How can I print the lowest key of an array? - php

Question

This is my array:
array(4) {
["1"]=>
array(3) {
[0]=>
string(2) "01"
[1]=>
string(2) "02"
[2]=>
string(2) "03"
}
["2"]=>
array(2) {
[0]=>
string(2) "01"
[1]=>
string(2) "02"
}
["3"]=>
array(1) {
[0]=>
string(2) "01"
}
["4"]=>
array(1) {
[0]=>
string(2) "01"
}
}
I want to print the lowest key, but only from the keys, that have less than 3 values.
echo min(array_keys($myarray));
gives me the result: 1
But key 1 already has 3 values, so the result I would need is 2. In the case every key has 3 values then print the next key (in this case would be 5)
I do not know how to do this. I am happy for every hint or advise.

Answer 1

This function iterate over your array and looks for all keys that has a value less then 3 values. It will return the first it founds if none is found the next key is return.
function getLowestKeyWithLessThan($yourArray, $number=3)
{
foreach ($yourArray as $key => $value) {
if (count($value) < $number)
return $key;
}
return count($yourArray) + 1;
}
If I run the following lines:
print "Answer " . getLowestKeyWithLessThan($yourArray);
print "\nAnswer " . getLowestKeyWithLessThan($AllKeysHasThreeElements);
This gives the answer:
Answer 2
Answer 5
Here is the data I used to test this:
$yourArray = array(
"1"=> array(
'0' => "01",
'1' => "02",
'2' => "03",
),
"2"=> array(
'0' => "01",
'1' => "02",
),
"3"=> array(
'0' => "01",
),
"4"=> array(
'0' => "01",
),
);
$threeValues = array(
'0' => "01",
'1' => "02",
'2' => "03",
);
$AllKeysHasThreeElements = array(
"1"=> $threeValues,
"2"=> $threeValues,
"3"=> $threeValues,
"4"=> $threeValues,
);
Of course the data could also been written like this:
$threeValues = array("01", "02", "03");
$yourArray = array($threeValues, array("01", "02"), array("01"), array("01"));
$AllKeysHasThreeElements = array($threeValues,$threeValues,$threeValues,$threeValues);