There is a problem regarding selenium PHPUnit.
PHPUnit version: 3.7.21
OS: Windows7
Selenium Server: selenium-server-standalone-2.48.2
I am getting a very weird situation, that I have a text present on the page, and using assertTextPresent() function on that page only. But it continuously fail.
Earlier I thought, may be it because of page not loaded properly. So I just use pause() for page to load. And now I am able to see the text on page.
I also captured the screenshot, In that screenshot I am also able to see that pattern.
But there is something wrong, that this function is not able to find text in the page.
Any help will be appreciated.
Thanks.
Can you give a more specific example of what steps you're performing and what parameters you're using? Anyway, you could wait for an element to be present on the page like this:
for ($second = 0; ; $second++) {
if ($second >= 30) $this->fail("Element not found");
try {
if ($value == $this->getText("$locator")) break;
} catch (Exception $e) {}
sleep(1);
}
where $value is the text you're looking for and $locator is the path where you expect to find the text. OR (if you don't care about where the text needs to be):
for ($second = 0; ; $second++) {
if ($second >= 30) $this->fail("\n Text not found");
try {
if ($this->isTextPresent("$value")) break;
}
catch (Exception $e) {
}
sleep(1);
}
You can use this code as a workaround
$txt = $this->byXPath("insert-xpath-of-text-here")->text();
$this->assertTrue($txt,"text-to-be-found","some-random-error-message-here");
or
$this->assertTrue($this->byXPath("insert-xpath-of-text-here")->text(),"text-to-be-found","some-random-error-message-here");
I figured that indicating the locator of the text to be found might solve the issue
$this->waitForPageLoad(1000);
You are using this method
assertElementExistsWithText_W();
Related
I was made a mistake yesterday and spent hours to fix it. I have method like this
{
if (isset($data['y'])) {
$this->y = $data['y'];
}
if (isset($data['z'])) {
$this->y = $data['z']; // <- error here
}
}
And yes, I assign $this->y two times instead of one y and one z :-(
So question: can any static analyze tools catch such errors? I have PHP Storm and Rector, PHPStan, PHP CS Fixer in my CI toolchain but they missed this error.
This isn't so much an answer, but it's too complicated to put in a comment.
As the comments pointed out, there's simply no way for a robot to figure out that what you wrote isn't what you intended. The easiest solution is to live with human frailty and debug your code.
But that doesn't mean you can't write your code to better express your intent. Consider:
{
$fields = ['x', 'y'];
foreach ($fields as $field) {
if (isset($data[$field]) {
$this->$field = $data[$field];
}
}
}
Now you have expressed in you code that you only want to assign like-named fields.
I am using this library (PHP Simple HTML DOM parser) to parse a link, here's the code:
function getSemanticRelevantKeywords($keyword){
$results = array();
$html = file_get_html("http://www.semager.de/api/keyword.php?q=". urlencode($keyword) ."&lang=de&out=html&count=2&threshold=");
foreach($html->find('span') as $e){
$results[] = $e->plaintext;
}
return $results;
}
but I am getting this error when I output the results:
Fatal error: Call to a member function find() on a non-object in
/var/www/vhosts/efamous.de/subdomains/sandbox/httpdocs/getNewTrusts.php
on line 25
(line 25 is the foreach loop), the odd thing is that it outputs everything (at least seemingly) correctly but I still get that error and can't figure out why.
The reason for this error is: the simple HTML DOM does not return the object if the size of the response from url is greater than 600000.
You can void it by changing the simple_html_dom.php file. Remove strlen($contents) > MAX_FILE_SIZE from the if condition of the file_get_html function.
This will solve your issue.
You just need to increase CONSTANT MAX_FILE_SIZE in file simple_html_dom.php.
For example:
define('MAX_FILE_SIZE', 999999999999999);
This error usually means that $html isn't an object.
It's odd that you say this seems to work. What happens if you output $html?
I'd imagine that the url isn't available and that $html is null.
Edit:
Looks like this may be an error in the parser. Someone has submitted a bug and added a check in his code as a workaround.
Before file_get_html/load_file method, you should first check if URL exists or not.
If the URL exists, you pass one step.
(Some servers, service a 404 page a valid HTML page. which has propriate HTML page structure like body, head, etc. But it has only text "This page couldn'!t find. 404 error bla bla..)
If URL is 200-OK, then you should check whether fetched thing is object and whether nodes are set.
That's the code i used in my pages.
function url_exists($url){
if ((strpos($url, "http")) === false) $url = "http://" . $url;
$headers = #get_headers($url);
// print_r($headers);
if (is_array($headers)){
if(strpos($headers[0], '404 Not Found'))
return false;
else
return true;
}
else
return false;
}
$pageAddress='http://www.google.com';
if ( url_exists($pageAddress) ) {
$htmlPage->load_file( $pageAddress );
} else {
echo 'url doesn t exist, i stop';
return;
}
if( $htmlPage && is_object($htmlPage) && isset($htmlPage->nodes) )
{
// do your work here...
} else {
echo 'fetched page is not ok, i stop';
return;
}
For those arriving here via a search engine (as I did), after reading the info (and linked bug-report) above, I started some code-prodding and ended up fixing my problems with 2 extra checks after loading the dom;
$html = file_get_html('<your url here>');
// first check if $html->find exists
if (method_exists($html,"find")) {
// then check if the html element exists to avoid trying to parse non-html
if ($html->find('html')) {
// and only then start searching (and manipulating) the dom
}
}
I'm having the same error come up in my logs and apart from the solutions mentioned above, it could also be that there is no 'span' in the document. I get the same error when searching for divs with a particular class that doesn't exist on the page, but when searching for something that I know exists on the page, the error doesn't pop up.
your script is OK.
I receive this error when it doase not find the element that i'm looking for on that page.
In your case, please check if the page that you are accessing it has 'SPAN' element
Simplest solution to this problem
if ($html = file_get_html("http://www.semager.de/api/keyword.php?q=". urlencode($keyword) ."&lang=de&out=html&count=2&threshold=") {
} else {
// do something else because couldn't find html
}
Error means, the find() function is either not defined yet or not available. Make sure you have loaded or include related function.
I have this ldap entry:
cn=blah,ou=apples,ou=people,dc=yay,dc=edu
I need to move that entry to:
cn=blah,ou=oranges,ou=people,dc=yay,dc=edu
My scripts are all PHP so I've been trying to use php.net/ldap_rename
ldap_rename($connection, "cn=blah,ou=apples,ou=people,dc=yay,dc=edu", "cn=blah", "ou=oranges,ou=people,dc=yay,dc=edu", true);
Does not work. It returns false.
This http://us2.php.net/manual/en/function.ldap-rename.php#82393 comment mentions that eDirectory wants to leave the parent as NULL. Like:
ldap_rename($connection, "cn=blah,ou=apples,ou=people,dc=yay,dc=edu", "cn=blah", NULL, true);
That returns TRUE but does not actually move the entry. Not surprising since it's not changing the parent... I'm sure it could change the cn=blah to something else...
I have thought of deleting the entry and recreating it. But that's a painful way to go about it. Writing out and running a LDIF file would also be painful.
So, how do I move an entry from one OU to another, in php, without the pain of my other two options?
What I'm running:
Ubuntu 12.04 LTS
PHP 5.3.10
eDirectory 8.8 is on SLES 11
Edit
So, I found this:
The modrdn change type cannot move an entry to a completely different subtree. To move an entry to a completely different branch, you must create a new entry in the alternative subtree using the old entry's attributes, and then delete the old entry.
From http://www.centos.org/docs/5/html/CDS/ag/8.0/Creating_Directory_Entries-LDIF_Update_Statements.html
I found a couple other pages with similar statements.
So it sounds like I have to make a new entry, copying the attributes, the delete the old one. Like the second painful option I mentioned above.
Well, I ended up using the "create new entry, delete old one" method. I still think I had another way working a while back, but I can't remember what. So here's a basic move function.
function move($connection, $ldapEntryReference, $new_dn){
//First, get the values of the current attributes.
$attributes = array(); //start attributes array
$firstattr = ldap_first_attribute($connection, $ldapEntryReference);
$value = ldap_get_values($connection, $ldapEntryReference, $firstattr);
$attributes[$firstattr] = $value;
while($attr = ldap_next_attribute($connection, $ldapEntryReference)) {
if (strcasecmp($attr, 'ACL') !== 0) { //We don't want ACL attributes since
//eDir/ldap should deal with them for us.
if (strcasecmp($attr, 'jpegPhoto') === 0) {
//binary values need to use the ldap_get_values_len function.
$value = ldap_get_values_len($this->connection, $ldapEntryReference, $attr);
} else {
$value = ldap_get_values($this->connection, $ldapEntryReference, $attr);
}
$attributes[$attr] = $value;
}
}
//Create a new entry array with the values.
$entry = array(); //start entry array.
foreach($attributes as $key => $value) {
foreach($value as $key2 => $value2) {
if (strcasecmp($key2, 'count') !== 0) {//get rid of 'count' indexes
//ldap_add chokes on them.
$entry[$key][$key2] = $value2;
}
}
}
//Add the new entry.
if (ldap_add($connection, $new_dn, $entry)) {
//Delete the old entry.
if (ldap_delete($connection, ldap_get_dn($connection, $ldapEntryReference)) {
return true;
} else {
return false;
}
} else {
return false;
}
}
Hopefully this helps someone, sometime.
There actually isn't a need to recreate in eDir. Doing a recreate causes problems in an environment that runs IDM as the object will have a new GUID and the IDM engine will not see the event as a true "move".
The following code moves users fine (tested eDir 8.8.x & eDir 9.x):
$olduserdn = "cn=userid,ou=container1,o=org";
$newdestdn = "ou=container2,o=org";
if (preg_match('/^(cn=[A-Za-z0-9]+)\,(.+)/i', $olduserdn, $rdnmatches))
{
if (ldap_rename($ldapconn, $olduserdn, $rdnmatches[1], $newdestdn, TRUE))
{
print("Moved $olduserdn to $rdnmatches[1],$newdestdn");
}
else
{
print("Failed move because " . ldap_error($ldapconn));
}
}
Don't forget to give a bit of time for replication...
Also consider constraints around modifying/moving objects that are still being replicated from a previous move event.
Try this:
ldap_rename($ldapconn, "cn=blah,ou=apples,ou=people,dc=yay,dc=edu", "cn=blah", "ou=oranges,ou=people,dc=yay,dc=edu", true);
I am quite new to programming, when I develop my program I use a simple strategy to debug it: I write the program to print along the debugging messages as it operate the significant statements, for example
function foo1($number)
{
//foo_print("I am function foo1({$number}). <br/>");
//foo_print("I am going to increase 'count' by {$number}. <br/>");
$GLOBALS["count"] = $GLOBALS["count'] + $number;
//foo_print("Now 'count' = {$GLOBALS["count"]}, I finished my task, BYE BYE. <br/>");
}
function isFoo($number)
{
//foo_print("I am function isFoo({$number}). <br/>");
//foo_print("I am checking if the number < 3 or not, if so, it is Foo, if not, it is not Foo. <br/>");
if($number <= 3)
{
//foo_print("Found that number = {$number} <= 3, I return true, BYE BYE. <br/>");
return true;
}
//foo_print("Found that number = {$number} > 3, I return false, BYE BYE. <br/>");
return false;
}
I call them debugging messages but, as you see, they're actually the thoroughly comments describing what does the program do on each line. I just write the function foo_print() to print them out when I am debugging the program. And comment them out in real use.
Instead of inserting and removing the comment sign '//' line by line in and out when switch between real run mode and debugging mode, I have the function foo_print to do the work: It can be set to turn on or off.
define(FOO_PRINT, 1)
function foo_print($message)
{
if(FOO_PRINT) print $message;
// if FOO_PRINT == 0 then do nothing.
}
But I think this method is ineffective, it has to check FOO_PRINT every time before printing a message.
My question is either or both of the following
Can I do something to tell php to ignore my foo_print() function when I don't want to use it?
Perhaps, instead of using foo_print function, I should write the messages in plain comment style using '//' sign and then tell php interpreter to print those comment messages when in debugging mode. Can I do that?
I think, other than debugging ease, this method will be of advantage that it can help me understand the program when I come back to see it in later days. (It very long and complicated for me that I believe I will forget it soon.)
I found it very complicated for me now to use advanced IDEs and debugging tools to develop my program. I believe some of these advanced debugging tools can do something similar to what I want, but I've tried on PHP-eclipse and xdebug for a week and it got me nowhere. thank you very much.
You could define two functions, one of which outputs the debug data and the other one doesn't. Then use a variable name to contain the name of the function you want to call and do your debugging by calling the function in the variable. Like this:
function debug_print($data) {
echo $data;
}
function debug_none($data) {
}
$debug = 'debug_print';
$debug('Testing one'); // This prints out 'Testing one'
$debug = 'debug_none';
$debug('Testing two'); // This doesn't print out anything
If you do this, don't forget to add global $debug to any functions that want to use the function.
EDIT: There is also a more object oriented way to achieve the same result. You could define an interface and write a couple of implementations for it, allowing you to choose which one to use at runtime.
$debugmode = true;
interface Debugger {
public function out($data);
}
class EchoDebugger implements Debugger {
public function out($data) {
echo $data;
}
}
class NullDebugger implements Debugger {
public function out($data) {
// Do nothing
}
}
if($debugmode)
$debugger = new EchoDebugger();
else
$debugger = new NullDebugger();
$debugger->out('This will be output if $debugmode is true');
No bud,
there is no such thing possible, and you have to define a condition every time.
This cannot be done in code of php
Is there any command in PHP to stop executing the current or parent if statement, same as break or break(1) for switch/loop. For example
$arr=array('a','b');
foreach($arr as $val)
{
break;
echo "test";
}
echo "finish";
in the above code PHP will not do echo "test"; and will go to echo "finish";
I need this for if
$a="test";
if("test"==$a)
{
break;
echo "yes"; // I don't want this line or lines after to be executed, without using another if
}
echo "finish";
I want to break the if statement above and stop executing echo "yes"; or such code which is no longer necessary to be executed, there may be or may not be an additional condition, is there way to do this?
Update: Just 2 years after posting this question, I grew up, I learnt how code can be written in small chunks, why nested if's can be a code smell and how to avoid such problems in the first place by writing manageable, small functions.
Sometimes, when developing these "fancy" things are required. If we can break an if, a lot of nested ifs won't be necessary, making the code much more clean and aesthetic.
This sample code illustrates that in certain situations a breaked if can be much more suitable than a lot of ugly nested ifs.
Ugly code
if(process_x()) {
/* do a lot of other things */
if(process_y()) {
/* do a lot of other things */
if(process_z()) {
/* do a lot of other things */
/* SUCCESS */
}
else {
clean_all_processes();
}
}
else {
clean_all_processes();
}
}
else {
clean_all_processes();
}
Good looking code
do {
if( !process_x() )
{ clean_all_processes(); break; }
/* do a lot of other things */
if( !process_y() )
{ clean_all_processes(); break; }
/* do a lot of other things */
if( !process_z() )
{ clean_all_processes(); break; }
/* do a lot of other things */
/* SUCCESS */
} while (0);
As #NiematojakTomasz says, the use of goto is an alternative, the bad thing about this is you always need to define the label (point target).
Encapsulate your code in a function. You can stop executing a function with return at any time.
proper way to do this :
try{
if( !process_x() ){
throw new Exception('process_x failed');
}
/* do a lot of other things */
if( !process_y() ){
throw new Exception('process_y failed');
}
/* do a lot of other things */
if( !process_z() ){
throw new Exception('process_z failed');
}
/* do a lot of other things */
/* SUCCESS */
}catch(Exception $ex){
clean_all_processes();
}
After reading some of the comments, I realized that exception handling doesn't always makes sense for normal flow control. For normal control flow it is better to use "If else":
try{
if( process_x() && process_y() && process_z() ) {
// all processes successful
// do something
} else {
//one of the processes failed
clean_all_processes();
}
}catch(Exception ex){
// one of the processes raised an exception
clean_all_processes();
}
You can also save the process return values in variables and then check in the failure/exception blocks which process has failed.
Because you can break out of a do/while loop, let us "do" one round. With a while(false) at the end, the condition is never true and will not repeat, again.
do
{
$subjectText = trim(filter_input(INPUT_POST, 'subject'));
if(!$subjectText)
{
$smallInfo = 'Please give a subject.';
break;
}
$messageText = trim(filter_input(INPUT_POST, 'message'));
if(!$messageText)
{
$smallInfo = 'Please supply a message.';
break;
}
} while(false);
goto:
The goto operator can be used to jump to another section in the program. The target point is specified by a label followed by a colon, and the instruction is given as goto followed by the desired target label. This is not a full unrestricted goto. The target label must be within the same file and context, meaning that you cannot jump out of a function or method, nor can you jump into one. You also cannot jump into any sort of loop or switch structure. You may jump out of these, and a common use is to use a goto in place of a multi-level break...
There exist command: goto
if(smth) {
.....
.....
.....
.....
.....
goto My123;
.....
.....
}
My123:
....your code here....
BUT REMEMBER! goto should not be ever used anywhere in real-world scripts, as it is a sign of poor code.
You could use a do-while(false):
<?php
do if ($foo)
{
// Do something first...
// Shall we continue with this block, or exit now?
if ($abort_if_block) break;
// Continue doing something...
} while (false);
?>
as described in http://php.net/manual/en/control-structures.if.php#90073
No, there is no way to "break" an if block like you would inside loops.:(
So turn your test into a switch !
I wonder why nobody encouraged you to use switch statement since (even if you haven't to many test cases)
Do you think it's too verbose?
I would definitely go for it here
switch($a){
case 'test':
# do stuff here ...
if(/* Reason why you may break */){
break; # this will prevent executing "echo 'yes';" statement
}
echo 'yes'; # ...
break; # As one may already know, we might always have to break at the end of case to prevent executing following cases instructions.
# default:
# something else here ..
# break;
}
To me Exceptions are meant to raise errors and not really to control execution flaw.
If the break behaviour you are trying to set is not about unexpected error(s), Exception handling is not the right solution here :/.
$a = 1;
switch($a) {
case "1":
if ($condition1){
break;
}
if ($condition2){
break;
}
if ($condition3){
break;
}
}
In this way I got what I want. I use a switch only has a definite case and then use break in case to choose if condition. The reason why I use the break : condition1 and condition2 may both satisfy, in that situation only condition1 is applied .IF is selective according the order.
I had the same problem. A solution is to pile if.
The first example is simplistic but...
$a="test";
if("test"==$a)
{
do something
//break; We remove from your example
if(comparison) {
echo "yes";
}
}
echo "finish";
Or, you can use goto.
$a="test";
if("test"==$a)
{
do something
goto the_end_of_your_func;
echo "yes";
}
the_end_of_your_func:
echo "finish";
No.
But how about:
$a="test";
if("test"==$a)
{
if ($someOtherCondition)
{
echo "yes";
}
}
echo "finish";
Just move the code that is not supposed to be executed to else/elseif branch. I don't really see why would you want to do what you're trying to do.
The simple answer is that no, there isn't a way to break from an if statement without completely stopping the execution (via exit). Other solutions won't work for me because I can't change the structure of the if statement, since I'm injecting code into a plugin, like so:
if ( condition ) {
// Code and variables I want to use
// Code I have control over
// Code I don't want to run
}
// More code I want to use
Answering to your question whether that is achievable or not, then yes that is achievable using "goto" operator of php.
But ethically, its not a good practice to use "goto" and of there is any need to use goto then this means that code need to be reconstructed such that requirement of goto can be removed.
According to the sample code you posted above, it can be clearly seen that the code can be reconstructed and the code that is no more required can be either deleted or commented (if possibility is there for use in future).
$arr=array('test','go for it');
$a='test';
foreach($arr as $val){
$output = 'test';
if($val === $a) $output = "";
echo $output;
}
echo "finish";
combining your statements, i think this would give you your wished result.
clean and simple, without having too much statements.
for the ugly and good looking code, my recomandation would be:
function myfunction(){
if( !process_x() || !process_y() || !process_z()) {
clean_all_processes();
return;
}
/*do all the stuff you need to do*/
}
somewhere in your normal code
myfunction();
i have a simple solution without lot of changes.
the initial statement is
I want to break the if statement above and stop executing echo "yes"; or such code which is no longer necessary to be executed, there may be or may not be an additional condition, is there way to do this?
So it seems simple. try code like this:
$a="test";
if("test"==$a)
{
if (1==0){
echo "yes"; // this line while never be executed.
// and can be reexecuted simply by changing if (1==0) to if (1==1)
}
}
echo "finish";
if you want to try without this code, it's simple. and you can back when you want. another solution is comment blocks.
or simply thinking and try in another separated code and copy paste only the result in your final code.
and if a code is no longer nescessary, in your case, the result can be
$a="test";
echo "finish";
with this code, the original statement is completely respected
and more readable!
The simple solution is to comment it out.
$a="test";
if("test"==$a)
{
//echo "yes"; //no longer needed - 7/7/2014 - updateded bla bla to do foo
}
The added benefit is your not changing your original code and you can date it, initial it and put a reason why.
What about using ternary operator?
<?php
// Example usage for: Ternary Operator
$action = (empty($_POST['action'])) ? 'default' : $_POST['action'];
?>
Which is identical to this if/else statement:
<?php
if (empty($_POST['action'])) {
$action = 'default';
} else {
$action = $_POST['action'];
}
?>
To completely stop the rest of the script from running you can just do
exit; //In place of break. The rest of the code will not execute
I'm late to the party but I wanted to contribute. I'm surprised that nobody suggested exit(). It's good for testing. I use it all the time and works like charm.
$a ='';
$b ='';
if($a == $b){
echo 'Clark Kent is Superman';
exit();
echo 'Clark Kent was never Superman';
}
The code will stop at exit() and everything after will not run.
Result
Clark Kent is Superman
It works with foreach() and while() as well. It works anywhere you place it really.
foreach($arr as $val)
{
exit();
echo "test";
}
echo "finish";
Result
nothing gets printed here.
Use it with a forloop()
for ($x = 2; $x < 12; $x++) {
echo "Gru has $x minions <br>";
if($x == 4){
exit();
}
}
Result
Gru has 2 minions
Gru has 3 minions
Gru has 4 minions
In a normal case scenario
$a ='Make hot chocolate great again!';
echo $a;
exit();
$b = 'I eat chocolate and make Charlie at the Factory pay for it.';
Result
Make hot chocolate great again!
$a="test";
if("test"!=$a)
{
echo "yes";
}
else
{
echo "finish";
}