rows($rows);
$last = ceil($rows/$page_rows);
if ($pg < 1) {
$pg = 1;
} elseif ($pg > $last) {
$pg = $last;
}
echo 'html stuff <p>';
foreach ($rows as $row) {
echo "test foreach <p>";
$pk = $row['Product_NO'];
echo '<tr>' . "\n";
echo '<td>'.$row['USERNAME'].'</td>' . "\n";
echo '<td>'.$row['shortDate'].'</td>' . "\n";
echo '<td>'.$row['Product_NAME'].'</td>' . "\n";
echo '</tr>' . "\n";
}
if ($pg == 1) {
} else {
echo " <a href='{$_SERVER['PHP_SELF']}?pg=1'> <<-First</a> ";
echo " ";
$previous = $pg-1;
echo " <a href='{$_SERVER['PHP_SELF']}?pg=$previous'> <-Previous</a> ";
}
echo "---------------------------";
if ($pg == $last) {
} else {
$next = $pg+1;
echo " <a href='{$_SERVER['PHP_SELF']}?pg=$next'>Next -></a> ";
echo " ";
echo " <a href='{$_SERVER['PHP_SELF']}?pg=$last'>Last ->></a> ";
}
echo "</table>\n";
}
echo "</div>";
function getRowsByProductSearch($searchString, $table, $max) {
$searchString = mysql_real_escape_string($searchString);
$result = mysql_query("SELECT Product_NO, USERNAME, ACCESSSTARTS, Product_NAME, date_format(mycolumn, '%d %m %Y') as shortDate FROM {$table} WHERE upper(Product_NAME) LIKE '%" . $searchString . "%'" . $max);
if($result === false) {
echo mysql_error();
}
$rows = array();
while($row = mysql_fetch_assoc($result)) {
echo "test while <p>";
$rows[] = $row;
}
return $rows;
mysql_free_result($result);
}
edit: I have printed out the mysql error of which there was none. However 8 "test whiles" are printed out, from a database with over 100 records. The foreach loop is never entereded, and I am unsure why.
The problem (or at least one of them) is in the code that reads:
$rows = getRowsByProductSearch($query, $table, $max);
$numRows = mysql_num_rows($rows);
The $numRows variable is not a MySQL resultset, it is just a normal array returned by getRowsByProductSearch.
Change the code to read:
$rows = getRowsByProductSearch($query, $table, $max);
$numRows = count($rows);
Then it should at least find some results for you.
Good luck, James
Hi there,
The next problem is with the line that reads:
$last = ceil($rows/$page_rows);
It should be changed to read:
$last = ceil($numRows / $page_rows);
Would recommend adding the following lines to the start of you script at least while debugging:
ini_set('error_reporting', E_ALL | E_STRICT);
ini_set('display_errors', 'On');
As that would have thrown up a fatal error and saved you a whole lot of time.
if (!(isset($pg))) {
$pg = 1;
}
How is $pg going to get set? You don't appear to be reading it from $_GET. If you're relying on register_globals: don't do that! Try to read it from $_GET and parse it to a positive integer, falling back to '1' if that fails.
<a href='{$_SERVER['PHP_SELF']}?pg=$next'>Next -></a>
You appear to be losing the other parameters your page needs, 'query' and 'cmd'.
In general I'm finding it very difficult to read your code, especially the indentation-free use of echo(). Also you have untold HTML/script-injection vulnerabilities every time you "...$template..." or .concatenate a string into HTML without htmlspecialchars()ing it.
PHP is a templating language: use it, don't fight it! For example:
<?php
// Define this to allow us to output HTML-escaped strings painlessly
//
function h($s) {
echo(htmlspecialchars($s), ENT_QUOTES);
}
// Get path to self with parameters other than page number
//
$myurl= $_SERVER['PHP_SELF'].'?cmd='.urlencode($cmd).'&query='.urlencode($query);
?>
<div id="tableheader" class="tableheader">
<h1><?php h($query) ?> Sales</h1>
</div>
<div id="tablecontent" class="tablecontent">
<table border="0" width="100%"> <!-- width, border, cell width maybe better done in CSS -->
<tr>
<td width="15%">Seller ID</td>
<td width="10%">Start Date</td>
<td width="75%">Description</td>
</tr>
<?php foreach ($rows as $row) { ?>
<tr id="row-<?php h($row['Product_NO']) ?>" onclick="updateByPk('Layer2', this.id.split('-')[1]);">
<td><?php h($row['USERNAME']); ?></td>
<td><?php h($row['shortDate']); ?></td>
<td><?php h($row['Product_NAME']); ?></td>
</tr>
<?php } ?>
</table>
</div>
<div class="pagercontrols">
<?php if ($pg>1) ?>
<<- First
<?php } ?>
<?php if ($pg>2) ?>
<-- Previous
<?php } ?>
<?php if ($pg<$last-1) ?>
Next -->
<?php } ?>
<?php if ($pg<$last) ?>
Last ->>
<?php } ?>
</div>
Is it possible to have a continuous link for several items?
Across cells, no. But you're not really using a link anyway - those '#' anchors don't go anywhere. The example above puts the onclick on the table row instead. What exactly is more appropriate for accessibility depends on what exactly your application is trying to do.
(Above also assumes that the PK is actually numeric, as other characters may not be valid to put in an 'id'. You might also want to consider remove the inline "onclick" and moving the code to a script below - see "unobtrusive scripting".)
This is wrong:
if($cmd=="GetRecordSet")
echo "test in loop\n"; {
It should be:
if($cmd=="GetRecordSet") {
echo "test in loop\n";
In your getRowsByProductSearch function, you return the result of mysql_error if it occurs. In order to debug the code, maybe you can print it instead, so you can easily see what the problem is.

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