While loop if statement NULL issue - php

Question

I can't seem to get this figured out. What am I doing wrong? I have a table in my database and some rows have an empty column for the "company" field.
I'm trying to get the "Users own uploaded files in the html table below. It belongs with "1629"
<?php
// Make a MySQL Connection
mysql_connect("localhost", "", "") or die(mysql_error());
//echo "Connected to MySQL<br />";
mysql_select_db("") or die(mysql_error());
//echo "Connected to Database";
$query = "SELECT company, dmy, COUNT(company) FROM AdTracking WHERE DATE(dmy) = CURRENT_DATE GROUP BY company";
$result = mysql_query($query) or die(mysql_error());
echo "<div style='margin-top:100px;'><center><h2>";
echo date('l jS \ F Y');
echo "<br />";
echo "</h2><center></div>";
echo '
<center> <table class="pure-table pure-table-horizontal">
<thead>
<tr>
<th>Company</th>
<th>Total</th>
</tr>
</thead>
<tbody>
';
// Print out result
while($row = mysql_fetch_array($result)){
if ($row['company'] == NULL) {
echo "Users own uploaded files";
};
echo "<tr>";
echo "<td><strong>" . $row['company'] . "</strong></td>";
echo "<td>" . $row['COUNT(company)'] . "</td>";
echo "</tr>";
}
echo '
</tbody>
</table> </center>
';
?>

Answer 1

You are printing outside of td and tr.
You have maintain format .
Try like this
echo "<tr>";
echo "<td><strong>" .($row['company'] == NULL ? "Users own uploaded files" : $row['company']). "</strong></td>";
echo "<td>" . $row['COUNT(company)'] . "</td>";
echo "</tr>";

Answer 2

you should use mysql_fetch_assoc() instead of mysql_fetch_array()

Answer 3

while($row = mysql_fetch_array($result)){
if (!$row['company']) // it check null or have something value
$value = "Users own uploaded files";
else
$value = $row['company'];
echo "<tr>";
echo "<td><strong>" . $value . "</strong></td>";
echo "<td>" . $row['COUNT(company)'] . "</td>";
echo "</tr>";
}
use mysqli or PDO instead of mysql because "mysql" is deprected.