I'm updating some old wordpress plugin files and understand I need to update "mysql_fetch_array" to "$wpdb->get_results" to get the plugin to talk with the database.
Here is the code where "mysql_fetch_array" is used:
//select ads id's stored into db table
$sql = "SELECT id FROM $table_name_ad_google";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
How do I rewrite this to use $wpdb->get_results?
$sql = "SELECT * FROM tbl_employee WHERE 1=1";
$query = $wpdb->get_results($sql,ARRAY_A);
foreach($query as $row){
/*$row["your column name"];*/
}
Related
I am new to PHP coding and just trying to fix some functionality on my site that was left over from the lead developer.
The site, [Vloggi], is a marketplace. So I need to show the name of the job poster in the assignments page . The table I have the jobs in only has the ID, not the name.
So I need a join, but I've tried and it breaks the entire site.
The SQL has 17 tables, I need to display the User Name (usr_name) contained in table 3, the organisation contained in table 7 (usrg_orgname) with the job posting user (vlop_usr_id) details in table 14.
The primary key is users.usr_id, which is linked to users_gor.usrg_usr_id and vlog-ops.vlog_usr_id.
Table 3: users
usr_id, usr_email, usr_password, usr_fbuser, usr_fbtoken, usr_name, usr_loc_name, usr_loc_lat1, usr_loc_lon1, usr_loc_lat2, usr_loc_lon2, usr_status, usr_gor, usr_vgr, usr_token, usr_regtoken,
table 7: users_gor
usrg_usr_id, usrg_creditops, usrg_creditvlog, usrg_creditvlogette, usrg_destination, usrg_orgname, usrg_orgtype, usrg_location, usrg_website, usrg_jobtitle, usrg_phone, usrg_address1, usrg_address2, usrg_state, usrg_postcode, usrg_country
Table 14: vlog-ops
vlop_id, vlop_title, vlop_description, vlop_tags, vlop_deadline, vlop_quantity, vlop_quantityposted, vlop_vser_id, vlop_usr_id,vlop_loc_name, vlop_loc_lat1, vlop_loc_lon1, vlop_loc_lat2, vlop_loc_lon2, vlop_campaign, vlop_rules, vlop_tips, vlop_status
So in main.php i have written the following Sql lookup
in main.php, I have the following SQL lookups:
$sql = "SELECT * FROM users_gor WHERE usrg_usr_id = ".$db->quote($user_info['usr_id'])." LIMIT 1";
$rows = $db->select($sql);
$users_gor = $rows[0];
$sql = "SELECT * FROM users_vgr WHERE usrv_usr_id = ".$db->quote($user_info['usr_id'])." LIMIT 1";
$rows = $db->select($sql);
$users_vgr = $rows[0];
$sql = "SELECT * FROM users WHERE usr_id = ".$db->quote($user_info['usr_id'])." LIMIT 1";
$rows = $db->select($sql);
$users = $rows[0];
$sql = "SELECT * FROM vlog-ops WHERE vlop_usr_id ".$db->quote($user_info['usr_id'])." LIMIT 1";
$rows = $db->select($sql);
$users = $rows[0];
$sql = "SELECT usr_name AS vlop_usr_name FROM users WHERE usr_id = ".$db->quote($user_info['usr_id'])." LIMIT 1";
$rows = $db->select($sql);
$users = $rows[0];
And then in the page template itself, I have written
<?php echo $vlop['vlop_vser_id'] ?>
<?php echo $vlop['vlop_usr_name'] ?>
The first one works, the second doesn’t. What I want eventually is to display the user name and the organisation name in a table.
Whenever I try a JOIN or a NATURAL JOIN or a LEFT JOIN it breaks and the entire site goes blank.
Any help for a newbie would be appreciated with a million thanks.
When you use JOIN you need to specify how you're joining them.
In the query below I'm assuming you're looking for the fields in bold from your question.
$query='SELECT u.usr_name, g.usrg_orgname, v.vlop_usr_id FROM users u
JOIN vlog-ops v on u.usr_id = v.vlop_usr_id
JOIN users_gor g on u.usr_id = g.usrg_usr_id';
I believe I got the name of the fields right but if not just replace them with the correct ones.
Once you have the data fetched, you just loop through the results:
$result = mysqli_query($connection, $query);
while($row = mysqli_fetch_assoc($result)) {
echo 'User name = ' . $row['u.usr_name'];
echo 'Org name = ' . $row['g.usrg_orgname'];
echo 'Job posting user id = ' . $row['v.vlop_usr_id'];
}
How can I make in PHP, that from my SQL baze are written all data, if value parent is not 0 from the same table, it find value from the line, which is the same idas parent.
I check this but I want data from one table.
Similar as below written, but in one query:
$query = "SELECT * FROM posts ORDER BY date DESC;";
$result = $mysqli->query($query);
while($rez = $result->fetch_assoc()) {
$query="SELECT * FROM ".$dbPrefix."posts WHERE
id=".$rez['parent']."";
$parents = $mysqli->query($query);
while($parent = $parents->fetch_assoc()) {
$parentName=$parent['name'];
}
}
How can I make the loop start from latest id to first one?
include 'config.php';
$con->set_charset('utf8');
$sql = "SELECT * FROM tablename";
$names = mysqli_query($con,$sql);
while($row = mysqli_fetch_array ($names)){
//here will make loop start from first id
}
Change your sql variable like this. This should work
$sql = "SELECT * FROM tablename ORDER BY `id` DESC";
In the below script I want to fetch data from mysql using a explode function and also a variable within an explode function.
Here's how I want to get
<?php
include ('config.php');
$track = "1,2,3";
$i = 1
$trackcount = explode(",",$track);
$sql = "SELECT * FROM tracks WHERE id='$trackcount['$i']'";
$retval = mysql_query($sql, $conn);
while ($row = mysql_fetch_array($retval, MYSQL_ASSOC))
{
echo "{$row['track_name']}";
}
mysql_free_result($retval);
?>
This is the code
$sql = "SELECT * FROM tracks WHERE id='$trackcount[$i]'";
I want sql to fetch data from tracks table where id = $trackcount[$i]
Whatever the value of $trackcount[$i] mysql should fetch but it shows a blank screen.
If I put this
$sql = "SELECT * FROM tracks WHERE id='$trackcount[1]'";
It works perfectly
save your $trackcount[$i] in one variable and then pass it in the query as given below
<?php
include ('config.php');
$track = "1,2,3";
$i = 1;
$trackcount = explode(",",$track);
$id=$trackcount[$i];
$sql = "SELECT * FROM tracks WHERE id='$id'";
$retval = mysql_query($sql, $conn);
while ($row = mysql_fetch_array($retval, MYSQL_ASSOC))
{
echo "{$row['track_name']}";
}
mysql_free_result($retval);
?>
and one more thing check your previous code with echo of your query and see what is passing ok.
echo $sql = "SELECT * FROM tracks WHERE id='$trackcount['$i']'";//like this
problem is with your query
$sql = "SELECT * FROM tracks WHERE id='$trackcount['$i']'";//change
to
$sql = "SELECT * FROM tracks WHERE id='$trackcount[$i]'";
Generally you would want to use the IN operator with this type of query, so for you this would be:-
$sql="SELECT * FROM `tracks` WHERE `id` in (".$track.");";
or, if the $ids are in an array,
$sql="SELECT * FROM `tracks` WHERE `id` in (".implode( ',', $array ) .");";
hi
i can rewrite a column's values in a mysql databse based on another columns values, but this time i need to do this with a twist...
there are two tables (and multiple values at once): specifications and products.
products has two columns: specificationids and specificationorderids
specifications has two columns aswell: id and specificationorder
specificationids has multiple values formatted like this: ,31,29,27,18,
these are also the id in the specifications table. each id has a specificationorder value (same row, other column). now what i want to do is, that i want to swap the values of the id with the value of specificationorder and write these to specificationorderids in the products table in the same format.
ofcourse this process has to loop through all the id's in the products table.
i hope i made the problem clear and understandable
thanks for your help!
Swap id and specificationorder, specificationorder writen in specificationorderids if I understand you:
<?php
/* Swap id and specificationorder */
$sql = "SELECT id, specificationorder from specifications";
$result = mysql_query($sql);
while($row = mysql_fetch_row($result))
{
$id = $row[0];
$sporder = $row[1];
$sql = "UPDATE specifications SET id=$id, specificationorder=$sporder WHERE id=$id";
mysql_query($sql);
}
/* specificationorder writen in specificationorderids */
$sql = "SELECT specificationorder from specifications";
$result = mysql_query($sql);
while($row = mysql_fetch_row($result))
{
$sporder = $row[0];
$sql = "INSERT INTO products(specificationorderids) VALUES($sporder)";
mysql_query($sql);
}
?>
for the past couple days i havent been able to come up with a normal code, so heres what ive got so far. ive added comments so you know what i was thinking when experimenting with the code... as in my previous comment i include an image of what i want to achive: img822.imageshack.us/i/specm.png
//get specificationids
$sql = "SELECT specificationids from products";
$result = mysql_query($sql);
$row = mysql_fetch_row($result);
$spids = $row[0];
//get specifications
$sql2 = "SELECT id from specifications";
$result2 = mysql_query($sql2);
$row2 = mysql_fetch_row($result2);
$spid = $row2[0];
//get specificationorder
$sql3 = "SELECT specificationorder from specifications";
$result3 = mysql_query($sql3);
$row3 = mysql_fetch_row($result3);
$sporder = $row3[0];
//if the value of specificationids matches a specificationid, then....
while(VALUES($spids)==$spid)
{
$spids=$sporder; //...it should be replaced by the specificationorder
//and then update the specificationorderids column accordingly
$sql = "UPDATE products(specificationorderids) VALUES($spids)";
mysql_query($sql);
}