Deletion of row in MySQL using php - php

Question

I have been developing a CRUD application using PHP & MySQL database.
I was succeeded by creating, displaying, updation parts. But I stuck at the deletion part of a row from a database table.
I tried my best solving all the PHP shown errors but now in final it is now showing a message which I wrote to echo in case of failure.
I request someone to please help me with this problem.
Thankyou in advance.
Code I wrote for deletion:
//include database connection
include 'db_connect.php';
//$mysqli->real_escape_string() function helps us prevent attacks such as SQL injection
$query = "DELETE
FROM `grocery`
WHERE `GrocerID` ='".$mysqli->real_escape_string($_GET['id'])."'
limit 0,1";
//execute query
if( $mysqli->query($query) ){
//if successful deletion
echo "User was deleted.";
}else{
//if there's a database problem
echo "Database Error: Unable to delete record.";
}
$mysqli->close();
?>
Code I wrote for delete link in display table:
//just preparing the delete link to delete the record
echo "<a href='delete.php?id={$GrocerID}'>Delete</a>";
Code I wrote for db config:
<?php
//set connection variables
$host = "localhost";
$username = "root";
$password = "secret";
$db_name = "crud"; //database name
//connect to mysql server
$mysqli = new mysqli($host, $username, $password, $db_name);
//check if any connection error was encountered
if(mysqli_connect_errno()) {
die("Connection failed: " . $conn->connect_error);
exit;
}
?>

Answer 1

I tried this and got working, can you update the code and see if this works?
$host = "localhost";
$username = "root";
$password = "secret";
$db_name = "crud"; //database name
//connect to mysql server
$mysqli = new mysqli($host, $username, $password, $db_name);
//check if any connection error was encountered
if(mysqli_connect_errno()) {
die("Connection failed: " . $conn->connect_error);
exit;
}
// Delete row
if ($mysqli->query (sprintf( "DELETE FROM grocery WHERE email = '".$mysqli->real_escape_string($_GET['id'])."' LIMIT 1") )) {
printf ( "Affected Rows %d rows.\n", $mysqli->affected_rows );
}
I hope this helps.

Answer 2

Provide a connection :
if( $mysqli->query($con, $query) ){