How to Insert to database from loop Using PHP? - php

Question

The problem occurs when I insert without data. So I want your help in solving this problem.
This is my file:
students.php
<form id="student_form" method="POST" action="">
<?php
if(mysql_num_rows($q)>0){
?>
<table border="0" dir="ltr" align="center"cellpadding='0' cellspacing='0' >
<tr> <th>Student ID</th><th>Name</th><th>AVG</th><th>Joining Year</th><th>Message</th><th>Sending Message</th> </tr>
<?php while($row = mysql_fetch_array($q)){ ?>
<tr>
<td id="stud_id[]"> <?php echo $row['studant_ID']; ?></td>
<td> <?php echo $row['studant_Name']; ?></td>
<td> <?php echo $row['Average']; ?></td>
<td> <?php echo $row['year']; ?></td>
<td> <input id="message1[]" name="message1[]" type="text" size="25px" /></td>
<td><input name="submit[]" id="submit[]" type="submit" value="Send" /> </td>
</tr>
<?php }}
and this is my insert file:
insert_message.php
if (isset($_POST['message1']) && $_POST['message1']!='') {
$addss = mysql_real_escape_string($_POST['message1']);
}
if (isset($_POST['stud_id']) && $_POST['stud_id']!='') {
$std_id = mysql_real_escape_string($_POST['stud_id']);
}
//#######################################################################
$query1 = "INSERT INTO `message` (`rcvrid`, `senderid`, `msg`) VALUES ('$std_id', '22011111', '$addss'); ";
mysql_query($query1);
I connect between two file by jquery and ajax.
<script>
$("#student_form").on("submit", function(event) {
event.preventDefault();
$.ajax({
type: "POST",
url: "insert_message.php",
data: $(this).serialize(),
success: function(data) {
$("#inner_contant").append(data+"<br/>");//instead this line here you can call some function to read database values and display
},
});
});
</script>

Answer 1

Remove the form from the page
<tr>
<td id="stud_id"> <?php echo $row['studant_ID']; ?>
<input type="hidden" name="stud_id" value="<?php echo $row['studant_ID']; ?>"/>
</td>
<td> <?php echo $row['studant_Name']; ?></td>
<td> <?php echo $row['Average']; ?></td>
<td> <?php echo $row['year']; ?></td>
<td> <input id="message1" name="message1" type="text" size="25px" /></td>
<td><button class="submit" type="submit" />Send </button> </td>
</tr>
second:
your js should look like this:
$(".submit").on("click", function(event) {
event.preventDefault();
$.ajax({
type: "POST",
url: "insert_message.php",
data: {stud_id:$(this).closest('tr').find('input[name="stud_id"]').val(),message1:$(this).closest('tr').find('input[name="message1"]').val()},
success: function(data) {
$("#inner_contant").append(data+"<br/>");//instead this line here you can call some function to read database values and display
},
});
});
In insert_message.php
you need to echo a message to see if you where succesful in updating the database
echo json_encode(array('message'=>'Data updated/Error'));

Answer 2

First of all - all data passed to server in a $_POST array is taken from input fields with name attribute (unless you have some custom js handlers).
So
<td id="stud_id[]"> <?php echo $row['studant_ID']; ?></td>
does nothing.
If you want to store studant_ID somehow - use hidden field for example:
<td>
<input type="hidden" name="stud_id[]" value="<?php echo $row['studant_ID']; ?>" />
</td>
Next - what do you want from this buttons:
<input name="submit[]" id="submit[]" type="submit" value="Send" />
As they are all belong to one form they will do the same - send all fields to server. If you want every submit button send to server only a pair student_id, message you have to create a form for each pair (or do some js-handlers). Otherwise, on your server you'll have:
$_POST['stud_id'] array of all students ids from form
$_POST['message1'] array of all messages from form
If you want to process them all - do a foreach:
foreach ($_POST['stud_id'] as $key => $id) {
// find the message
$msg = $_POST['message1'][$key];
$query1 = "INSERT INTO `message` (`rcvrid`, `senderid`, `msg`) VALUES ('$id', '22011111', '$msg'); ";
mysql_query($query1);
}
And of course you should remove mysql_ functions and use newer apis - PDO or mysqli