SQL Json Query With Variable - php

Question

I am trying to query SQL database with IMEI variable from android device, the variable is received (verified with log.txt), however whenever I replace '00000000000000' (android virtual device IMEI) with '$androidIMEI' the results are not returned but if I explicitly use the IMEI and not the variable I receive data.
<?php
include 'config.php';
$con=mysql_connect("$servername", "$username", "$password")or die("cannot connect");
mysql_select_db("$dbname")or die("cannot select DB");
$androidIMEI = isset($_POST['IMEI']) ? $_POST['IMEI'] : '';
//$f = fopen("log.txt", "w");
//fwrite($f, print_r($androidIMEI, true));
//fclose($f);
$sql = "SELECT * from users WHERE Request = '0' AND IMEI = '000000000000000' ";
//$sql = "SELECT * from users WHERE Request = '0' AND IMEI = '$androidIMEI ' "; //not working
$result = mysql_query($sql);
$json = array();
if(mysql_num_rows($result)){
while($row=mysql_fetch_assoc($result)){
$json['users'][]=$row;
}
}
mysql_close($con);
echo json_encode($json);
?>
Update: (printing SQL to log file)
$sql = "SELECT * from users WHERE Request = '0' AND IMEI = '$androidIMEI'";
$result = mysql_query($sql);
$f = fopen("log.txt", "w");
fwrite($f, print_r($sql, true));
fclose($f);
Reading Log File:
SELECT * from users WHERE Request = '0' AND IMEI = '000000000000000'
AND THIS IS WHY I HAVE NO IDEA WHY IT IS NOT WORKING
Second Update:
This might be useful, code from android, how I'm sending my IMEI to PHP:
class loadData extends AsyncTask<String, Integer, String> {
private StringBuilder sb;
private ProgressDialog pr;
private HttpResponse req;
private InputStream is;
#Override
protected void onPreExecute() {
super.onPreExecute();
}
#SuppressWarnings("deprecation")
#Override
protected String doInBackground(String... arg0) {
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("IMEI",IMEI));
System.out.println("IMEI: "+IMEI);
try
{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://mysite/myfile.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
InputStreamReader ireader = new InputStreamReader(is);
BufferedReader bf = new BufferedReader(ireader);
sb = new StringBuilder();
String line = null;
while ((line = bf.readLine()) != null) {
sb.append(line);
}
Log.e("pass 1", "connection success ");
}
catch(Exception e)
{
System.out.println("Error catch e");
}
return id;
}

Answer 1

Change
"SELECT * from users WHERE Request = '0' AND IMEI = '$androidIMEI ' " with "SELECT * from users WHERE Request = '0' AND IMEI = '".$androidIMEI."' ".
Also you are vulnerable for SQL injections. Do not use deprecated mysql_* functions and filter your input. More information at How can I prevent SQL injection in PHP?

Answer 2

There is a space after $androidIMEI in your query.
$sql = "SELECT * from users WHERE Request = '0' AND IMEI = '$androidIMEI ' ";
should be
$sql = "SELECT * from users WHERE Request = '0' AND IMEI = '$androidIMEI';";

Answer 3

Try this line
$sql = "SELECT * from users WHERE Request = '0' AND IMEI = '{$android}IMEI'";
I hope it will work.
Just note those curly braces.