Parsing words fron string to array - php

Question

I have some searsh results like this
$search = 'an';
and some string that has many text like this
$text = 'Anda goes wiwsh totot anaana here goes like this <p>helle</p><b>an</b>Kako isyaay an koliko ana an here <div>hello ana</div>';
You will see there are a lots of words that have an
I need to go in that string and find only word that contained the search results and put in array, of course i dont need html inside, my final array must look like this
$results = array ('Anda','anaana','an','an','ana','an','ana');

Answer 1

Try something like this:
$all_words = explode(' ', strip_tags($text));
$results = array();
foreach ($all_words as $word) {
if (substr($search, $word) !== FALSE) {
$results[] = $word;
}
}
Note that because of the way your text is formatted, the array will include 'helleanKako' rather than 'an' in that one case.

Answer 2

Strrchr can return true when found match character,...
<?php
$search = "an";
$text = 'Anda goes wiwsh totot anaana here goes like this <p>helle</p><b>an</b>Kako isyaay an koliko ana an here <div>hello ana</div>';
$all_words = explode(' ', $text);
$results = array();
foreach ($all_words as $word) {
if (strrchr($word,$search) == TRUE) {
$results[] = $word;
}
}
var_dump($results);
?>

Answer 3

If it's not too late... :
<?php
$input = 'Anda goes wiwsh totot anaana here goes like this <p>helle</p><b>an</b>Kako isyaay an koliko ana an here <div>hello ana</div>';
$pattern = '/([^\s^>]*an[^\s^<]*)/i';
if (preg_match_all($pattern, $input, $matches)){
print_r($matches);
}
?>
Array
(
[0] => Array
(
[0] => Anda
[1] => anaana
[2] => an
[3] => an
[4] => ana
[5] => an
[6] => ana
)
[1] => Array
(
[0] => Anda
[1] => anaana
[2] => an
[3] => an
[4] => ana
[5] => an
[6] => ana
)
)
Hope that's what you've expected