I wrote a simple program that has two tables, one user and the other update_acc where the users table contains the registration details like username, name, last name, bank, account number of user while the update_acc contains users username, perfect money name, perfect money no. I have able to create the join but I want to output it one into a table with each information to its field then it shouldn't bring out every information to the user but just his own information, thanks.
` <?php
require_once 'core/init.php';
error_reporting(0);
require 'db/connect.php';
$sql = "
SELECT
users.username, users.name, users.last_name, users.bank, update_acc.perfect_money, update_acc.pm_no as update_acc
FROM users
JOIN update_acc ON users.username = update_acc.username
";
$results = $db->query($sql);
if($results->num_rows) {
while($row = $results->fetch_object()) {
echo "{$row->username} {$row->name} {$row->last_name} {$row->bank} {$row->update_acc}<br>";
}
}else{
echo 'No results.';
}
`
I guess what you are looking for is a where clause.
$sql = "
SELECT
users.username, users.name, users.last_name, users.bank, update_acc.perfect_money, update_acc.pm_no as update_acc
FROM users
JOIN update_acc ON users.username = update_acc.username
where users.username='adabebi' ";
this will show records for only username adabebi
Related
I have two different tables, one named users, and another named transactions. Transactions contains wallet1, wallet2, amount. Users contains user details such as firstname, lastname, and wallet. I am trying to display the corresponding first name and last name, depending on whether or not the SESSION_wallet is equal to wallet1 or wallet2 within transactions. I tried searching for a while, and came up with a solution for showing the correct display name for the first and last name making the transfer, however, I am trying to make it display the correct value for "Transfer to:"
Here is some of my code to get a better understanding of what I mean:
MySQLi Query:
$result2 = mysqli_query($link, "SELECT * FROM transactions INNER JOIN users ON transactions.wallet1 = users.wallet WHERE transactions.wallet1 = '" . $_SESSION["wallet"] . "' OR transactions.wallet2 = '" . $_SESSION["wallet"] . "' Order by transactions.id DESC LIMIT 5 ");
PHP Code:
<?php
if(mysqli_num_rows($result2) > 0)
{
while($row = mysqli_fetch_array($result2))
{
?>
The table that needs to display the transfer from, and transfer to:
<?php
if ($_SESSION["wallet"] == $row["wallet1"]) {
echo "<td>Transfer to ".$row["firstname"]." ".$row["lastname"]."</td>";
}
else if ($_SESSION["wallet"] == $row["wallet2"]) {
echo "<td>Transfer from ".$row["firstname"]." ".$row["lastname"]."</td>";
}
?>
Right now my tables are only showing the first and last name of the user that made the Transfer, however, I need it to display the first and last name of the user that the transaction is made to as well. The else if code is working correct, but the first part is not showing the corresponding value.
You will need to JOIN your transactions table to your users table twice, once to get each users name. Then to avoid duplicate column names overwriting the results in the output array, you will need to use column aliases. Something like this should work:
$result2 = mysqli_query($link, "SELECT t.*,
u1.firstname AS w1_firstname,
u1.lastname AS w1_lastname,
u2.firstname AS w2_firstname,
u2.lastname AS w2_lastname
FROM transactions t
INNER JOIN users u1 ON t.wallet1 = u1.wallet
INNER JOIN users u2 ON t.wallet2 = u2.wallet
WHERE t.wallet1 = '{$_SESSION["wallet"]}'
OR t.wallet2 = '{$_SESSION["wallet"]}'
ORDER BY t.id DESC
LIMIT 5 ");
Then you can access each user's names as $row['w1_firstname'] etc.:
if ($_SESSION["wallet"] == $row["wallet1"]) {
echo "<td>Transfer to ".$row["w2_firstname"]." ".$row["w2_lastname"]."</td>";
}
else if ($_SESSION["wallet"] == $row["wallet2"]) {
echo "<td>Transfer from ".$row["w1_firstname"]." ".$row["w1_lastname"]."</td>";
}
Note that ideally you should use a prepared query for this, for example:
$stmt = $link->prepare("SELECT t.*,
u1.firstname AS w1_firstname,
u1.lastname AS w1_lastname,
u2.firstname AS w2_firstname,
u2.lastname AS w2_lastname
FROM transactions t
INNER JOIN users u1 ON t.wallet1 = u1.wallet
INNER JOIN users u2 ON t.wallet2 = u2.wallet
WHERE t.wallet1 = ?
OR t.wallet2 = ?
ORDER BY t.id DESC
LIMIT 5");
$stmt->bind_param('ss', $_SESSION["wallet"], $_SESSION["wallet"]);
$stmt->execute();
$result2 = $stmt->get_result();
I develop a chat system where students and staff can exchange different messages. I have developed a database where we have five tables: the staff table, the student, the message and two mapping tables the staff_message and stu_message. These tables contain only the student/staff id and the message id.
My problem is that I cannot order the messages. I mean that I cannot figure out how can I make one SQL statement that will return all messages and be ordered by for example the ID. The code that I have made is this:
$qu = mysqli_query($con,"SELECT * FROM stu_message");
while($row7 = mysqli_fetch_assoc($qu)){
$que = mysqli_query($con, "SELECT * FROM student WHERE studentid =".$row7['stu_id']);
while($row8 = mysqli_fetch_assoc($que)) {
$username = $row8['username'];
}
$query3 = mysqli_query($con, "SELECT * FROM message WHERE id=".$row7['mid']);
while($row6 = mysqli_fetch_assoc($query3)) {
echo $row6['date']."<strong> ".$username."</strong> ".$row6['text']."<br>";
}
}
$query2 = mysqli_query($con, "SELECT * FROM staff_message");
while($row3 = mysqli_fetch_assoc($query2)){
$query = mysqli_query($con, "SELECT * FROM staff WHERE id =".$row3['staff_id']);
while($row5 = mysqli_fetch_assoc($query)) {
$username = $row5['username'];
}
$query3 = mysqli_query($con, "SELECT * FROM message WHERE id=".$row3['m_id']);
while($row6 = mysqli_fetch_assoc($query3)) {
echo $row6['date']."<strong> ".$username."</strong> ".$row6['text']."<br>";
}
}
?>
The result is different from that I want. To be more specific first are shown the messages from the students and then from the staff. My question is, is there any query that it can combine basically all these four tables in one and all messages will be shown in correct order? for example by the id?
Thank you in advance!
First, use JOIN to get the username corresponding to the stu_id or staff_id, and the text of the message, rather than separate queries.
Then use UNION to combine both queries into a single query, which you can then order with ORDER BY.
SELECT u.id, u.text, u.username
FROM (
SELECT s.username, m.text, m.id
FROM message AS m
JOIN stu_message AS sm ON m.id = sm.mid
JOIN student AS s ON s.id = sm.stu_id
UNION ALL
SELECT s.username, m.text, m.id
FROM message AS m
JOIN staff_message AS sm ON m.id = sm.m_id
JOIN staff AS s ON s.id = sm.staff_id
) AS u
ORDER BY u.id
I want to get some statitics out for my adminpanel.
I have two tables named users and cms_prosjekt. I want to count how many projects
that have the same attribute as users.
Each user have a motto that is connected to a project.
For example: Motto is spirit and the project code is spirit. It won't return anything. I have two users with the same motto as code in a project.
<?php
$result = mysql_query("SELECT
users.id,
COUNT(users.motto) AS count
FROM
users
LEFT JOIN cms_prosjekt ON
users.motto=cms_prosjekt.code
GROUP BY
users.motto");
$num_rows = mysql_num_rows($result);
echo "$num_rows";
?>
The query should be count(*) and group by user.motto
"SELECT
user.motto
, COUNT( * ) AS count
FROM users
LEFT JOIN cms_prosjekt ON users.motto=cms_prosjekt.code
GROUP BY users.motto"
The group by should be users.id not users.motto :
<?php
$result = mysql_query("SELECT users.id, COUNT(users.motto) AS count FROM users LEFT JOIN cms_prosjekt ON users.motto=cms_prosjekt.code GROUP BY (users.id)");
$num_rows = mysql_num_rows($result);
echo $num_rows;
?>
Note : i can't see any value for the left join you don't need any data from cms_prosjek but i keep it if you will use it later
I found the solution, but now I want to add a specific user id to the query. Since every administrator have their own home area, I want to list all the users that is connected to a specific administrator. Each administrator is creating projects with users.
I tried this:
$result = mysql_query("SELECT users.motto, COUNT( * ) AS count FROM users
WHERE id = '".$_SESSION['user']['id']."'
LEFT JOIN cms_prosjekt ON users.motto=cms_prosjekt.code
GROUP BY users.motto");
So I have two tables, one storing the username and the other with their personal info. What I'm trying to get is a result where, I want to take the current active username and join it with the personal info table to get the ID, Username + their basic info to appear in a table. I came up with the query after googling, but it seems that I did something wrong. Can someone tell me what I did wrong?
users = the table that contain username
userinfo table with their basic info
$username is basically a variable that was stored in the $SESSION
<?php
$query = mysql_query("
SELECT users.UserID, users.Username, userinfo.FirstName, userinfo.LastName,
FROM users
WHERE users.Username = $username
INNER JOIN userinfo
ON users.UserID=userinfo.UserID");
?>
Assuming I have the parse data to table coding right below that specific code, what is wrong with the query?
Basically the error I keep getting is error #1064 at line #2 (when I run the query without the php code). Thanks in advance!
<?php
$query = mysql_query("
SELECT users.UserID, users.Username, userinfo.FirstName, userinfo.LastName
FROM users
INNER JOIN userinfo
ON users.UserID=userinfo.UserID
WHERE users.Username = $username
");
?>
Try this
<?php
$query = mysql_query("
SELECT users.UserID, users.Username, userinfo.FirstName, userinfo.LastName,
FROM users
INNER JOIN userinfo
ON users.UserID=userinfo.UserID
WHERE users.Username = $username");
?>
The syntax is -
SELECT col, ...
FROM <tbl_name> AS t1
INNER JOIN <join_tbl_name> AS t2
ON t1.col = t2.col
WHERE <cond>
See the below code. If you print it, you will find where error occurs.
echo $query = mysql_query("SELECT users.UserID, users.Username, userinfo.FirstName, userinfo.LastName FROM users WHERE users.Username = '$username' INNER JOIN userinfo ON users.UserID=userinfo.UserID");
or use
$sql="SELECT users.UserID, users.Username, userinfo.FirstName, userinfo.LastName FROM users WHERE users.Username = '$username' INNER JOIN userinfo ON users.UserID=userinfo.UserID";
if(!mysql_query($sql,$con))
{
echo "Unexpected Error <br/>";;
die (mysql_error());
}
where $con is mysql connection statement.
You have an extra comma at the end of field select. Try removing that part:
$query = "SELECT users.UserID, users.Username, userinfo.FirstName, userinfo.LastName
FROM users
INNER JOIN userinfo
ON users.UserID=userinfo.UserID
WHERE users.Username = $username";
Okay I'm trying to count the amount of people in a clan. I have all the clans sent in a database like this: name(clan name) roomOwner(Owner of clan)
I have a user table like this: username, clan(Owner of Clan)
How could I get all of the people who have the same clan and count that?
I figure it would be something like this but I'm unsure atm
function countMembers($clan) {
include "mysql.ws";
$query = mysql_query("SELECT u.clan AS clan, a.*
FROM
users u
JOIN clans a ON(a.roomOwner = u.clan)
WHERE
u.username = '$clan'");
while($row = mysql_num_rows($query)){
$members = count($row);
return $row;
}
}
This should work:
select clan, count(username) as "# Of Members"
from users
where clan is not null
group by clan