How to flush output using Codeigniter 3? - php

Question

I'm writing a CodeIgniter 3 application. My goal is to have a view, which is constantly (as the code goes along) flushed with the output content. I read some answers in stackoverflow, but I am not sure, how to do this.
I have a Controller wich renders the view, in the update method.
<?php
defined('BASEPATH') OR exit('No direct script access allowed!');
class Dataupdate extends MY_Controller {
function __construct() {
parent::__construct();
}
public function index() {
$this->render('dataupdate_list_view');
}
public function update() {
$this->render('dataupdate_update_view');
}
}
?>
Here is the class "MY_Controller".
<?php
defined('BASEPATH') OR exit('No direct script access allowed!');
class MY_Controller extends CI_Controller {
protected $data = array();
function __construct() {
parent::__construct();
$this->data['page_title'] = 'Team Portal';
$this->data['before_head'] = '';
$this->data['before_body'] = '';
}
/**
* Render method is used to render a view using a template.
* The given template delivers the HTML header and footer.
* The view contains the actual page content.
*
* #param string $the_view The view to be rendered
* #param string $template The template to render the view
*/
protected function render($the_view = NULL, $template = 'master') {
if ($template == 'json' || $this->input->is_ajax_request()) {
header('Content-Type: application/json');
echo json_encode($this->data);
} else {
// Get current user from database
$this->load->model('user_model');
$user = $this->user_model->get_record_by_name($_SERVER['REMOTE_USER']);
// Data to pass to view
$this->data['the_view_content'] = (is_null($the_view)) ? '' : $this->load->view($the_view, $this->data, TRUE);
$this->data['user'] = $user;
// Load view with data
$this->load->view('templates/' . $template . '_view', $this->data);
}
}
}
?>
Then I have a view, which outputs the content.
<div>
<!-- PAGE TITLE -->
<div class="page-title">
<h3>Daten Update</h3>
<div class="title_right">
</div>
</div>
<div class="clearfix"></div>
<!-- ALERTS -->
<div class="row">
<div class="col-md-12 col-sm-12 col-xs-12">
<div class="x_panel">
<div class="x_title">
<h2>Fehler<small>Kleiner Text</small></h2>
<div class="clearfix"></div>
</div>
<div class="x_content bs-example-popovers">
<div class="alert alert-danger alert-dismissible fade in" role="alert">
<strong>Strong text.</strong>What to do now?
</div>
</div>
</div>
</div>
</div>
<!-- CONTENT -->
<div class="row">
<div class="col-md-12 col-sm-12 col-xs-12">
<div class="x_panel">
<div class="x_title">
<h2>Neues Daten Update ausführen</h2>
<div class="clearfix"></div>
</div>
<div class="x_content">
<?php echo form_open('dataupdate/update'); ?>
<input type="text" name="test" />
<button>Ausführen</button>
<?php echo form_close(); ?>
</div>
</div>
</div>
</div>
</div>
This works fine. So far.
Now, what I try to achieve is the following:
I click on the "Ausführen" (Execute) button, which submits the form to the same url as this page
Then I want a php script to execute, which continously outputs content to the page. Not all content at once, but adds output after output to the page.
I hope I made myself clear.
Any suggestions or tutorials, on how to do that?

Answer 1

You'll need to force the output by calling ->_display method on the output class
For example for JSON output you'll do something like this:
$response = array('status' => 'OK');
$this->output
->set_status_header(200)
->set_content_type('application/json', 'utf-8')
->set_output(json_encode($response, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE | JSON_UNESCAPED_SLASHES))
->_display();
exit;
Same thing goes when you load a view, if you're 100% sure you won't need anything else, You may call _display manually to get the output; just be sure to call exit after that otherwise you'll end-up with a duplicated output (one from your manual call & the other from the automatic call).
Have a look at the user's guide for output class: http://www.codeigniter.com/user_guide/libraries/output.html