PHP/ MySQL select box and input - php

Question

I begin to learn PHP because VBA is not enough.
And today I ask you to help.
I have Select box, which takes data from MySQL.
I have Input to which I would like to enter the data from the second column, the same table with that take the data to a select box and do not know how I do it.

Answer 1

If you want to add value from variable to input field you can do next
//$var you get from query from this your mysql table
<input type="text" name="somename" value="<?php echo $var['second_column']; ?>" id="someid">

Answer 2

are you asking for how to put data into a selectbox from database ?? If so, you can use this..
<select name="country">
<option value="">Select</option>
<?php
$countriesQuery=mysqli_query($conn,"SELECT id,name FROM countries");
while($countries=mysqli_fetch_assoc($countriesQuery))
{
echo "<option value='$countries[id]'>$countries[name]</option>";
}
?>
</select>

Answer 3

<select name="country">
<option value="">Select</option>
<?php
$countriesQuery=mysqli_query($conn,"SELECT id,name FROM countries");
while($countries=mysqli_fetch_assoc($countriesQuery))
{
echo "<option value='".$countries[id]."'>".$countries[name]." </option>";
}
?>
</select>

Answer 4

Hope this helps
<?php
$mysqli= new mysqli("localhost", "root", "", "db");
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
$result=$mysqli->query("select name from table");
/* name is your second field*/
?>
<select name="">
<?php
while($res=$result->fetch_array())
{?>
<option value="<?php echo $res[0]; ?>"><?php echo $res[0]; ?></option>
<?php
}
?>
</select>