avoiding duplicate mysql injection - php

Question

I created a controller and called the function for one time.But it call two times and inserted the value two times.I call the service upload_album in controller.Now value got inserted for two times.one with original value and another with dummy value
Controller
$scope.savealbum = function() {
$scope.album_pids = $routeParams.id;
$timeout(function () {
//console.log($scope.justapp);
for (tt in $scope.justapp) {
if ($scope.justapp[tt].id == $scope.album_pids) {
for (var i = 0; i < $rootScope.media_lib.length; i++) {
}
}
}
$scope.promise=AlbumServices.upload_album($scope.album_pids,$scope.images,$scope.videos);
$scope.promise.then(function(data) {
console.log(data);
alert('Photos Added to Album Successfully');
// $location.path('album_details/' + $routeParams.id);
}, function(reason) {
console.log(reason);
});
}, 1500, false);
};
Service
upload_album: function (alb,img,vid) {
var deferred = $q.defer();
var data = {};
data.pagename = "upload_album";
data.album = alb;
data.photo = img;
data.video = vid;
$http.post('js/data/album.php', data)
.success(function (data, status, headers, config)
{
console.log(status + ' - ' + data);
deferred.resolve(data);
})
.error(function (data, status, headers, config)
{
deferred.reject(data);
console.log('error');
});
return deferred.promise;
}
php
function upload_album ($prefix) {
$postdata = file_get_contents("php://input");
$request = json_decode($postdata);
$sub_id=$request->album;
$val=$request->photo;
$photo = json_encode($val);
$video = json_encode($request->video);
$now = date('Y-m-d H:i:s');
$count_pho = sizeof($photo);
$count_vid = sizeof($video);
$test = '';
if($count_pho != '0' ) {
$test .= "('".$sub_id."','".$content_type."','".$photo."','".$website_id."','".$now."'),";
$demo = substr($test, 0, -1);
$sql="INSERT INTO `album_details` (SUB_ID,CONTENT_TYPE,CONTENT_VALUE,WEBSITE_ID,CreatedTime)VALUES".$demo;
$query = mysql_query($sql) or sqlerrorhandler("(".mysql_errno().") ".mysql_error(), $sql, __LINE__);
}
if ($query) {
echo $msg = true;
} else {
echo $msg = false;
}
}

Answer 1

Because we cannot se the whole code (including the HTML) my suggestions are these:
check your html and/or run method inside angular to be sure that your controller was not instanciated twice
create a unique key pair in your database (it could help not have double records)
create a debouncer when using timeout so that if the timeout is always launched once. something like this:
var t = null;
var mySaveFunction = function () {
if (t) {
clearTimeout(t);
}
t = setTimeout(function () {
/* do saving here */
}, 2000);
};