I am implementing a simple newsletter form using PHP and CodeIgniter as part of a big project.
My HTML code is as follows.
<form method="POST" action='http://sit.com/index.php/Users/subscribenews'>
<div class="input-group">
<input type="email" id="pkemailid" name="pkemailid">
<span class="input-group-btn">
<button class="btn btn-lg btn-primary" type="submit"> Go
</button>
</span>
</div><!-- /input-group -->
</form>
In my Controller, I am handling the value as
$emailid = $this->input->post('pkemailid');
When I do a var_dump of the $_POST variable, I get the following
array(0) { }
The biggest problem is that I am able to run this correctly on my WAMP Server on localhost but it does not work on the hosted server.
Interestingly, if I change the POST to GET, then it starts working.
this line
<input type="email" id="pkemailid" name="pkemailid">
try changing it to
<input type="text" id="pkemailid" name="pkemailid">
type="email" is html 5 only and i don't know for certain -- but codeigniter might not support html 5 form values.
===== edit
so my suggestion when you are at the hair pulling questioning reality stage of trying to find a bug - get a fresh new copy of codeigniter, install on your server, make sure you get the welcome page.
now make the simplest form possible and echo something out from the controller method to make sure that you are submitting the form to the correct method. Next add a hidden form field with a value, and echo out that value from your method.
If all that works, then its not your server you have bug in your original code. And if it doesn't work then you have an issue with the server.
Related
Will React submit my form through PHP once it's on a hosting site with an actual server (Heroku) or do i need to use different code?
I'm using a react app for my website and in a contact page i have a form that i use action="form.php" but of course when i submit i get an error "cannot POST form.php. Probably because there is no server. My question is once i upload it to my hosting or heroku, will it automatically work or do i need to use different method than action... ?
I've tried other solutions but nothing worked
class ProjectReqs extends Component {
render() {
return (
<div>
<form action="./components/webform.php" class="webform" method="post">
<h4>Let's Design a beautiful Website</h4>
<h5>Please fill out your requirements for your website project below.</h5>
<div class="webformgenerate"></div>
<div class="webcustomreqsspace"></div>
<button class="submit-btn" name="submit" type="submit">Submit</button>
<button class="preview-btn wpb">Preview</button>
<span class="tooltip">You must preview and save before submitting</span>
</form>
</div>
I have a page ( index.html ) with a form. On submit the data is posted to a php-file which then stores said data in a (temporary) xml-file, however, I also have a number of iframes which also contain forms.
At first, I was planning on simply posting the input-data from the iframes to a seperate php file but I encountered several problems:
-I have several iframes, but I don't have a fixed amount since the user is supposed to be able to delete/ add iframes. Therefore I can't just tell iframe 1 to send its data to php-file no. 1, iframe 2 to send its data to php-file no.2 etc.., I need a flexible solution.
-I tried to submit all iframe inputs to ONE php file and was hoping it'd work since the xml-file this php-file sends the data to is only updated and not completely overwritten. As you might guess, this did not work.
-Another problem I encountered is that the user may go back and edit whatever he entered into the iframe. The data should only be saved once he clicks on the save button in the html-file to prevent that.
I also tried submitting the data via JavaScript, as people in similar questions suggested, but that did not work out for me. So I guess what I would like, is a suggestion as to how I should go about this. How can I send all the data once the "main" save button is clicked, it doesn't matter if the data goes to several php files. The solution shouldn't depend on a fixed amount of elements as that amount is not always the same.
Here's the iframe-html:
<form method="POST" action="php/iframe.php">
<label>Your thoughts:</label>
<input type="text" name="header">
<label>Suggestions:</label>
<textarea type="text" name="textbox"></textarea>
<input type="button" value="submit">
</form>
(It's basically the same for all Iframes).
Please let me know if you need any additional information.
Edit: I read that submitting forms at the same time may cause interference, I know that much
Edit:
Relevant index.html:
<form method="post" action="main.php">
<div id="firstSection"
<label>First input</label>
<input type="text" name="input[]">
<button type="button" onclick="openIframe1()">Read more</button>
</div>
<div id="secondSection"
<label>Second input</label>
<input type="text" name="input[]">
<button type="button" onclick="openIframe2()">Read more</button>
</div>
<button type="submit" value="submit"></button>
</form>
<div class="iframe">
<button type="button" class="close">Close</button>
<iframe src="iframe1.html"></iframe>
</div>
<div class="iframe">
<button type="button" class="close">Close</button>
<iframe src="iframe2.html"></iframe>
</div>
Define an array of your iframe inputs in the main page as hidden element, on click submit in the main page loop through the iframe by getting the datas and append to your hidden element from where you can now post that to your back end.. try this: Access jQuery data from iframe element
I have a page that has multiple php forms that send me different informations depending on the user and the form. How do I make php differentiat these? I saw something about the actions and I thought maybe it was like having a separate file, but when I created a "questions.php" and copied and pasted my php code into that and then added "action="questions.php"" to the tag, and ran it just as I had before it didn't work. So what is the correct way to do this?
My code is extremely long and filled with words which is why it would be nice to have separate files for it depending on the form instead of all in the top of my main page.
You could build one page as a standard page. in this page you could include the different forms. See the example below:
<!-- These are just example names -->
<div class="form-1">
<?php include "forms/form-1.php"; ?>
</div>
<div class="form-2">
<?php include "forms/form-2.php"; ?>
</div>
<div class="form-1">
<?php include "forms/form-3.php"; ?>
</div>
If you would like to save data that a user puts in a form in lets say a database you should use the <form method="post"> by adding an action to it. You're asking the form to send the user to another page when the submit button is clicked. an example of a form down below.
<form class="form-1" method="post" action="second_page.php">
<label>Name:
<input type="text" class="input" name="name">
</label>
<label>Email:
<input type="email" class="input" name="email">
</label>
<button type="submit">Send!</button>
</form>
Hope this helps!
I just added a / before the questions.php. apparently it had to do with file path? I don't understand it but it works now.
<form action="questions.php" method="post">
<!-- text boxes to get user inputs-->
<button type="submit" value="submit_btn">click here to go to page in action tag
</button>
</form>
If questions.php file is in same folder action="questions.php" is enough. If its inside 'x' folder, correct path should be given as action="x/questions.php"
I just started using twitter bootstrap, and I got stuck trying to get my form submit button to submit (PHP $_POST). Does anyone know why its not working?
No clue really..
I've been doing this previously and its been working until bootstrap:
<?php
if (isset($_POST["login"]) && $_POST["login"]=="login") {
echo "login here";
}
?>
<form action="http://mysite.com" method="post">
<input type="hidden" id="login" name="login" value="login" />
<button class="btn success" type="submit">Login</button>
</form>
The page seems to load but the PHP does not. Is the POST information being blocked?
My form input elements did not have an id or name (I didn't include them in my example).
Not an HTML expert, but I've always used <input type="submit" /> and not <button type="submit" />, not sure that button is a functional form element.
Also, your button element is closed twice - first with /> in the opening tag, and then again with a closing tag for no reason.
Maybe you are wrong with the action="http://mysite.com"? That attribute is for specifing the form data receiver, so in your case I think it's the page itself. So, if your page is named mypage.php, use action="mypage.php".
I had this same issue as well, turns out I was missing the name="submit". Gotta have that so the $_POST has a key in the assoc array!
it is adviseable that every element has a name thus (name="elementName") this makes it easy to reference them in your php scipt; also ensure that a form action and method are set.
I seem to have a bit of a problem here that I can't quite figure out.
So the deal is I have a php script along with an HTML file, in that file I have a few forms with some text boxes and some drop downs. Now the reason I had to go single forms on all of these was because if I did one big one none of them would work when I would hit the submit button. I have no idea... My current code is below, my previous code only had one form and it wouldn't work at all.
<form method="post" id="locationFromPost" name="locationFormPost">
<div class="formRow">
<div class="label">
<label for="locationForm">Current Location:</label>
</div>
<div class="field">
//If post is null go back to value pull originally else echo post
<?php if($_POST['locationForm']==null) $location=$location;else $location=$_POST['locationForm']; ?>
<input type="text" name="locationForm" id="locationForm" value="<?php echo $location?>"></input>
</div>
</div>
</form>
...... and so on.......
<form method="post" id="sexFromPost" name="sexFormPost">
<div class="formRow">
<div class="label">
<label for="sexForm">Sex</label>
</div>
<div class="dropDown">
<select name="sex" id="sexForm" >
//If post is null go back to value pull originally else echo post
<?php if($_POST['sexForm']==null) $sex=$sex;else $sex=$_POST['sexForm']; ?>
<option value="1" <?php if($sex==1){echo"selected='selected'";}?>>Male</option>
<option value="2" <?php if($sex==2){echo"selected='selected'";}?>>Female</option>
<option value="3" <?php if($sex==3){echo"selected='selected'";}?>>Not Specified</option>
</select>
</div>
</div>
</form>
...... and so on.......
<form method="post" id="submit" name="submit">
<div class="formRow"><div id="seperator"></div></div>
<div class="submitButton">
<input type="submit" name="submit" id="submit" value="Save Changes"/>
</div>
</div>
</form>
So thats what the top part of my code looks like, all the div's are for formatting you don't have to worry about those. Now the php code to save the information is below. I should note that the variables you see in the php parts of the code above are retrieved from the Database in the earlier part of the code, thats working fine. What I am having problems with is I want a user to be able to edit their information then just hit the submit button and the information to be saved. What currently happens is, well, absolutely noting. The page will refresh and all the values will go back to what they were when they were pulled, they are not stored in the DB at all, now I checked to make for sure that part of the code works, buy doing some test. It saves the data no problem. What I thin is the problem is the forms them-selfs, if I do everything in one big form it doesn't work... Don't know why. now if I hit enter at the end of each of the forms individually in the browser the data goes in but just that field, sometimes other fields are wiped completely out and a null or empty string is stored. I cant seem to figure this thing out at all.
heres the php to save the information.
<?php
if (isset($_POST['submit']))
{
mysql_query("UPDATE members SET location= '".$_POST['locationForm']."' WHERE usr='" .mysql_real_escape_string($_SESSION['usr']) ."'");
mysql_query("UPDATE members SET location= '".$_POST['sexForm']."' WHERE usr='" .mysql_real_escape_string($_SESSION['usr']) ."'");
........ you know the rest.......
}?>
I am completely lost at why this thing is doing this, now im not the best PHP programmer by any-means, so it could (probably is) be me. If anyone could point out what I would need to do to get a system like that working please let me know
Thanks.
I wasn't clear exactly what your problem was.
However this:
<?php if($_POST['locationForm']==null) $location=$location;else $location=$_POST['locationForm']; ?>
Doesn't look to me like it is going to do much. Try something like this:
<?php
if(!isset($_POST['locationForm'])){
$location=$location;
}
else {
$location=$_POST['locationForm'];
}
?>
(Curly braces are my own personal liking)
Assuming you have $location defined somewhere you didn't show us. This will check if there is NOT a $_POST['locationForm'], and if there is it will use it.
Try placing all the form fields within on form tag and also use mysql_real_escape_string on your variable as well.
you need all the fields that are going to be submitted to any given page to exist in a single form tag. any elements in a different form tag will submit as a set of THAT form tag.
I' assuming that you also want to maybe combine down your updates?
//$_SESSION['usr'] should already be sanitized and safed wherever you handle your site credentials..
//set your submittable values, with a default to an empty string in this case.
$sex=isset($_POST['sexForm'])?mysql_real_escape_string($_POST['sexForm']):"";
$location=isset($_POST['locationForm'])?mysql_real_escape_string($_POST['locationForm']):"";
//single statement, no need to iterate for each field, that's wasted connections.
$sql="update "UPDATE members SET location= '$location' , sex='$sex' WHERE usr='".$_SESSION['usr']."'";