So currently, I'm making a music database online. The part I'm trying to implement is a playlist function so that given a list of your playlists, you can click one and view the music. What I have is this:
if($result = mysqli_query($link, $playlist))
{
if(mysqli_num_rows($result) > 0)
{
echo "<h1 style='text-align:center;'>Playlists</h1>";
echo "<table style='width:100%'>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . '<a href="getPlaylist.php>' . $row['name']."</td>";
echo "</tr>";
}
echo "</table>";
mysqli_free_result($result);
So I need it so that once someone clicks the link, it will transition them into getPlayList.php and also send over the name in the link, (technically $row['name']) so that I can actually pull up the information in the SQL database. I've tried doing things like:
echo "<td>" . '<a href="getPlaylist.php?link=' . $row["name"]. '">' . $row['name']."</td>";
but to no avail. Can anyone help?
edit:
So what this segment is supposed to do is, it makes a table with each row having a link to a different playlist, but they all go to "getPlaylist.php" where using the name of the link clicked, it will then retrieve all the songs that exist inside it.
edit: solved thanks to RamRaider
I had to use $_GET['link'] in getPlaylist.php
Related
I'm trying to create a button for each row in my database that, when pressed, will delete this particular row. I should also mention that the data from the database is displayed correctly and the table I'm using is also completely fine.The buttons appear at the side of each row, when the button is clicked, the row dissapears but the data is not deleted from the database, when the page is reloaded the rows that were previously "deleted", reappear. After pressing the button i also get this "Fatal error: Uncaught Error: Call to undefined function mysql_query() in C:\xampp\htdocs\INDUSTRIALPROJECT\records.php:56 Stack trace: #0 {main} thrown in C:\xampp\htdocs\INDUSTRIALPROJECT\records.php on line 56".
line 56 is : $del = mysql_query("DELETE FROM records WHERE id=" . $row['id']);. The same query works fine when placed directly into phpMyAdmin.
<?php
// Check connection
include_once 'config.php';
if ($link->connect_error) {
die("Connection failed: " . $link->connect_error);
}
$sql = "SELECT * FROM records";
$result = $link->query($sql);
function post($key){ return(isset($_POST[$key]) ? htmlspecialchars($_POST[$key]) : ""); }
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
if(post('rowButton'.$row['id']) =="Delete"){
$del = mysql_query("DELETE FROM records WHERE id=" . $row['id']);
$deleted = '<p>Entry ' . $row['id'] . ' was succesfully deleted</p>';
}
else {
echo '<form action ="' . $_SERVER['PHP_SELF'] . '" method="post">';
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row["visitingdate"]. "</td>";
echo "<td>" . $row["department"] . "</td>";
echo "<td>" . $row["visitingreason"]. "</td>";
echo "<td>" . $row["importance"]. "</td>";
echo "<td>" . $row["visitorname"]. "</td>";
echo "<td>" . $row["company"]. "</td>";
echo "<td>". $row["internalrecipientname"]. "</td>";
echo "<td>". $row["visitinglocation"]. "</td>";
echo "<td>". $row["ETA"]. "</td>";
echo "<td>". $row["ETD"]. "</td>";
echo "<td>". $row["HRverification"]. "</td>";
echo "<td>". $row["visitcompleted"]. "</td>";
echo '<td><input type="submit" name="rowButton'. $row['id'] .'" value="Delete"/> </td>';
echo "</tr>";
echo "</form>";
}
}
echo "</table>";
echo $deleted;
}
else { echo "0 results"; }
$link->close();
?>
First, this appears to be rather vulnerable to SQL injection attacks. StackOverflow is quite font of pointing this out up front, because it's really a solved problem that you should account for in the early stages of development. You're taking untrusted data (that was submitted by the user, without sanitizing it) and putting it directly in an SQL query. Bad things can happen when that occurs. Now with that aside, on to your actual question.
"Nothing happens" means the page doesn't change at all, right? So the browser doesn't know what to do when the button is clicked.
I think you haven't put any <form...> declaration here, which would be required for <input type="submit"> to do anything useful. You could use JavaScript with the stand alone submit button, but I don't see that in your code, either. You'll need something to tell the browser what to do when the submit button is pressed.
I haven't really tested the rest of your code, but based on what you've got already you might add the following:
else {
+ echo '<form action ="' . $_SERVER['PHP_SELF'] . '" method="post">';
echo "<tr>";
and
echo "</tr>";
+ echo "</form>";
}
(don't add the plus sign, that's just to show which line is added). I should add that I don't usually use submit buttons like this, so there's a chance I missed some additional details about how you're calling this, but putting the form in a <form> tag is at least a good start.
Edit
The mysql_query() function was removed in PHP 7; if you're using an older PHP you need to add support for the MySQL functions or if you're on PHP 7, you should use the MySQLi or PDO_MySQL functions instead. The warning box on the PHP manual page for mysql_query has some links for alternatives, how to select an alternative, and other supporting documentation that may help you. This StackOverflow answer may help, as well.
I have this piece of code below. It displays the image and name of all the entries in a table in my database. The name is set up to become a hyperlink.Is it possible to make it so when one specific name is clicked that data for only that specific name will be displayed on the page you are sent to?
So for example if I select the first entry that is displayed back "mealname1" and it takes me to the showrecipe.php page, can I make it so I can display all the data I have for "mealname1" and only "mealname1". I'm really lost, I have scoured the internet and my php books but can't find anything to that is relevant.
If there is no way of doing it is there an obvious solution that I am missing?... I am very much a novice to this... thanks for your help guys.
<?php
require("db.php");
$prodcatsql = "SELECT * FROM recipes";
$prodcatres = mysql_query($prodcatsql);
$numrows = mysql_num_rows($prodcatres);
if($numrows == 0)
{
echo "<h1>No Products</h1>";
echo "There are no recipes available right now.";
}
else
{
echo "<table id='recipetable'>";
while($prodrow = mysql_fetch_assoc($prodcatres))
{
echo "<tr>";
if(empty($prodrow['image'])){
echo "<td><img
src='./images/No_image.png' alt='"
. $prodrow['mealname'] . "'></td>";
}
else {
echo "<td><img src='./images/".$prodrow['image']
. "' alt='"
. $prodrow['mealname'] . "'></td>";
}
echo "<td>";
echo ''.$prodrow['mealname'].'';
echo "</td>";
echo "</tr>";
}
echo "</table>";
}
?>
Change the query to
SELECT * FROM recipes WHERE mealname='$mealname' LIMIT 1;
You can remove "LIMIT 1" if you want but this makes sure you will only get 1 or 0 row back. Don't forget to escape the string.
I have a show results page dumping the contents of a table. I've managed to echo in an edit link on each of my table rows. Edit kicks user to an update records page.
I'm trying to include the variables from the table row to the edit URL so I can do a $_GET URL param function on the update page and propagate the update form.
Here's what I have at the moment:
echo "<table>";
/* Get field information for all fields */
while ($row = mysqli_fetch_object($queryResult))
{
echo "<tr>";
echo "<td>" . $row->band_name . "</td><td>" . $row->votes . "</td><td><a href='vote.html?$band_name&$votes'>Edit</a></td>";
echo "</tr>";
}
First off, make sure that you declare your variables properly. It seems these guys are undefined in your url:
$band_name&$votes
Then format your url properly:
while ($row = mysqli_fetch_object($queryResult))
{
$band_name = $row->band_name;
$votes = $row->votes;
echo "<tr>";
echo "
<td>$band_name</td>
<td>$votes</td>
<td>
<a href='vote.html?band_name=".urlencode($band_name)."&votes=$votes'>Edit</a>
</td>";
echo "</tr>";
}
Are you sure its <a href='vote.html? HTML? you won't be able to parse this properly. Change it to vote.php
Then in vote.php, just get those values thru $_GET:
<?php
if(isset($_GET['band_name'], $_GET['votes'])) {
$band_name = $_GET['band_name'];
$votes = $_GET['votes'];
// rest of code mysqli etc. etc.
}
?>
You're not very clear on exactly what is not working, but in order for PHP to be able to get the query params they have to have a name.
if you change the following line and add parameter names, you should be able to access the data with $_GET or parse_str.
echo "<td>" . $row->band_name . "</td><td>" . $row->votes . "</td><td><a href='vote.html?band_name=$band_name&votes=$votes'>Edit</a></td>";
Currently I have a query running that brings up all the contents of the 'products' table and the 'user' associated with the products. It prints on a table. I want to create a button, that brings up the entire records.
Please note that I must only be able to view the selected record only.. How would I go about this?
echo "<table border='1'>
<tr>
<th>user_id</th>
<th>user_name</th>
<th>selected_product</th>
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
echo "<td>" . $row['user_id'] . "</td>";
echo "<td>" . $row['user_name'] . "</td>";
echo "<td>" . $row['selected_product'] . "</td>";
So a button should appear for each record that is returned as a result. When I click this button another window should appear which shows the entire contents (for this record only) and the user associated.
How does the button know which record its associated with.
<a href="anotherpage.php?id=<?php echo $row['user_id']?>" ><button>View Details</button></a>
This will take you to another page.
Use get method tho get the id into php variable.
$userId = $_GET['id'];
And now use sql query to fetch all the data from the database for single user.
$userResult = mysql_query("SELECT * FROM userTable WHERE user_id = ".$userId);
I have a table with arrays pulling information from a database, I have linked the fix to be a hyperlink "click me for fix" I have entered the link to send the variable to a php that will use $GET to echoe the information.
code below , i am new to php and been racking brains . the only out put i get is Welcome . (done welcome to test if information was being passed)
<div id=list>
<?php
// Create connection
$con=mysqli_connect('172.16.254.111',"user","password","Faults"); //(connection location , username to sql, password to sql, name of db)
// Check connection
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
//where statement in the sql syntax will select where in db to get infor, use AND to add another condition
$result = mysqli_query($con,"SELECT * FROM Fixes WHERE Product='Serv1U' AND Fault_type='Broadcast Manager'"); //this creates a variable that selects the database
//below is the echo statment to create the results in a table format, list collumn titles
echo "<table id=tables border='1'>
<tr>
<th>Products</th>
<th>Fault_type</th>
<th>Fault_Description</th>
<th>Fix</th>
</tr>";
//below is script to list reults in a table format, $row [row name on table]
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['Product'] . "</td>";
echo "<td>" . $row['Fault_type'] . "</td>";
echo "<td>" . $row['Fault_Description'] . "</td>";
echo "<td>Click for Fix</td>"; //this is how you link into an echo, alsothe id=" hopefully means i can send ID information.
}
echo "</tr>";
echo "</table>";
// below closes the coonection to mysql
mysqli_close($con);
index.php:
Welcome <?php echo $_GET["Fix"]; ?>.
I'm lost. Any help is appreciated.
Thanks
?>
Is it just a typo here? $GET must be $_GET.
And it should be $row['Fix'] not $rows['Fix']! Note the 's'!