Laravel Blade - pass variable via an #include or #yield - php

I need to pass a variable to an included Blade file. I have attempted this two-ways; however, neither have been successful.
Pass a variable, title, to the included file:
#section('left')
#include('modal', ['title' => 'Hello'])
#stop
Use #yield and set the section:
#section('left')
#include('modal')
#section('title')
Hello
#stop
#stop
I am using Laravel 4.2. I am unaware if what I am trying to do is possible, but I imagine it is.

According to the documentation, the include-way should be the way to do it:
Including Sub-Views
#include('view.name')
You may also pass an array of data to the included view:
#include('view.name', array('some'=>'data'))
My hunch is that $title is conflicting with another variable in your nested templates. Just for troubleshooting, try temporarily calling it something else.

pass an array of data to the included view
#include('view.name', array('some'=>'data'))
then use this on view/name folder
{{ $some }}

Related

How to pass a subview to a master view in Laravel?

I have a master view and depending on the URL and controller, it will load in another subview to a variable called $content, that's the idea.
Currently I am trying with:
return view("master")->with(["content" => view("pages.group")]);
So for example, if the URL is https://example.com/group/1 I am trying to get the subview included on my master template. Currently, it just gets escaped for XSS but I feel like this isn't the right way to do this?
I assume you are trying to display the sub-view content in the follwing way:
{{ $content }}
Change your syntax from {{ }} (Escaped output) to {!! !!} (Non escaped output).
{!! $content !!}
In the end after #lagbox mentioned it, using Laravel sections enabled me to use a master view and extend it when needed. https://laravel.com/docs/6.x/blade#extending-a-layout

Laravel Blade - Advantage of #slot/#component vs #include?

Laravel 5.4 Blade introduced the concept of components & slots - but I can't see what they add over the traditional #include. As I understand, with component/slots, you do:
In template component-tpl.blade.php:
<div class='container'>
<h1>{{$slot1}}</h1>
<h2>{{$slot2}}</h2>
</div>
Using slots in page template, you do:
#component('component-tpl')
#slot('slot1')
The content of Slot 1
#endslot
#slot('slot2')
The content of Slot 2
#endslot
#endcomponent
What functionality does that provide over the older:
#include('component-tpl',['slot1'=>'The content of Slot 1',
'slot2'=>"The content of Slot 2"])
using the exact same 'component-tpl.blade.php' Blade template?
What am I missing? Thanks for any insights.
Chris
As stated, there's no functional difference I was incorrect - see benjaminhull's answer for details on variable scoping and passing blade syntax code. The following still holds for basic usage, though.
If a slot could contain HTML, then using a component will give a cleaner syntax in your blade files.
#component('test')
<strong>This text has html</strong>
#endcomponent
versus
#include('test', ['slot' => '<strong>This text has HTML</strong>'])
Equally, if a component has no slots, then an include may be preferred:
#include('test')
versus
#component('test')
#endcomponent
There are two key differences.
1. Variable scope
As described in #DavidHyogo's answer, a component only sees variables explicitly passed to it. So you have to give it all variables like so...
#component('my-component', ['foo' => 'bar', 'etc' => 'etc'])
Whereas an include will adopt all variables from the global/current scope by default - unless you define an explicit set of variables to pass it, which then becomes local scope again.
{{-- This include will see all variables from the global/current scope --}}
#include('my-component')
{{-- This include will only see the variables explicitly passed in --}}
#include('my-component', ['foo' => 'bar', 'etc' => 'etc'])
2. Component's {{ $slot }} vs include's {{ $var }}
When using a {{ $slot }} in a component, you can give it blade syntax code e.g...
{{-- alert.blade.php --}}
<div class="alert">{{ $slot }}</div>
#component('alert')
<div>Hello {{ $name }} #include('welcome-message')</div>
#endcomponent
Note how the slot will receive html AND blade syntax code and just deal with it.
This is not possible with includes because you can only pass variables into includes...
{{-- alert.blade.php --}}
<div class="alert">{{ $slot }}</div>
#include('alert', ['slot' => "I CAN'T PASS IN BLADE SYNTAX HERE!"])
It could be done in a more hacky way by grabbing a fresh view() helper and passing it some variables to compile the output we want to pass into the slot, but this is what components are for.
I think I've tracked down another crucial difference. For instance, from the documentation for 5.4:
Blade's #include directive allows you to include a Blade view from within another view. All variables that are available to the parent view will be made available to the included view:
As far as I can tell, components have a different scope from a containing view and so the variables available to the parent view are not available within the component. You need to pass a variable to a component like this:
#component('alert', ['foo' => 'bar'])
#endcomponent
This discussion is related to this problem:
Use variables inside the Markdown Mailables
As the documentation says:
Components and slots provide similar benefits to sections and
layouts; however, some may find the mental model of components and
slots easier to understand.
For me most important thing is component needs a class. So when I need just a simplest reusable part of html (blade) there is no need to create blade file + php file, just simple #include with subview is enough ;)

How to correct Laravel's Blade variable section scoping when yielding inside a loop?

When I include a blade template that extends a base blade, any variables within the section of the included blade show only the variables of the first iteration.
Reading around it seems the render order here is important, and views are rendered before variables, or vice versa.
Note
I have read this SO question/answer: Laravel Blade #yield variable scope
The below snippet is greatly reduced in complexity, so the example could be restructured to exclude sections/extends. However my real case can't be
Example
// index.blade.php
//
#foreach($jobs as $job)
{{ $job->id }} // <-- Correct output, 1,2,3,..N
#include('job-detail', ['id' => $job->id])
#endforeach
Then in the job detail blade
// job-detail.blade.php
//
#extends('job-base')
A: {{ $id }} // <-- Correct output, 1,2,3,..N
#section('content')
B: {{ $id }} // <-- Incorrect output, 1,1,1,..1 (or whatever the first index is)
#endsection // have also tried #stop
Then in the job base blade
// job-base.blade.php
//
#yield('content') // Have also tried #section('content') + #show
After wading through the source code, namely BladeCompiler and View/Factory I noticed the following snippet:
protected function compileOverwrite($expression)
{
return '<?php $__env->stopSection(true); ?>';
}
In the background Laravel appears to store rendered content (by including the file, and extract current variables in a ob_style fashion) in a keyed array, with the view name being the key.
When stopSection is not passed a boolean true, it creates a new key, and the view gets the data from the original key.
Long story short, it's now undocumented (for 5.1+) but can be found in the docs for 5.0:
https://laravel.com/docs/5.0/templates
However it doesn't really explain the "why". This page seems to explain it a little better:
http://laravel-recipes.com/recipes/244/stopping-injecting-content-into-a-section-and-overwriting

Laravel 4 Blade #include variable

I was trying to do include with Laravel blade, but the problem is it can't pass the variable. Here's my example code:
file_include.blade.php
<?php
$myvar = "some text";
main.blade.php
#include('file_include')
{{$myvar}}
When I run the file, it return the error "Undefined variable: myvar". So, how can I pass the variable from the include file to the main file?
Thank you.
Why would you pass it from the include to the calling template? If you need it in the calling template, create it there, then pass it into the included template like this:
#include('view.name', array('some'=>'data'))
Above code snippet from http://laravel.com/docs/templates
Unfortunately Laravel Blade engine doesn't support what you expected!.But a little traditional way you can achieve this!
SOLUTION 1 - without Laravel Blade Engine
Step a:
from
file_include.blade.php
to
file_include.php
Step b:
main.blade.php
<?php
include('app/views/file_include.php')
?>
{{$myvar}}
SOLUTION 2 with Laravel Blade Engine
routes.php
$data = array(
'data1' => "one",
'data2' => "two",
);
View::share('data', $data);
Access $data array from Any View like this
{{ $data['data1'] }}
Output
one
Blade is a Template Engine for Laravel. So try passing the value from the controller or you may define it in the routes.php for testing purposes.
#include is used to include sub-views.
I think you must understand the variable scope in Laravel Blade template. Including a template using #include will inherit all variables from its parent view(the view where it was defined). But I guess you can't use your defined variables in your child view at the parent scope. If you want your variable be available to the parent try use View::share($variableName, $variableValue) it will be available to all views as expected.
In this scenarion $myvar would be available only on the local scope of the include call.
Why don't you send the variable directly from the controller?
I suggest you do a classic PHP require if you really want to change your variable (then it's automatically by reference)

Override section in a laravel blade template throwing undefined variable errors

I am using Laravel 4 and blade templates, and running into an issue when I try and extend a template.
In my layout I have
#yield('content')
and in my page I have
#section('content')
Welcome {{ $name }}
#stop
which works fine, I've created another page very similar to my first, and just want to change override the admin content section. The other sections in the template are fine.
so I extend my page, and do
#section('content')
Hello!
#stop
I get an undefined notice with the $name variable.
I tried
#section('content')
Hello!
#overwrite
and same deal, I get the notice error.
I checked my controller and it IS using the correct template. I am not calling #parent so I don't understand, how can I overwrite a section in a template with out notice errors?
Blade layouts work their way up the tree to the route or master view before rendering any of the children. Thus, nested views that extend others must always have their parent rendered before they are. As a result, parent views that contain sections will always be rendered prior to the child.
To overcome the problem you are experiencing it is a good idea to only ever nest pages that don't overwrite parents sections that contain variables, as the parents content will always be rendered before the child.
As the above ideal can't always be adhered to or a parents section content is still required, a good alternative method would be to use view composers. View composers give you an opportunity to declare variables for any specific view whenever they are rendered.
View::composer(array('pages.admin'), function($view)
{
$view->with('name', Auth::user()->username);
});
Another alternative would be to use a view creator. Creators are fired the moment a view is instantiated rather than rendered. This method allows you to overwrite the variable should you so wish prior to the view being rendered.
View::creator(array('pages.admin'), function($view)
{
$view->with('name', Auth::user()->username);
});
You can read up more about these methods in the documentation here. (Or here for the Laravel 5 documentation.)
I can't guarantee support for Laravel 4 but for those looking for a solution that works in Laravel 5.5 (and probably a fair bit further back – hard to check) is to define the variables you need when #extending.
E.g. in the example in the question:
#extend('my.parent.view', ['name' => ''])
This approach can be especially useful if the data needed is available to the child-view, but under a different name.
E.g. if a parent-view needed a $parent variable, but the child view only has a $child variable which has a property referencing the parent, you might do:
#extend('my.parent.view', ['parent' => $child->parent])
I am not sure if this is a bug or intentional, but it seems like Laravel renders the variables before interpreting blade instructions.
The workaround would be this:
views/layouts/testlayout.blade.php:
<html>
<body>
#yield('sidebar', 'This is the master sidebar. {{ $name }}' )
<div class="container">
#yield('content')
</div>
</body>
</html>
actual view: views/test.blade.php
#extends('layouts.testlayout')
#section('sidebar')
No variable in the child
#stop
#section('content')
This is a child content
#stop
This prevents the variable $name to get rendered if there is a section with that name in the actual view. It seems like this is the approach if the content in the layout file contains a variable
In your page try this :
#section('content')
#hasSection('content')
#yield('content')
#else
Welcome {{ $name }}
#endif
#stop
And read this post for more inspiration https://laracasts.com/discuss/channels/laravel/laravel-blade-layouts-inheritence-problem
I found an easy solution for this problem :)
Just add the # symbol before the variable/method you call in the parent view. If there is an error (notice/warning) PHP will ignore that and continue the execution.
It's not perfect, but save us to code view/composers.
Hope this help!

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