PHP MySQL insert/update multiple rows at once [duplicate] - php

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This question already has an answer here:
Post form and update multiple rows with mysql
(1 answer)
Closed last year.
I have read this question: https://stackoverflow.com/questions/20255690/php-insert-a-variable-number-of-records-to-mysql-from-a-html-form#=
But I cannot figure out how to apply this to a form with multiple inputs.
I want these inputs to go into the same row (per array id).
My PHP renders the following HTML:
<div class="panel-body">
<div class="row">
<div class="col-xs-12 col-sm-6 col-md-4 col-lg-3 employee-container">
<label for="visible-107">
<img title="Jane Doe" src="/images/prof-pics/default.jpg" class="img-responsive img-circle" alt="Jane Doe">
</label>
<h4><input type="checkbox" name="visible[0]" id="visible-107"> <label for="visible-107">Jane Doe</label></h4>
<div class="input-group">
<span class="input-group-addon">Function</span>
<input type="text" class="form-control" name="function[0]" id="function-107">
</div>
<div class="input-group">
<span class="input-group-addon">Order</span>
<select class="form-control" name="order[0]" id="order-107">
<option value="">-- select one --</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>
</div>
Description<br>
<textarea class="form-control" name="description[0]" id="description-107"></textarea>
</div>
<div class="col-xs-12 col-sm-6 col-md-4 col-lg-3 employee-container">
<label for="visible-2"><img title="John Doe" src="/images/prof-pics/default.jpg" class="img-responsive img-circle" alt="John Doe"></label>
<h4><input type="checkbox" name="visible[1]" id="visible-2"> <label for="visible-2">John Doe</label></h4>
<div class="input-group">
<span class="input-group-addon">Function</span>
<input type="text" class="form-control" name="function[1]" id="function-2">
</div>
<div class="input-group">
<span class="input-group-addon">Order</span>
<select class="form-control" name="order[1]" id="order-2">
<option value="">-- select one --</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>
</div>
Description<br>
<textarea class="form-control" name="description[1]" id="description-2"></textarea>
</div>
</div>
</div>
How would I iterate these arrays so that I can insert/update them as a row per array ID?
After implementing Nana Partykar's answer
function set_team($web_mysqli, $mysqli, $uid, $visible, $function, $order, $description, $action, $update_id = null ) {
$number_empl = sizeof($function);
for($i=0; $i<$number_empl; $i++) {
$uid = $uid[$i];
$visible = $visible[$i];
$function = $function[$i];
$order = $order[$i];
$description = $description[$i];
$name = get_full_name($mysqli, $uid, false);
$sql = "INSERT INTO team (name, function, description, displayorder, visible) VALUES ('$name', '$function', '$description', '$order', '$visible')";
$web_mysqli->query($sql) or die(mysqli_error($web_mysqli));
}
$_SESSION['success'] = "Employee list website updated";
header("Location: ".BASE_PATH."/includes/views/list-employees.php");
exit();
if(isset($_POST['submit-btn'])) {
set_team($web_mysqli, $mysqli, $_POST['uid'], $_POST['visible'], $_POST['function'], $_POST['order'], $_POST['description'], 'insert');
}
When I save only the first name is inserted into the table followed by 3 blank rows.

Answer 1

No Need for name[0],
<input type="checkbox" name="visible[0]" id="visible-107">
<input type="text" class="form-control" name="function[0]" id="function-107">
<select class="form-control" name="order[0]" id="order-107">
<textarea class="form-control" name="description[0]" id="description-107"></textarea>
Make
<input type="checkbox" name="visible[]" id="visible-107">
<input type="text" class="form-control" name="function[]" id="function-107">
<select class="form-control" name="order[]" id="order-107">
<textarea class="form-control" name="description[]" id="description-107"></textarea>
SomePage.php (Submit Page)
<?
extract($_POST);
$sizeOfFunc=sizeof($function);
for($i=0;$i<$sizeOfFunc;$i++)
{
$Visible=$visible[$i];
$Function=$function[$i];
$Order=$order[$i];
$Description=$description[$i];
echo $Visible." ".$Function." ".$Order." ".$Description;
//Use $Visible, $Function, $Order, $Description in your query
}
?>
Updated Code
Don't use same variable name. Atleast change variable name.
This is wrong.
$uid = $uid[$i];
$visible = $visible[$i];
$function = $function[$i];
$order = $order[$i];
$description = $description[$i];
This is correct
$Uid = $uid[$i];
$Visible = $visible[$i];
$Function = $function[$i];
$Order = $order[$i];
$Description = $description[$i];
I've changed your code. Use the below code. It will work.
<?
function set_team($web_mysqli, $mysqli, $uid, $visible, $function, $order, $description, $action, $update_id = null ) {
$number_empl = sizeof($function);
for($i=0; $i<$number_empl; $i++) {
$Uid = $uid[$i];
$Visible = $visible[$i];
$Function = $function[$i];
$Order = $order[$i];
$Description = $description[$i];
$name = get_full_name($mysqli, $Uid, false);
$sql = "INSERT INTO team (name, function, description, displayorder, visible) VALUES ('$name', '$Function', '$Description', '$Order', '$Visible')";
$web_mysqli->query($sql) or die(mysqli_error($web_mysqli));
}
$_SESSION['success'] = "Employee list website updated";
header("Location: ".BASE_PATH."/includes/views/list-employees.php");
exit();
if(isset($_POST['submit-btn'])) {
set_team($web_mysqli, $mysqli, $_POST['uid'], $_POST['visible'], $_POST['function'], $_POST['order'], $_POST['description'], 'insert');
}
?>
I checked your code in my system after editing. It working fine.
<?
error_reporting(0);
extract($_POST);
echo $number_empl = sizeof($function);
for($i=0; $i<$number_empl; $i++)
{
$Visible = $visible[$i];
$Function = $function[$i];
$Order = $order[$i];
$Description = $description[$i];
$name="Just";
echo $sql = "INSERT INTO team (name, function, description, displayorder, visible) VALUES ('$name', '$Function', '$Description', '$Order', '$Visible')"."<br>";
}
?>