Display field from different table in a input form - php

Question

How would I display student.Student instead of student_id
<?php
for ($i = 0; $i < $chkcount; $i++) {
$id = $chk[$i];
$res = $MySQLiconn->query("SELECT Student.ID, student.Student, student.School,student.PR, Jumps.dis_ft_1, Jumps.dis_in_1, Jumps.dis_ft_2, Jumps.dis_in_2, Jumps.dis_ft_3, Jumps.dis_in_3, Jumps.dis_ft_4, Jumps.dis_in_4, Jumps.dis_ft_5, Jumps.dis_in_5, Jumps.dis_ft_6, Jumps.dis_in_6
FROM Student LEFT JOIN Jumps ON Student.ID = Jumps.student_id WHERE ID=" . $id);
while ($row = $res->fetch_array()) {
?>
<tr>
<td>
<input type="hidden" name="id[]" value="<?php echo $row['ID']; ?>"/>
Student ID: <input type="text" name="st[]" value="<?php echo $row['student_id']; ?>"
class="form-control"/>
Attempt 1 <input type="text" name="df1[]" value="<?php echo $row['dis_ft_1']; ?>"
class="form-control"/>
<input type="text" name="di1[]" value="<?php echo $row['dis_in_1']; ?>"
class="form-control"/>
Attempt 2 <input type="text" name="df2[]" value="<?php echo $row['dis_ft_2']; ?>"
class="form-control"/>
<input type="text" name="di2[]" value="<?php echo $row['dis_in_2']; ?>"
class="form-control"/>
Attemp 3 <input type="text" name="df3[]" value="<?php echo $row['dis_ft_3']; ?>"
class="form-control"/>
<input type="text" name="di3[]" value="<?php echo $row['dis_in_3']; ?>"
class="form-control"/>
Attempt 4 <input type="text" name="df4[]" value="<?php echo $row['dis_ft_4']; ?>"
class="form-control"/>
<input type="text" name="di4[]" value="<?php echo $row['dis_in_4']; ?>"
class="form-control"/>
Attempt 5 <input type="text" name="df5[]" value="<?php echo $row['dis_ft_5']; ?>"
class="form-control"/>
<input type="text" name="di5[]" value="<?php echo $row['dis_in_5']; ?>"
class="form-control"/>
Attempt 6 <input type="text" name="df6[]" value="<?php echo $row['dis_ft_6']; ?>"
class="form-control"/>
<input type="text" name="di6[]" value="<?php echo $row['dis_in_6']; ?>"
class="form-control"/>
</td>
</tr>
<?php
}
}
?>
Not sure it can be done. But Student name would be better than student id.
Wouldn't post with more text so just typing so it will post.
I am learning PHP.

Answer 1

If there is only one field called Student i.e Student.Student, then you could just output the name <?php echo $row['Student']; ?>.
However, if there are ever name clashes, you can always give the field a new name for PHP to access.
SELECT Student.ID, Student.Student AS some_new_name FROM ....
<?php echo $row['some_new_name']; ?>