Regular Expression with php Error [duplicate] - php

Question

This question already has answers here:
Extract HTML attributes in PHP with regex [duplicate]
(2 answers)
Closed 7 years ago.
i have the following html structure :
<div data-provincia="mi" data-nazione="it" ecc...
I'm trying to take "mi" with preg_match function.
This is my code :
$pattern = '/data-provincia=*"[a-zA-Z]*"/';
preg_match($pattern,$element,$provincia);
I think that the code is right but it doesn't match with anything.
Where i'm wrong?
Thanks.

Answer 1

You might want to use the quantifier + (1 or more) next to the character class between brackets, and remove the first star. Also added a subtpattern for you to get exactly the part you want. Give it a try :
$pattern = '/data-provincia="([a-zA-Z]+)"/';
preg_match($pattern,$element,$provincia);
echo $provincia[1];

Answer 2

$element = '<div data-provincia="mi" data-nazione="it" ecc...>';
$pattern = '/<div[^>]*data-provincia=\"([^\"]+)\"[^>]*>/';
preg_match($pattern,$element,$provincia);
print_r($provincia[1]);

Answer 3

In addition to my comment, for this simple attribute you can use the following regex:
$regex = '/data-provincia="([^"]*)/i';
preg_match($regex,$element,$matches);
echo $matches[1];
Basically match everything except a double quote as many times as possible (or none). But please at least consider using a Parser for this task, regular expressions were not meant to deal with it.

Answer 4

Its working fine for me
$element = '<div data-provincia="mi" data-nazione="it"></div>';
$pattern = '/data-provincia=*"[a-zA-Z]*"/';
$matches= array();
preg_match($pattern,$element, $matches);
if (!empty($matches)) {
foreach ($matches as $eachOne) {
//code to remove unwanted
$text = trim(preg_replace('/^data-provincia\=/', '', $eachOne), '""');
echo " $eachOne; $text";
}
}