Oracle SQL Trigger Error- OCI_SUCCESS_WITH_INFO: ORA-24344 - php

I am using a trigger called "users_id_trigger" to auto increment the users.user_id column.
But in Object Browser its status is showing invalid!
I am working on a PHP project where i am getting this error while i run the query from a PHP script. here is the error message:
oci_execute(): OCI_SUCCESS_WITH_INFO: ORA-24344: success with compilation error
Here is my method to create the entire table and related SEQUENCE and TRIGGER to be able to have auto increment feature in the user_id column.
public function create_users_table()
{
// creating users table
oci_execute(oci_parse($this->conn, "CREATE TABLE users(
user_id NUMBER(10) NOT NULL,
user_name VARCHAR2(100) NOT NULL,
user_password VARCHAR(100) NOT NULL,
user_email VARCHAR(100) NOT NULL,
user_location VARCHAR(100) NOT NULL,
CONSTRAINT users_pk PRIMARY KEY (user_id)
)"));
// creating users sequence
oci_execute(oci_parse($this->conn, "CREATE SEQUENCE users_seq
MINVALUE 1
START WITH 1
INCREMENT BY 1
NOCACHE;
"));
// creating user sequence trigger
echo oci_execute(oci_parse($this->conn, "CREATE OR REPLACE TRIGGER users_id_trigger
BEFORE INSERT ON users
FOR EACH ROW
BEGIN
:new.user_id := users_seq.nextval;
END;
"));
}
What i am doing wrong? because the table and sequence is created successfully but not the trigger.
EDIT:
while inserting a new row i got this error:
insert into users values(1, 'hasan', '1234',
'hdg#live.com', 'Dhaka, Bangladesh')
* ERROR at line 1: ORA-04098: trigger 'FLIPLISTS.USERS_ID_TRIGGER' is invalid and failed re-validation
Oracle Version i am using: Oracle Database 11g Express Edition Release 11.2.0.2.0 - 64bit Production (Windows 10)
Compilation Error: ORA-04082: NEW or OLD references not allowed in table level triggers

If oracle version that you are using is less than 11g then Modify your trigger as below
CREATE OR REPLACE TRIGGER users_id_trigger
BEFORE INSERT ON users
FOR EACH ROW
BEGIN
select users_seq.nextval into :new.user_id from dual ;
END;

The issue is that you have newlines on windows,so remove them.
echo oci_execute(oci_parse($this->conn, trim(preg_replace('/\s+/', ' ', "CREATE OR REPLACE TRIGGER users_id_trigger
BEFORE INSERT ON users
FOR EACH ROW
BEGIN
:new.user_id := users_seq.nextval;
END;
"));));

Related

MySQL getting 0 from pdo lastInsertID

Like so many others, using the pdo lastInsertID() is only returning 0 for me. I've looked at all of the helper questions that stack Overflow puts up, searched online and I've still getting a 0. I think the code is right but I clearly missed something as I still get 0 no matter what I try.
My table has an auto-incrementing id column (named 'id'). It is also the primary key for the table. I'm using a stored procedure for the insert and so the code looks like:
$stmt = $pdo_write->prepare('CALL sp_Save_Requests(:formSecret,:ipAddress)');
$stmt->bindParam(':formSecret', $formSecret, PDO::PARAM_STR);
$stmt->bindParam(':ipAddress', $ipAddress, PDO::PARAM_STR);
$stmt->execute();
$lastID = $pdo_write->lastInsertID();
This consistently returns 0 even though a new id is available in the table - as can be seen below in the export from phpmyadmin.
I use separate connections depending if I'm selecting or inserting/updating. In this instance the connection object is:
try {
$pdo_write = new PDO("mysql:host=$myServer;dbname=$myDB", $myRW_UID, $myRW_PW);
$pdo_write->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING );
$pdo_write->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
$pdo_write->setAttribute( PDO::ATTR_EMULATE_PREPARES,TRUE );
} catch(PDOException $e) {
echo 'RW Connection Failed: '.$e->getMessage();
exit();
}
One possible issue - I do use a trigger to create and set a guid in the table but that is set to fire before the actual insert. The dump from phpmyadmin of the table follows though the name of the real table has been changed.:
SET SQL_MODE = "NO_AUTO_VALUE_ON_ZERO";
SET AUTOCOMMIT = 0;
START TRANSACTION;
SET time_zone = "+00:00";
-- Table structure for table `tbl_test`
CREATE TABLE `tbl_test` (
`id` int(10) NOT NULL,
`guid` varchar(100) NOT NULL,
`formSecret` varchar(100) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
--
-- Triggers `tbl_test`
--
DELIMITER $$
CREATE TRIGGER `tr_TestRequests_GUID` BEFORE INSERT ON `tbl_test` FOR EACH ROW SET NEW.guid = UUID()
$$
DELIMITER ;
--
-- Indexes for table `tbl_test`
--
ALTER TABLE `tbl_test`
ADD PRIMARY KEY (`id`),
ADD UNIQUE KEY `guid` (`guid`),
ADD UNIQUE KEY `id` (`id`);
--
-- AUTO_INCREMENT for table `tbl_test`
--
ALTER TABLE `tbl_test`
MODIFY `id` int(10) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=44;
COMMIT;
I would prefer to not use a select to pull the ID if I don't have to. But, I'm stumped and hope that someone can see what I'm missing. Many thanks in advance for any help.
Turns out I had a syntax error in the id assignment to the out variable. Took forever to see it but it works now.
Thanks for the feedback and making me go back through this once again.

interrupt the execution of the stored procedure (mysql) in php

I wrote a stored procedure (mysql)
CREATE PROCEDURE `set_SiteAttendance`(IN _UserName VARCHAR(20) CHARSET utf8, IN _EventDesc VARCHAR(250) CHARSET utf8, IN _EventTime BIGINT(20))
BEGIN
DECLARE _EventID INT;
DECLARE cursorGetID CURSOR FOR
SELECT id
FROM client_pages
WHERE name = _EventDesc
LIMIT 0, 1;
-- try to add a new record to the database
INSERT INTO client_pages (id, name) SELECT (IFNULL(MAX(id), 0) + 1), _EventDesc FROM client_pages;
-- get id from the database records
OPEN cursorGetID;
FETCH cursorGetID INTO _EventID;
-- set the data on the visit of the page in the database
INSERT INTO login_history VALUES (NULL, _UserName, _EventID, _EventTime);
END
When I call it using MySQL Workbench, it works correctly.
CALL set_SiteAttendance('MyName', 'page#1', 100);
When I call it using php, then the stored procedure aborts on the INSERT statement:
$query = "CALL set_SiteAttendance('$user_name', '$user_page', $user_ticks)";
mysql_query($query);
mysql_error() call issues
Duplicate entry 'page#1' for key 'name'
why it happens and how to fix?
Well, that's pretty obvious. You have a unique index on name, so your query INSERT INTO client_pages (id, name) SELECT (IFNULL(MAX(id), 0) + 1), _EventDesc FROM client_pages; can only be run once with same _EventDesc parameter.
Remove the index or change the logic of your procedure.
I decided my problem:
INSERT IGNORE INTO client_pages (id, name) SELECT (IFNULL(MAX(id), 0) + 1), _EventDesc FROM client_pages;
Error (name was found) was ignored and procedure is not interrupted

LIKE % XX(YY)GG % not working in MySQL

I have used Stored procedure to check whether a name exist in a table or not by using the following code snippet..
BEGIN
IF ids = 0 THEN
SELECT * FROM table_name WHERE `table_id` = alb_id AND name LIKE CONCAT('%',var_name,'%');
END IF;
END
I got the solution if the name doesn't contain any special characters or brackets, like XXXX.
If the name contains any brackets means result not came, like XX(YY)GG.
Suggest me for the best solution
Edited:
In this if a name exist already i should not insert it again, for this condition i used this procedure. If it returns mysql_num_rows > 0 means i wont insert, else i will insert the name into my table..
My sample names are,..
Turning Tables (Live Acoustic)
Hiding My Heart
Someone Like You (Live Acoustic)
Right Now (Na Na Na)
Keep You Much Longer
Someone Like You
In the list of name "Someone Like You" and "Someone Like You (Live Acoustic)" are two different names, i want to identify the name "Someone Like You (Live Acoustic)" is already exist or not..
How do i do?
CREATE TABLE `stack_test` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`text` varchar(100) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB CHARSET=utf8;
INSERT INTO `blur_new`.`stack_test` (`id`, `text`) VALUES ('1', 'run (rabbit) run');
INSERT INTO `blur_new`.`stack_test` (`id`, `text`) VALUES ('2', 'test');
set #a = 'n (rabbit)';
select * from stack_test where text like concat('%',#a,'%');
results in:
1 |run (rabbit) run
So, it works.
check the rest of the conditions in where clause
check how are you passing the value
you might gonna have to check you data types. I have a feeling something is not right there

oci_execute(): OCI_SUCCESS_WITH_INFO: ORA-24344 using a trigger/sequence to auto increment an oracle table error

I'm using a sequence and trigger to essentially auto increment a column in a table, however I'm getting an error - ORA-24344: success with compilation error.
I was using this post: How to create id with AUTO_INCREMENT on Oracle? and it worked successfully for two other tables w/ auto increment I made, but there must be something in here I'm not familiar with causing an error.
More edits: Thanks to Polppan we've established that this likely isn't an Oracle issue, rather an OCI with PHP issue. I'm using:
oci_execute($sql);
And as mentioned here (again, thanks Polppan for that link), there's a bit of an issue between EOL characters and oci_execute. It was 11 years ago, so I don't know if that's been patched or not, and I did try his solution but it didn't help. Does anyone know if there are other issues with oci_execute and creating triggers?
Creating the table: (works)
CREATE TABLE RT_documents (
documentID INT NOT NULL,
reviewID varchar2(20) NOT NULL,
file_location CLOB NOT NULL,
version NUMBER(*,3) NOT NULL,
CONSTRAINT RT_documents_pk PRIMARY KEY (documentID)
)
Creating the sequence: (works)
CREATE SEQUENCE rt_documents_seq
Creating/replacing trigger: (doesn't work)
CREATE OR REPLACE TRIGGER rt_documents_bir
BEFORE INSERT ON RT_documents
FOR EACH ROW
BEGIN
SELECT RT_documents_seq.NEXTVAL
INTO :new.documentID
FROM dual;
END;
EDIT: Exact error message as requested - (Note, I'm executing these query-by-query using OCI/Oracle in PHP. PHP tag added just in case, but pretty sure this is an oracle syntax error or something).
Error:
Notice: oci_execute(): OCI_SUCCESS_WITH_INFO: ORA-24344: success with
compilation error in (...)
-I can successfully execute the first two queries, and double checked and the table is there so it worked properly.
Trigger doesn't understand new.id as id doesn't exist in RT_documents table.
Your trigger should be
CREATE OR REPLACE TRIGGER rt_documents_bir
BEFORE INSERT
ON RT_documents
FOR EACH ROW
BEGIN
SELECT RT_documents_seq.NEXTVAL INTO :new.documentID FROM DUAL;
END;
Update
SELECT * FROM v$version;
Oracle Database 10g Enterprise Edition
CREATE TABLE RT_documents
(
documentID INT NOT NULL,
reviewID VARCHAR2 (20) NOT NULL,
file_location CLOB NOT NULL,
version NUMBER (*, 3) NOT NULL,
CONSTRAINT RT_documents_pk PRIMARY KEY (documentID)
);
Table created.
CREATE SEQUENCE rt_documents_seq;
Sequence created.
CREATE OR REPLACE TRIGGER rt_documents_bir
BEFORE INSERT
ON RT_documents
FOR EACH ROW
BEGIN
SELECT RT_documents_seq.NEXTVAL INTO :new.documentID FROM DUAL;
END;
/
Trigger created.
INSERT INTO RT_documents (reviewID, file_location, version)
VALUES ('test', 'test', 1);
1 row created.
SELECT * FROM RT_documents;
DOCUMENTID REVIEWID FILE_LOCATION
VERSION
---------- -------------------- -------------------------------------------
-------------------------------- ----------
1 test test
1
Thanks to Polppan.
The solution was removing the EOL characters. (I did try this but had, without realising, removed the semi-colons, which caused the same error code)
This was a PHP error after all. Using oci_execute, you must remove EOL characters in triggers:
$sql = "CREATE OR REPLACE TRIGGER ......."; //shortened for easy reading
$sql = str_replace(chr(13),'',$sql);
$sql = str_replace(chr(10),'',$sql);
oci_execute($sql);

creating DB table by giving input from php text box

I want to make a table in a database, by giving the name of that table as an input from a text box.
<?php
$tablename = $_POST['tablename'];
// Create a MySQL table in the selected database
mysql_query("CREATE TABLE $tablename(
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
firstpublish VARCHAR(255),
descriptions VARCHAR(255))") or die(mysql_error());
?>
it makes the table and the field, but i can't insert any data in it. When i run the code below
<?php
$firstpublish = $_POST['firstpublish'];
$descriptions = $_POST['descriptions'];
if(isset($_POST['firstpublish']) || ($_POST['descriptions']))
{
$order="INSERT INTO $tablename (id,firstpublish,descriptions) VALUES ('','$firstpublish','$descriptions')";
$result = mysql_query($order) or die (mysql_error());
}
?>
it showing an error message
"You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '( id INT NOT NULL AUTO_INCREMENT, PRIMARY KEY(id), firstpublish VARCHA' at line 1"
how can i fixed this problem.
-thankyou.
My best guess would be that your first query is somehow being rerun with a blank value for $tablename
If this is a publicly accessible page, i'd be very careful about creating tables from user input. You also probably want to (at the very least) run $tablenale through mysql_real_escape_string() and change CREATE TABLE to CREATE TABLE IF NOT EXISTS
The error is here:
mysql_query("CREATE TABLE $tablename(
Since you are mixing a variable in a quoted string, you insert whitespace after its name, because "$tablename(" is illegal name and will most likely be replaced will null, so the SQL-statement will actually be seen for MySQL as
CREATE TABLE id INT NOT NULL AUTO_INCREMENT, PRIMARY KEY(id), firstpublish VARCHAR(255), descriptions VARCHAR (255))
which, in turn, is a syntax error.
Solution: Add a space between $tablename and "(".

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