PHP Get 52 week start/end date for a specific year - php

Question

I would like to calculate the start date from Tuesday and the end date to land on Mondays in the year 2016
I am trying to have the output
start date("j/n/Y"); end date("j/n/Y");
I have looked at similar SO questions, and google searches but its for specific week #'s, or not what I am trying to accomplish.
What I am trying to get is the following.
Start: 12/14/2015
End 12/21/2015
Start: 12/22/2015
End 12/28/2015
....
Start: 01/05/2016
End 01/11/2016
Start: 01/12/2016
End 01/18/2016
...
so on and soforth.
Any help would be greatly appreciated, and hope people dont downvote the crap out of this question. it is valid, and I have looked and cannot seem to find what I am after.

Answer 1

You can use the strtotime function to have the first tuesday of january 2016 and then loop 52 times, using next monday, and tomorrow. So you don't have to do any calculation.
<?php
$ts=strtotime("tuesday january 2016");
echo "<table>";
for ($i=0;$i<52;$i++) {
echo "<tr><td>Start: ".date("Y/m/d", $ts);
$ts=strtotime("next monday", $ts);
echo "</td><td>End: ".date("Y/m/d", $ts)."</td>\n";
echo "</td><td>Payweek: ".date("W", $ts)."</td></tr>\n";
$ts=strtotime("tomorrow", $ts);
}
echo "</table>";

Answer 2

You can try following code:
$start_date=date("m-d-Y", strtotime('tuesday this week'));
$end_date=date("m-d-Y", strtotime('monday next week'));
It will give you week starting from Tuesday and ending from Monday.

Answer 3

$oneWeek = 7*24*60*60; // 1 week in seconds
$curr_ts = time();
while ($curr_ts < strtotime('2017-01-01')) {
echo " Start: ",
date('m/d/Y', strtotime('tuesday this week', $curr_ts)),
"\nEnd ",
date('m/d/Y', strtotime('monday next week', $curr_ts)),
"\n";
$curr_ts = $curr_ts + $oneWeek;
}

Answer 4

While the date is less than your defined end date, loop over each week.
$date = Some start date ...;
$endDate = Some end date ...;
while (date_interval_format($date->diff($endDate),'%R') == '+') {
echo $date->format('j/n/Y') . " - " . $date->add(new DateInterval('P6D'))->format('j/n/Y') . "\n";
$date->add(new DateInterval('P1D'));
}