PHP $_GET content in <div> - php

first of all i'm new here so if I do mistakes pls let me know^^"
I try to get the content of a div element with php $_POST and I dont really know how to do it. I use MVC patter if that matters.
My div is editable and the answer box to write something on the page.
<form action="index.php?page=addPost&topic_id={TOPIC_ID}" method="post">
<div id="editor" name="editor">
Lorem Ipsum...
</div>
<input type="submit" name="submit" value="senden" >
</form>
I can't just use a textarea but I would like to get everything between the div element with something like
$text = $_POST['editor'];
is that possible?

You could use a hidden textarea, and add the contents of the div to the textarea on form submit:
<form action="index.php?page=addPost&topic_id={TOPIC_ID}" method="post" onsubmit="getEditorContents(this);">
<div id="editor">
Lorem Ipsum...
</div>
<textarea style="display:none;" name="editor"><!-- --></textarea>
<input type="submit" name="submit" value="senden" >
</form>
<script>
function getEditorContents(form){
var html = document.getElementById("editor").innerHTML;
form.editor.value = html;
return true;
}
</script>

Use ajax or just use a textarea form element
<form id="data" method="post" enctype="multipart/form-data">
<div id="editor" name="editor">
Lorem Ipsum...
</div>
<input type="submit" name="submit" value="senden" >
<input type="hidden" id="topicId" value="{TOPIC_ID}" >
</form>
<script>
$(document).ready(function(){
$("form#data").submit(function(){
var formData = new FormData($(this)[0]);
formData.append('editor', $('#editor').html());
$.ajax({
url: 'index.php?page=addPost&topic_id='+$('$topicId').val(),
type: 'POST',
data: formData,
async: false,
success: function (data) {
alert(data);
location.reload();
},
cache: false,
contentType: false,
processData: false
});
return false;
});
});
</script>

Here is how you can proceed with:
<script>
$(document).ready(function(){
$("#myform").on("submit",function(e){
e.preventDefault(); //Prevent default form submission
var xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = function () {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
if (xmlhttp.responseText == "true") {
//success message
} else {
//error message
}
}
}
xmlhttp.open("POST", "index.php", true);
xmlhttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); //to maintain HTML format though you pass value through POST
xmlhttp.send("page=addPost&topic_id="+$('#topicID').val()+"value=" + $('#editor').html());
});
});
</script>
Small rework with your form:
<form id="myform" method="post">
<div id="editor" name="editor">
Lorem Ipsum... in WYSIWYG format
</div>
<input type="hidden" id="topicID" value="{TOPIC_ID}"/>
<input type="submit" name="submit" value="senden" />
</form>

Related

TinyMCE and AJAX is not sending data to php in mysql server

<!-- Page containing form -->
Paragraph
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>
<script src="//tinymce.cachefly.net/4.2/tinymce.min.js"></script>
<!-- Just be careful that you give correct path to your tinymce.min.js file, above is the default example -->
<script>tinymce.init({selector:'textarea'});</script>
</head>
-->
<div class="container">
<br />
<br />
<h2 align="center">Enter a new paragraph</h2>
<div class="form-group">
<form name="add_paragraph" id="add_paragraph">
<div class="table-responsive">
<table class="table table-bordered
id="dynamic_field">
<tr>
<textarea id = "paragraph" type="text" name="paragraph" placeholder="Enter paragraph text"></textarea>
</tr>
</tr>
</table>
<input type="button" name="submit" id="submit" class="btn btn-info" value="Submit" />
</div>
</form>
</div>
</div>
</body> </html> <script> $(document).ready(function(){
$('#submit').click(function(){
$.ajax({
url:"form1_support.php",
method:"POST",
data:$('#add_paragraph').serialize(),
success:function(data)
{
alert(data);
$('#add_paragraph')[0].reset();
}
});
}); }); </script>
require 'db/connect.php';
$number = count($_POST["paragraph_name"]); //it said experience
before, maybe experience_list?
if($number > 0) {
for($i=0; $i<$number; $i++)
{
if(trim($_POST["paragraph_name"] != ''))
{
$paragraph_name = mysqli_real_escape_string($db, $_POST['paragraph_name']);
$paragraph_text = mysqli_real_escape_string($db, $_POST['paragraph']);
$sql = "INSERT INTO paragraph (paragraph_name, paragraph_text)
VALUES( '$paragraph_name', '$paragraph_text')";
mysqli_query($db, $sql);
}
}
echo "Data Inserted"; } else {
echo "Please Enter Your Paragraph."; } ?>
If you are replacing a textarea with TinyMCE then the actual textarea does not get updated automatically unless one of the following happens:
You perform a standard HTML form submission - in this scenario TinyMCE will automatically update the textarea at the start of the form submission process.
You use the triggerSave() API to force TinyMCE to update the textarea.
Try adding a triggerSave() call before you send the AJAX request.
https://www.tiny.cloud/docs/api/tinymce/root_tinymce/#triggersave
<textarea id="editor" name="editor" type="text"></textarea>
tinyMCE.triggerSave();
var content = $("textarea[name=editor]").val();
var formData = new FormData();
formData.append("content", content);
$.ajax({
url: '../boot/newBlog.php',
method: 'POST',
type: 'POST',
data: formData,
contentType: false,
processData: false,
success: function(response) {
switch (response){
}
}
});

How to submit and validate a form via ajax

Please I am trying to simultaneously submit and validate my form to my database through the use of Ajax, but it is not working for me.
Here is my jquery
$(document).ready(function(){
$(".button").click(function(){
$("#myform").validate();
//Ajax to process the form
$.ajax({
type: "POST",
url: "process.php",
data: { firstname: $("#firstname").val()},
success: function(){
$('#message').html(data);
}
});
return false;
});
});
The problem is when I submit the form,the Ajax form submit to itself.
Please What is the right way to use the jquery validate and $.ajax together?
Pass data as a parameter in your success function:
success: function(data){
Your success function won't do anything because you haven't defined data
Try this (working for me as expected):
HTML Form:
<link rel="stylesheet" href="http://jquery.bassistance.de/validate/demo/css/screen.css" />
<script src="http://jquery.bassistance.de/validate/lib/jquery.js"></script>
<script src="http://jquery.bassistance.de/validate/jquery.validate.js"></script>
<script>
// JQuery Script to submit Form
$(document).ready(function () {
$("#commentForm").validate({
submitHandler : function () {
// your function if, validate is success
$.ajax({
type : "POST",
url : "process.php",
data : $('#commentForm').serialize(),
success : function (data) {
$('#message').html(data);
}
});
}
});
});
</script>
<form class="cmxform" id="commentForm" method="get" action="">
<fieldset>
<p>
<label for="cname">Name (required, at least 2 characters)</label>
<input id="cname" name="name" minlength="2" type="text" required />
<p>
<label for="cemail">E-Mail (required)</label>
<input id="cemail" type="email" name="email" required />
</p>
<p>
<label for="curl">URL (optional)</label>
<input id="curl" type="url" name="url" />
</p>
<p>
<label for="ccomment">Your comment (required)</label>
<textarea id="ccomment" name="comment" required></textarea>
</p>
<p>
<input class="submit" type="submit" value="Submit" />
</p>
</fieldset>
</form>
<div id="message"></div>
PHP Code:
<?php
echo $_POST['email'];
?>
You forget to pass the response
$(document).ready(function() {
$(".button").click(function() {
//check the validation like this
if ($("#myform").valid()) {
//Ajax to process the form
$.ajax({
type: "POST",
url: "process.php",
data: {
firstname: $("#firstname").val()
},
//you forget to passs the response
success: function(response) {
$('#message').html(response);
}
});
return false;
}
});
});
First of all, why would you submit form if validation is not passed?
Try this, if validate really validates:
$(function(){
$(".button").click(function(){
var myform = $("#myform");
if (myform.validate()) {
$.post("process.php", myform.serialize(), function(data){
$('#message').html(data);
});
}
return false;
});
});

Get the textbox Text using ajax on button click

I want a code for get textbox value when submit button is clicked. It must be Ajax.Here is the code I tried so far.But I culdent get to work....
<form action="" method="post">
<p>Route No :
<input type="text" name="route_no" required="required" />
<input type="submit" value="Search" name="search" />
</form>
Ajax Code
<script type="text/javascript">
$(document).ready(function() {
$("#sub").click(function() {
var textboxvalue = $('name or id of textfield').val();
$.ajax({
type: "POST",
url: 'ajaxPage.php',
data: {txt1: textboxvalue},
success: function(result) {
$("div").html(result);
}
});
});
});​
</script>
PHP code
$txt = null;
if((isset($_POST)) && (isset($_POST['txt1'])))
{
echo $txt = $_POST['txt1'];
}
HTML:
<label for="route_no">Route No:</label><input type="text" id="route_no" name="route_no" required="required" />
<input type="button" value="Search" id="search" />
<div id="result"></div>
JavaScript:
$(document).ready(function()
{
$("#search").click(function()
{
var textboxvalue = $('input[name="route_no"]').val();
$.ajax(
{
type: "POST",
url: 'ajaxPage.php',
data: {txt1: textboxvalue},
success: function(result)
{
$("#result").html(result);
}
});
});
});​
ajaxPage.php:
if(isset($_POST) && isset($_POST['txt1']))
{
echo $_POST['txt1'];
}
You have problem here
$("#sub").click(function() {
you are using id ="sub" for submit button but you are not assigning id to that button so give id to submit button as id="sub".
To get the value of the textbox you can use:
$('#elementid').val()

Jquery for submiting without refresh (no validation required)

I have a form for Tags that is working OK, with some server validation, I would like to add a Jquery to submit the content without refreshing:
<form method="post" action="tags">
<div>
<input type="hidden" name="id" value="getId()" />
<input type="text" name="tag" />
<input type="submit" value="Add" name="add" />
</div>
</form>
Any advice will be highly appreciated.
Check out the jQuery Form Plugin. Using it, you can submit a form without reloading the page like so:
<form id="aForm" action="target.php" method="post>
...
</form>
<script type="text/javascript">
$(document).ready(function() {
$("#aForm").ajaxForm();
});
</script>
The ajaxForm() function also supports all options (such as a callback function) that can be passed to the standard jQuery $.ajax function.
$(document).ready(function() {
$(form).submit( function() { // could use $(#submit).on('click', function(){ as well
$.ajax({
url: 'yourposturl',
data: $(form).serialize(),
Success: function() {
alert('ok');
}
}); //end ajax
return false;
}); //end submit()
});
Should take all form vars , serialize them so the server can receive, the return false is so page doesnt refresh on submit (stops propagation and default)
Add the JQuery javascript library
Turn the submit into a button
<button id="submitbutton" >Add</button>
Add ids to your inputs
<input type="text" id="tag" name="tag" />
And add the jquery to the click for the button ...
<script type="text/javascript">
$(document).ready(function() {
$("#submitbutton").button().click(function(){
$.post("tags.php",{id: $("#id").val(), tag: $("#tag").val()});
});
});
</script>
<form method="post" action="tags">
<div>
<input type="hidden" name="id" value="getId()" />
<input type="text" name="tag" />
<input class="button" type="button" value="Add" name="add" />
</div>
</form>
$(function(){
$('.button').click(function(){
var data = $('form').serializeToObject();
$.post('tags.php', data);
});
});
// jQuery Extension to serialize a selector's elements to an object
$.fn.serializeToObject = function () {
var o = {};
var a = this.serializeArray();
$.each(a, function () {
if (o[this.name] !== undefined) {
if (!o[this.name].push) {
o[this.name] = [o[this.name]];
}
o[this.name].push(this.value || '');
} else {
o[this.name] = this.value || '';
}
});
return o;
};

Colorbox and php form

I have a simple form page and i want to when the form is submit show the response message which came from my process.php in to colorbox. Thanks for your helping.
You could try with this
$("#link").colorbox({ inline:true, href: "#msg"});
$('input[type="submit"]').click(function(){
$.ajax({
type: "POST",
url: "process.php",
data: $('intpu[type="text"]').serialize(),
success: function(data){
$("#msg").html(data);
$("#link").click(); // My mistake $("#link").colorbox(); This doesn't work
return false;
}
});
return false;
});
Your html
<form name="exam" method="post">
<input size="60" type="text" name="quote" />
<input type="submit">
</form>
<a id="link" style="display:none"></a>
<div id="msg" style="display:none;"></div>

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