How do I retrieve specific Column Data - php

Question

I've been messing around with PHP once again. I am trying to retrieve information from a specific Column. So for example I'll do
http://127.0.0.1:8002/api/galaxy/rgalaxy.php?api&Name=Hi
The Column looks like this.
+----------------+-------+
| Name | Data |
+----------------+-------+
--> | Hi | Grab | <--
| Medium product | 9.99 |
| Large product | 15.99 |
+----------------+-------+
And It'll retrieve this info Grab
So since I put in Hi As the Parameter, It'll retrieve Grab
I have no idea how to do that. Would anyone mind helping?

Answer 1

$query = "SELECT column_name FROM table_name WHERE other_column = 'value'";
replace "column_name", "table_name", "other_column" and "value" by desired.
To get your 'Name' value from url use $_GET['Name']

Answer 2

Firstly, open a connection to your database
$connection = mysqli_connect('localhost', 'db_username', 'db_password, 'db_name');
Then, use this connection to perform your query
Edit : to avoid SQL injection
<?php
$name = '';
if(isset($_GET['Name'])){
$name = $_GET['Name'];
}
$connection = mysqli_connect('localhost', 'root', '', 'ett');
$query = 'SELECT name FROM items WHERE name like ?';
$stmt = $connection->prepare($query);
$stmt->bind_param('s', $name);
$stmt->execute();
$result = $stmt->get_result();
$names_array = array();
while ($row = $result->fetch_assoc()) {
$names_array[] = $row;
}

Answer 3

Insert this Mysql query if you want only Data value as Grab
$name=$_GET['Name'];
$sql = "SELECT Data FROM YOUR_TABLE_NAME WHERE Name='.$name.' ";
and if you want to fetch more data like
| Hi | Grab |
| Medium product | 9.99 |
| Large product | 15.99 |
all then you need to add one more column who's value is common to all row and pass those column value to your url .

Answer 4

Your MySQL query will look something like this:
"SELECT * FROM your_table_name WHERE Name=$_GET['Name']"
Then you need to run the above query, and fetch it into a PHP variable and do whatever you want with that. I hope this helps you.